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  • 0 Votes
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    SGaistS

    Hi,

    You should contact the folks from LastPass to check how applications can integrate/communicate with their application.

  • 0 Votes
    3 Posts
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    K

    @SGaist Thanks for your quick answer. And sorry for the delayed reply.

    Overriding QLineEdit was in my mind. Wanted to know if there are any straight forward way to get it done.

    But now am sure about that!

    Thank you!

  • 0 Votes
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    P

    @Leonardo Yeah, that works. Thank you.

  • 0 Votes
    7 Posts
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    R

    Mmmm... that was what I was afraid of... thas maybe it could be a bug... In which version was this bug fixed? where do you see this?

    What u say about catch the input.. I already tried too with that:

    in .h: class MyValidator2: public QValidator { public: MyValidator2(QObject* parent=nullptr): QValidator(parent) {} State validate(QString& input, int&) const override { if (input=="0" or input=="1" or input=="2" or input=="3" or input=="4" or input=="5" or input=="6" or input=="7" or input=="8" or input=="9") return QValidator::Acceptable; } }; in constructor .cpp: auto validator12 = new MyValidator2(parent); le_Pwd->setValidator(validator12); le_Pwd->setMaxLength(8); le_Pwd->setEchoMode(QLineEdit::Password);

    But if i write 1 and then 2, the first one is erased and it only allows me to write one number.... and I don't know if its the bug or if I did wrong the validator ...

    EDIT: I tried also with:

    class MyValidator2: public QValidator { public: MyValidator2(QObject* parent=nullptr): QValidator(parent) {} State validate(QString& input, int&) const override { static const char alphanum[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" "abcdefghijklmnopqrstuvwxyz"; for (int i = 0; i < sizeof(alphanum) - 1; ++i) { if (input == &alphanum[i]) return QValidator::Invalid; else return QValidator::Acceptable; } return QValidator::Acceptable; } };

    But either works...