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how to cause view to update based on model change?

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  • M Offline
    M Offline
    mzimmers
    wrote on 28 Sept 2024, 18:01 last edited by
    #1

    Hi all -

    In this code:

    ListView {
        model: spaceProxyModel
        delegate: GridView {
            required property Space space
            property var spaceFeatureList: 
                sceneModel.featureUuidList(false, space.uuid) // from a C++ function
            model: spaceFeatureList
            delegate: Item {
                ...
    

    The property spaceFeatureList gets updated from another screen, but my view doesn't reflect the change to the model (I've confirmed that spaceFeatureList is indeed being changed). What do I need to do to force the view update?

    Thanks...

    G 1 Reply Last reply 29 Sept 2024, 23:00
    0
    • A ankou29666
      3 Oct 2024, 21:14

      @jeremy_k said in how to cause view to update based on model change?:

      Doing this will cause the view to reset and create new delegates for all items visible. The documentation apparently isn't sufficiently explicit. Assigning a JS object to a view's model property does not create a QAIM that tracks the object's content.

      from my own experience, QAbstractItemModel doesn't magically track the object content. If you modify the underlying data out of the QAIM or any connected view, the QAIM is unaware of these changes. I mean that if a QAIM encapsulates a QList<WhatSoEver> list, and you modify that list directly, the QAIM won't see the change.

      I'm getting a little bit confused now, but as OP has two views and the problem is, if I understand it right, when one view is modified, the other is not updated.

      What I would make is an underlying ListModel that would encapsulate the JSArray. And bind those two view to that ListModel rather than to the JSArray. Perhaps wouldn't solve everything, a good beginning I think.

      @GrecKo said in how to cause view to update based on model change?:

      Forget the dataChanged() discussion, it is not relevant here as you realized since no QAIM is involved.

      Yep my bad, I really don't understand where I got a dataChanged signal to ListModel, it doesn't have any.

      J Offline
      J Offline
      jeremy_k
      wrote on 3 Oct 2024, 21:54 last edited by jeremy_k 10 Mar 2024, 21:56
      #25

      @ankou29666 said in how to cause view to update based on model change?:

      @jeremy_k said in how to cause view to update based on model change?:

      Doing this will cause the view to reset and create new delegates for all items visible. The documentation apparently isn't sufficiently explicit. Assigning a JS object to a view's model property does not create a QAIM that tracks the object's content.

      from my own experience, QAbstractItemModel doesn't magically track the object content. If you modify the underlying data out of the QAIM or any connected view, the QAIM is unaware of these changes. I mean that if a QAIM encapsulates a QList<WhatSoEver> list, and you modify that list directly, the QAIM won't see the change.

      Put more abstractly, if code avoids the interface of a class, it won't function as an instance of that class. Hopefully that's not a surprise.

      I'm getting a little bit confused now, but as OP has two views and the problem is, if I understand it right, when one view is modified, the other is not updated.

      What I would make is an underlying ListModel that would encapsulate the JSArray. And bind those two view to that ListModel rather than to the JSArray. Perhaps wouldn't solve everything, a good beginning I think.

      At the risk of repeating, a JS Array (or any javascript object) does not have a change notification signal. This means that nothing else is aware that an update is required. Detecting changes must therefore depend on another mechanism. For example:

      • Assign a new object to a QtObject's property when the change is made.
      • Run a Timer and go looking for changes in data, refreshing display Items as appropriate.
      • Limit changes to a dedicated editor "page" that doesn't rely on change signals, and reload all other "pages" when the editor page is destroyed.

      There are probably other options that I haven't considered.

      The TL;DR; version is: Why not use ListModel? It has member functions for inserting, removing, and modifying items in the list that can be called from javascript.

      Asking a question about code? http://eel.is/iso-c++/testcase/

      A 1 Reply Last reply 3 Oct 2024, 22:17
      1
      • S Offline
        S Offline
        SGaist
        Lifetime Qt Champion
        wrote on 28 Sept 2024, 18:21 last edited by
        #2

        Hi,

        Might be a silly question but are you emitting the dataChanged signal from your model with the roles used in QML ?

        Interested in AI ? www.idiap.ch
        Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

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        • M Offline
          M Offline
          mzimmers
          wrote on 28 Sept 2024, 18:30 last edited by
          #3

          @SGaist that's actually a very good question, and the answer is "no." I thought dataChanged() was only a method of a proper QAbstractItemModel object - my model is just a JS array that is initialized by a call to an invokable function. Do I need to implement my own signal (and handler) for when the list changes?

          1 Reply Last reply
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          • A Offline
            A Offline
            ankou29666
            wrote on 28 Sept 2024, 19:37 last edited by
            #4

            if your data structure changes outside of the model, then your data has to emit a signal to the model, that the model itself will have to relay to the view. Assuming that the datastructure is a QObject derivative that can emit signals, which is probably not your case.

