Get touch device info

rrr_rrr_rrr1

Hello everyone.

I need to get a resolution of plugged touch display.

I know that QtouchEvent contains member 'window()' from which this event was sent. And the pointer to this window contains info about width and height of the window. But I do not see the same (or similar) information in QMouseEvent.

And the question: how can I get a resolution of plugged touch display in scope of mousePressEvent, mouseMoveEvent and mouseReleaseEvent?

Thanks.

SGaist

Hi,

You could get the widget from which the event was generated and then QDesktopWidget to get the info you want.

mrjj

Hi
https://doc.qt.io/qt-5/qscreen.html
can be used to find such information.
You can use the widget as context.
As far as I know you cant get the information via the mouse Events as such.

QScreen* pScreen = QGuiApplication::screenAt(widget->mapToGlobal({widget->width()/2,0}));
QRect availableScreenSize = pScreen->availableGeometry();

rrr_rrr_rrr1

@SGaist, @mrjj I have found out the following info https://doc.qt.io/qt-5/qmouseevent-members.html

@SGaist I cannot see how can I get the widget from which the event was generated. Could you please explain how exactly to do the action from your post?

@mrjj I cannot see how can I link your example

QScreen* pScreen = QGuiApplication::screenAt(widget->mapToGlobal({widget->width()/2,0}));
QRect availableScreenSize = pScreen->availableGeometry();

and QMouseEvent data. Could you please explain how exactly I can get QScreen info using QMouseEvent?

mrjj

@rrr_rrr_rrr1

Well, dont you get the mouse event in a class?
So the "widget" in the code can be replaced with "this" and it should work.