Refresh entire form upon pressing a button
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Hi all,
I have two forms -
form1,form2.
form1has aQTableWidgetwhich reads and showsxmlentries in folder.form2is a dialogue form, collect user data and save asxml.I need to implement the following:
Pressingbutton1inform2save and close the window and immediately updateQtabletwidgetinform1with new values.I did the following in
form2:void FormTwo::on_pushButton_clicked() { . . here read user data and save as xml file . . hide(); FormOne *updatewindow = new FormOne(this); updatewindow->show(); }So everytime a "new" FormOne will be created with updated contents. But I think this is a wrong way to proceed this
Is there a way to implement this with
signals and slots?Thanks in advance
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Hi all,
I have two forms -
form1,form2.
form1has aQTableWidgetwhich reads and showsxmlentries in folder.form2is a dialogue form, collect user data and save asxml.I need to implement the following:
Pressingbutton1inform2save and close the window and immediately updateQtabletwidgetinform1with new values.I did the following in
form2:void FormTwo::on_pushButton_clicked() { . . here read user data and save as xml file . . hide(); FormOne *updatewindow = new FormOne(this); updatewindow->show(); }So everytime a "new" FormOne will be created with updated contents. But I think this is a wrong way to proceed this
Is there a way to implement this with
signals and slots?Thanks in advance
@russjohn834 What is not clear from your description: should form1 always be there or only after closing form2?
Who creates form2? If you say "form" do you mean a window or a widget in a window?
If it is like this: form1 is always there and it creates form2 ,then you can use signals/slots. In form1 when you create form2 instance connect the "update" signal from form2 to a slot in form1. In that slot you then do what needs to be done in form1. -
@russjohn834 What is not clear from your description: should form1 always be there or only after closing form2?
Who creates form2? If you say "form" do you mean a window or a widget in a window?
If it is like this: form1 is always there and it creates form2 ,then you can use signals/slots. In form1 when you create form2 instance connect the "update" signal from form2 to a slot in form1. In that slot you then do what needs to be done in form1.@jsulm Thank you.
I just figured out a way do this withoutsignal & slot.I close form 1(btw , it is QMainwindow) when form 2 is created. Then when I press button form 2 will be closed and a new form 1 will be created. Like this:
this->close(); ---->form 2 MainWindow *back = new MainWindow(this); back->show();I hope this is fine.
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@jsulm Thank you.
I just figured out a way do this withoutsignal & slot.I close form 1(btw , it is QMainwindow) when form 2 is created. Then when I press button form 2 will be closed and a new form 1 will be created. Like this:
this->close(); ---->form 2 MainWindow *back = new MainWindow(this); back->show();I hope this is fine.
MainWindow *back = new MainWindow(this);Although permissible, this creates a brand new main window instance, which is "unusual". It will also lose any state you had previously. You're also parenting the new main window off a "form" you have already
close()d.If you really want to swap windows this way (
QStackedWidgetmay be preferable), consider usingshow()&hide()instead, rather than total destruction & re-creation. If all you really want is to have one window/form/whatever at a time visible and user clicks to go between them, I think thatQStackedWidgetis going to be simpler & better for you. And you don't have to have your multiple main windows as the stack: you could have one main window, with its furniture, and have a stacked widget area on it, which is what gets switched. -
Thank you @JonB for your feedback