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How can I set the origin of a polar graph?

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  • B Offline
    B Offline
    Bert59
    wrote on last edited by
    #1

    Hi,
    I have the following polar graph.
    a1d24690-765a-4705-a6e9-e96d92ccab45-image.png

    I would like to change the orientation so that the 0 is to the right as shown below.
    efdce68c-98b1-45b0-b5de-68caee6653dc-image.png

    Is there a way to achieve that?

    kshegunovK 1 Reply Last reply
    0
    • B Bert59

      Hi,
      I have the following polar graph.
      a1d24690-765a-4705-a6e9-e96d92ccab45-image.png

      I would like to change the orientation so that the 0 is to the right as shown below.
      efdce68c-98b1-45b0-b5de-68caee6653dc-image.png

      Is there a way to achieve that?

      kshegunovK Offline
      kshegunovK Offline
      kshegunov
      Moderators
      wrote on last edited by
      #2

      What component is used to draw this? Is this QtCharts?

      Read and abide by the Qt Code of Conduct

      1 Reply Last reply
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      • B Offline
        B Offline
        Bert59
        wrote on last edited by
        #3

        I'm using QPolarChart from QtCharts

        kshegunovK JonBJ 2 Replies Last reply
        0
        • B Bert59

          I'm using QPolarChart from QtCharts

          kshegunovK Offline
          kshegunovK Offline
          kshegunov
          Moderators
          wrote on last edited by
          #4

          Right, well I'm sorry to say I don't know anything about that, so I can't really help. I hope someone else can give you advice.

          Read and abide by the Qt Code of Conduct

          1 Reply Last reply
          0
          • B Bert59

            I'm using QPolarChart from QtCharts

            JonBJ Offline
            JonBJ Offline
            JonB
            wrote on last edited by
            #5

            @Bert59
            I don't know, but I think https://stackoverflow.com/questions/62734807/qpolarchart-change-axis-orientation is asking for the same as you, but never got an answer...?

            1 Reply Last reply
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