            With data not being a QObject, I would add a method to the model that would emit the signal. This method would have to be called upon any single data update

            If your data changes outside of the model, the model has to be notified of that change so that it can transmit to (the cascade of proxies if ever relevant and to) the view.

            M 1 Reply Last reply 28 Sept 2024, 21:15
            0
            • A ankou29666
              28 Sept 2024, 19:37

              if your data structure changes outside of the model, then your data has to emit a signal to the model, that the model itself will have to relay to the view. Assuming that the datastructure is a QObject derivative that can emit signals, which is probably not your case.

              With data not being a QObject, I would add a method to the model that would emit the signal. This method would have to be called upon any single data update

              If your data changes outside of the model, the model has to be notified of that change so that it can transmit to (the cascade of proxies if ever relevant and to) the view.

              M Offline
              M Offline
              mzimmers
              wrote on 28 Sept 2024, 21:15 last edited by
              #5

              @ankou29666 said in how to cause view to update based on model change?:

              With data not being a QObject, I would add a method to the model that would emit the signal.

              My model is a simple JS array. How does an array emit a signal?

              J A 2 Replies Last reply 28 Sept 2024, 21:39
              0
              • M mzimmers
                28 Sept 2024, 21:15

                @ankou29666 said in how to cause view to update based on model change?:

                With data not being a QObject, I would add a method to the model that would emit the signal.

                My model is a simple JS array. How does an array emit a signal?

                J Offline
                J Offline
                JoeCFD
                wrote on 28 Sept 2024, 21:39 last edited by JoeCFD
                #6
                This post is deleted!
                M 1 Reply Last reply 28 Sept 2024, 21:52
                0
                • J JoeCFD
                  28 Sept 2024, 21:39

                  This post is deleted!

                  M Offline
                  M Offline
                  mzimmers
                  wrote on 28 Sept 2024, 21:52 last edited by
                  #7

                  @JoeCFD that works for a C++ model, but in this instance, my model is just a JS array of strings. I don't have the context from which to make any of those calls.

                  J 1 Reply Last reply 28 Sept 2024, 22:09
                  0
                  • M mzimmers
                    28 Sept 2024, 21:52

                    @JoeCFD that works for a C++ model, but in this instance, my model is just a JS array of strings. I don't have the context from which to make any of those calls.

                    J Offline
                    J Offline
                    JoeCFD
                    wrote on 28 Sept 2024, 22:09 last edited by
                    #8

                    @mzimmers Sorry my bad.

                    1 Reply Last reply
                    1
                    • M mzimmers
                      28 Sept 2024, 21:15

                      @ankou29666 said in how to cause view to update based on model change?:

                      With data not being a QObject, I would add a method to the model that would emit the signal.

                      My model is a simple JS array. How does an array emit a signal?

                      A Offline
                      A Offline
                      ankou29666
                      wrote on 29 Sept 2024, 07:48 last edited by ankou29666
                      #9

                      @mzimmers said in how to cause view to update based on model change?:

                      @ankou29666 said in how to cause view to update based on model change?:

                      With data not being a QObject, I would add a method to the model that would emit the signal.

                      My model is a simple JS array. How does an array emit a signal?

                      As I said, you create a method in your model

                      Item
                      {
                          ListModel
                          {
                              id: yourListModel
                      
                              function emitSignal ()
                              {
                                   emit dataChanged ;
                              }
                          }
                      }
                      

                      and you ensure that any modification to the data is followed by a call to this method.

                      This is basically what I did by the past (but in C++ not in QML).
                      but in the future, in order to make it fool proof, I would rather put the data structure as protected or private member of the model, such that any change that has been made outside of the views has to be done through public accessors of the model, that automatically trigger the appropriate signals.

                      J 1 Reply Last reply 29 Sept 2024, 08:50
                      0
                      • A ankou29666
                        29 Sept 2024, 07:48

                        @mzimmers said in how to cause view to update based on model change?:

                        @ankou29666 said in how to cause view to update based on model change?:

                        With data not being a QObject, I would add a method to the model that would emit the signal.

                        My model is a simple JS array. How does an array emit a signal?

                        As I said, you create a method in your model

                        Item
                        {
                            ListModel
                            {
                                id: yourListModel
                        
                                function emitSignal ()
                                {
                                     emit dataChanged ;
                                }
                            }
                        }
                        

                        and you ensure that any modification to the data is followed by a call to this method.

                        This is basically what I did by the past (but in C++ not in QML).
                        but in the future, in order to make it fool proof, I would rather put the data structure as protected or private member of the model, such that any change that has been made outside of the views has to be done through public accessors of the model, that automatically trigger the appropriate signals.

