Call to qRound()/qRound64 is ambiguous.

artwaw

Good evening,
I hope someone will help me understand. Seems like something obvious that I miss here. (Qt 5.15.2, multios)

The case is really simple, I want to display the file size in kB. QFileInfo::size() returns bytes.
So, I built my QString:

QFileInfo info;
// fill the data, load the file, etc. rubbish
QString fsize = QString("%1 kB").arg(qRound64(info.size()/1024));

And I get this error. Of course, same for usual qRound. I don't use math methods very often...
What is ambiguous here?

Many thanks in advance.

SGaist

Hi,

You are dividing two integers. You can use 1024.0 or explicitly cast it in order to get either a double or a float which is what qRound and qRound64 are expecting.
But first why trying to round an integer value ?

artwaw

@SGaist imagine me doing glorious facepalm...
I jump between three languages recently and somehow I was deeply convinced that result will be a floating point value...

Shame on me.
Thank you for clarifying!