Yeah but the user also want to be able to reorder things as he wants, not just sort (ie, put this row here, drag all my selection at this position, invert these two rows, ...)

Ok. Thank you for your answer.
I never use QAbstractListModel. Do you have some keys to start ?

What is difference between using QAbstractListModel and QQmlListProperty ?
In which case is it better to use them ?

That's a brilliant and elegant solution!
Thank you bro for spending your precious time with a newbie like me!

@p3c0 said:

@Kofr So is it that you want to access the roles (namely hue, saturation, brightness) values from outside of this ListView delegate ? If so then did you accessing ListVIew model from outside ? Once you get hold of it the data can be accessed too.

code above is just example, not my case. what I need is to get model.roleName of delegate j when I work in delegate i

@Mark81 Even in JavaScript you have two models, you just don't typically think of it that way: model 1: the database, model 2: the results on the client side.

Here, you have two models: 1 - the database, 2 - the QML side.

So what you need to do is create a paginated model using LIMIT/OFFSET queries.

@Mark81 If index is 0 then don't start the animation. Well something like:

property int myIndex : 0 function animate(idx) { listAnimation.running = false var pos = list.contentY; var destPos; list.positionViewAtIndex(idx, ListView.Beginning); destPos = list.contentY; listAnimation.from = pos; listAnimation.to = destPos; listAnimation.running = true; } Timer { ... onTriggered: { if(myIndex==0) list.positionViewAtIndex(myIndex,ListView.Beginning); else animate(myIndex) myIndex++ if(myIndex==list.count-1) myIndex = 0 } }

@Qmyo You can create a 2 Q_INVOKABLE functions. One will return the Repeater's model number and other will return ListView's models. You can make use of index attached property which can be passed to the Q_INVOKABLE functions to return particular model.

In dropEvent called a new function from model which stores all the parameter of item when droped and emitted layoutAboutToBeChanged() before appending to my TableList and then emitted layoutChanged() which worked for me.

Thanks to @kshegunov , @SGaist , @mrjj for the help.

Sneaky one !

Glad you found out :)

@SGaist I don't mind refactoring it, it's not very long. I will definitely look into this. Thanks!

Thanks for your efforts.
As you said it works in a project I have a second look at my code.
I'm not writing a Quick-App but a QWidget-App and use the map inside a QQuickWidget. I have read about another approach to embed qml content in a QWidget-App using QQuickView inside a QObject-Container.
This approach works as expected. I don't know why it doesn't work with a QQuickWidget but my problem is solved.

Best Regards

Code would help.
And do you see any error messages when your app crashes? Did you try to debug?

@Alexander_Lanin didn't see you already found it before I submit my reply...

Thanks for reply. I already solved it too.

It's necessary to return pointer to AnimalModel and not reference. Also there is no necessity for NOTIFY.

So this is the correct way:

Q_PROPERTY(AnimalModel * modelAnimals READ modelAnimals CONSTANT) AnimalModel* modelAnimals() { return &m_model;}

Hi and welcome to devnet,

To make models accessible to QML you have to do sum customization like described in the QtQuick Model Views Data documentation.

QSqlTableModel example here

Good !

Since you have it working now, please mark the thread as solved using the "Topic Tool" button so that other forum users may know a solution has been found :)

You're setting the wrong role. See my answer here.