                        J Offline
                        J Offline
                        JonB
                        wrote on 29 Sept 2024, 08:50 last edited by JonB
                        #10

                        @ankou29666 , @mzimmers
                        I know nothing about QML! But I don't think emit will work from JavaScript, it's #defined to empty in C++? My guess would be you need to write just dataChanged(...) or maybe yourListModel.dataChanged(...)?

                        1 Reply Last reply
                        0
                        • A Offline
                          A Offline
                          ankou29666
                          wrote on 29 Sept 2024, 09:26 last edited by
                          #11

                          not impossible, I had made a little pause with Qt and currently rather working on the UI than the code, so it's far from impossible that I make a few bullshits in my code snippets.

                          1 Reply Last reply
                          0
                          • M Offline
                            M Offline
                            mzimmers
                            wrote on 29 Sept 2024, 14:25 last edited by
                            #12

                            There's still something missing here -- again, my model isn't a QML list model; it's a simple JS array. According to the docs, this is a valid model. What the docs don't say, though (at least nowhere that I can find), is how such a model can generate a signal to update the view. Maybe this can't be done from an array model, but I imagine that somehow, I can effect the same thing.

                            J 1 Reply Last reply 29 Sept 2024, 16:26
                            0
                            • A Offline
                              A Offline
                              ankou29666
                              wrote on 29 Sept 2024, 14:35 last edited by
                              #13

                              I would rather formulate it this way : the doc doesn't say that such JS array data doesn't update the underlying Qt model, if any, and thus, the Qt views.

                              1 Reply Last reply
                              0
                              • M mzimmers
                                29 Sept 2024, 14:25

                                There's still something missing here -- again, my model isn't a QML list model; it's a simple JS array. According to the docs, this is a valid model. What the docs don't say, though (at least nowhere that I can find), is how such a model can generate a signal to update the view. Maybe this can't be done from an array model, but I imagine that somehow, I can effect the same thing.

                                J Offline
                                J Offline
                                JonB
                                wrote on 29 Sept 2024, 16:26 last edited by JonB
                                #14

                                @mzimmers
                                Yes, a JSON array is not going to be able to emit a signal. What is the problem with calling dataChanged() per above whenever you change existing data the underlying JS array? I mean even if we were in C++ and I altered an array or vector or QList or whatever was my model's actual data I would still have to emit dataChanged() explicitly correspondingly.

                                1 Reply Last reply
                                0
                                • M mzimmers
                                  28 Sept 2024, 18:01

                                  Hi all -

                                  In this code:

                                  ListView {
                                      model: spaceProxyModel
                                      delegate: GridView {
                                          required property Space space
                                          property var spaceFeatureList: 
                                              sceneModel.featureUuidList(false, space.uuid) // from a C++ function
                                          model: spaceFeatureList
                                          delegate: Item {
                                              ...
                                  

                                  The property spaceFeatureList gets updated from another screen, but my view doesn't reflect the change to the model (I've confirmed that spaceFeatureList is indeed being changed). What do I need to do to force the view update?

                                  Thanks...

                                  G Offline
                                  G Offline
                                  GrecKo
                                  Qt Champions 2018
                                  wrote on 29 Sept 2024, 23:00 last edited by
                                  #15

                                  Forget the dataChanged() discussion, it is not relevant here as you realized since no QAIM is involved.
                                  @mzimmers said in how to cause view to update based on model change?:

                                  The property spaceFeatureList gets updated from another screen, but my view doesn't reflect the change to the model (I've confirmed that spaceFeatureList is indeed being changed). What do I need to do to force the view update?

                                  Nothing, it is handed automatically if the spaceFeatureList actually changes.
                                  Are you sure it does? How did you confirm it?

                                  M 1 Reply Last reply 30 Sept 2024, 02:30
                                  1
                                  • G GrecKo
                                    29 Sept 2024, 23:00

                                    Forget the dataChanged() discussion, it is not relevant here as you realized since no QAIM is involved.
                                    @mzimmers said in how to cause view to update based on model change?:

                                    The property spaceFeatureList gets updated from another screen, but my view doesn't reflect the change to the model (I've confirmed that spaceFeatureList is indeed being changed). What do I need to do to force the view update?

                                    Nothing, it is handed automatically if the spaceFeatureList actually changes.
                                    Are you sure it does? How did you confirm it?

                                    M Offline
                                    M Offline
                                    mzimmers
                                    wrote on 30 Sept 2024, 02:30 last edited by
                                    #16

                                    @GrecKo said in how to cause view to update based on model change?:

                                    How did you confirm it?

                                    I have a telltale printout.

