@sayan275 It's also always better to post the relevant code as text and not as image, so others can reproduce it easier.

@Saviz I think is not possible to expose a QMap directly to QML, https://doc.qt.io/qt-6/qtqml-cppintegration-data.html#sequence-type-to-javascript-array Maybe one should use a QVariantMap https://doc.qt.io/qt-6/qtqml-cppintegration-data.html#qvariantlist-and-qvariantmap-to-javascript-array-and-object

Thank You so much Bro You Are Life Save I wish All the best happy life for you <3 note : it works better than i ever imagine <3

@jsulm said in Cout in a loop for QLabel Widgets: @Swati777999 Names[ii] = new QLabel(QString("Name %1").arg(ii)); Works perfectly! Thanks.

Hi, You can use QMap:: keyValueBegin and QMap::keyValueEnd for your use case.

@SGaist Thank oyu, that worked!

@QTNewbie2020 QMap isn't, by itself, a complete type. A function can't return a QMap in-general. QMap<QString, int> is what you declare inside the function, so you have to declare the function as return that specific type of QMap to have a complete type. A QMap<float, int> for example would be a completely different type as far a sthe compiler is concerned. They just look like similar names to a human.

@SGaist Thank you.

@Dariusz your signature of the overload isn't correct: see this also make sure those implementations are in the corresponding header file

@mpergand Thank you for help.

@Taz742 Thank you for the tip!

form http://doc.qt.io/qt-5/qmapiterator.html The first call to next() advances the iterator to the position between the first and second item, and returns the first item; so first call to next returns the first item (0), the second call returns the second item (1) the first call to previous returns the first item again (1) using this image: [image: javaiterators1.png] next and previous return the item they jumped over so if you call next 1 time it returns A as it jumps over A, the second time it jumps over B, if you then call previous it jumps over B again so it returns b again

@tmladek You are comparing QVariants that contain QList<Cat>, so you need to provide registered comparison operator for QList<Cat> (or conversions might take place), which you don't do. PS. Also, this: qRegisterMetaType<Cat>("Cat"); should be: qRegisterMetaType<Cat>(); as specifically mentioned in the documentation.

Hi, To add to @micland, what's the base class of my_Struct ?

I'm such a newbie programmer :( I study electronics engineer and I like programming but I don't receive a good foundation in my university and I had to learn a lots of things by myself. Also, I haven't done any OOP for years and I'm new in Qt. Many many thanks!! I will pay more attention to my coding :)

@mrjj said: used as key did funky stuff? The only funky stuff with that macro is that char * doesn't have a meaningful operator <, which is required for it to be a key in the map. The comparison is done as you'd compare integers.

Thank you all, I am going to mark this discussion as solved; However, Any more comments would be much appreciated;