Running and showing a certain page on stacked widget as default

georgehanna1993

Hey guys,
I'm trying to run an application with stacked widget.
Is there a way to view a default page in the stacked widget?

JonB

@georgehanna1993
Just use QStackedWidget::setCurrentIndex/Widget() to set whichever page/widget you want before showing. Yes, you have to have the "default page" among its pages.

georgehanna1993

@JonB tried that, didn't work, is there any way to set an index for each page?
How should it look like?

JonB

@georgehanna1993 said in Running and showing a certain page on stacked widget as default:

@JonB tried that, didn't work

In what way "didn't work"? It sets the specified page as the current one displayed.

is there any way to set an index for each page

Pages are indexed (from 0 upward) in the order you add them via QStackedWidget::addWidget(), or you can alter the order via QStackedWidget::insertWidget(). You can pass an index number to setCurrentIndex(), or you can pass the actual desired widget via setCurrentWidget().

How should it look like?

How should what look? The QStackedWidget will display whichever the previously-specified current index/widget is.

QStackedWidget works fine. I do not know what your expectations might be.

georgehanna1993

@JonB The code was created using QT designer, and i'm really new to all of this, that's why I'm asking for help:)

georgehanna1993

Inside the code itself, I found that the QT Designer automatically assigned page number 3 to be the current Index, I changed it and it worked, Thanks!

JonB

@georgehanna1993
It probably just saves with whatever the last page you created, or edited, as the current one.