Solved Call to qRound()/qRound64 is ambiguous.
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Good evening,
I hope someone will help me understand. Seems like something obvious that I miss here. (Qt 5.15.2, multios)The case is really simple, I want to display the file size in kB. QFileInfo::size() returns bytes.
So, I built my QString:QFileInfo info; // fill the data, load the file, etc. rubbish QString fsize = QString("%1 kB").arg(qRound64(info.size()/1024));
And I get this error. Of course, same for usual qRound. I don't use math methods very often...
What is ambiguous here?Many thanks in advance.
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Hi,
You are dividing two integers. You can use 1024.0 or explicitly cast it in order to get either a double or a float which is what qRound and qRound64 are expecting.
But first why trying to round an integer value ? -
@SGaist imagine me doing glorious facepalm...
I jump between three languages recently and somehow I was deeply convinced that result will be a floating point value...Shame on me.
Thank you for clarifying!