                                    My main QML file is SceneSetup.qml. On a button press, I push another component (SceneFeatureSelect.qml) onto my stack. I pass the model as a required property. When SceneFeatureSelect changes the list (the model) it uses a callback to notify SceneSetup. My printout in SceneSetup confirms the addition to the model, but my GridView doesn't change.

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                                      GrecKo
                                      Qt Champions 2018
                                      wrote on 30 Sept 2024, 07:41 last edited by
                                      #17

                                      @mzimmers said in how to cause view to update based on model change?:

                                      My printout in SceneSetup confirms the addition to the model, but my GridView doesn't change.

                                      To which model?
                                      That's too abstract for me to make the link with your code.
                                      Does or does not the spaceFeatureList get reevaluated with a new value?
                                      You didn't confirm it with onSpaceFeatureListChanged: print("space feature list changed" if I understand correctly.

                                      In the following code:

                                      ListView {
                                          model: spaceProxyModel
                                          delegate: GridView {
                                              required property Space space
                                              property var spaceFeatureList: 
                                                  sceneModel.featureUuidList(false, space.uuid)
                                      

                                      The spaceFeatureList will get reevaluated if you change if sceneModel corresponding NOTIFY signal is emitted or if there's a dataChanged signal for the uuid role of the corresponding row in spaceProxyModel (or for a modelResest or layoutChanged).
                                      It also may work if featureUuidList is a function implemented in JS but I doubt that's the case.

                                      M 2 Replies Last reply 30 Sept 2024, 11:23
                                      0
                                      • G GrecKo
                                        30 Sept 2024, 07:41

                                        @mzimmers said in how to cause view to update based on model change?:

                                        My printout in SceneSetup confirms the addition to the model, but my GridView doesn't change.

                                        To which model?
                                        That's too abstract for me to make the link with your code.
                                        Does or does not the spaceFeatureList get reevaluated with a new value?
                                        You didn't confirm it with onSpaceFeatureListChanged: print("space feature list changed" if I understand correctly.

                                        In the following code:

                                        ListView {
                                            model: spaceProxyModel
                                            delegate: GridView {
                                                required property Space space
                                                property var spaceFeatureList: 
                                                    sceneModel.featureUuidList(false, space.uuid)
                                        

                                        The spaceFeatureList will get reevaluated if you change if sceneModel corresponding NOTIFY signal is emitted or if there's a dataChanged signal for the uuid role of the corresponding row in spaceProxyModel (or for a modelResest or layoutChanged).
                                        It also may work if featureUuidList is a function implemented in JS but I doubt that's the case.

                                        M Offline
                                        M Offline
                                        mzimmers
                                        wrote on 30 Sept 2024, 11:23 last edited by
                                        #18
                                        This post is deleted!
                                        1 Reply Last reply
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                                        • G GrecKo
                                          30 Sept 2024, 07:41

                                          @mzimmers said in how to cause view to update based on model change?:

                                          My printout in SceneSetup confirms the addition to the model, but my GridView doesn't change.

                                          To which model?
                                          That's too abstract for me to make the link with your code.
                                          Does or does not the spaceFeatureList get reevaluated with a new value?
                                          You didn't confirm it with onSpaceFeatureListChanged: print("space feature list changed" if I understand correctly.

                                          In the following code:

                                          ListView {
                                              model: spaceProxyModel
                                              delegate: GridView {
                                                  required property Space space
                                                  property var spaceFeatureList: 
                                                      sceneModel.featureUuidList(false, space.uuid)
                                          

                                          The spaceFeatureList will get reevaluated if you change if sceneModel corresponding NOTIFY signal is emitted or if there's a dataChanged signal for the uuid role of the corresponding row in spaceProxyModel (or for a modelResest or layoutChanged).
                                          It also may work if featureUuidList is a function implemented in JS but I doubt that's the case.

                                          M Offline
                                          M Offline
                                          mzimmers
                                          wrote on 30 Sept 2024, 17:02 last edited by
                                          #19

                                          @GrecKo said in how to cause view to update based on model change?:

                                          To which model?
                                          That's too abstract for me to make the link with your code.

                                          Sorry - this is a fairly complicated bit of stuff. Here's a snippet of the relevant code:

                                          Pane {
                                              id: sceneSetupPane
                                              signal featureListChanged(spaceId: string, activityId: string, status: bool)
                                              function changeCallback(spaceId, activityId, status)
                                              {
                                                  featureListChanged(spaceId, activityId, status)
                                              }
                                              ListView {
                                                  model: spaceProxyModel
                                                  delegate: GridView {
                                                      required property Space space
                                                      property var spaceFeatureList: sceneModel.featureUuidList(false, space.uuid)
                                                      model: spaceFeatureList
                                                      delegate: Text { text: modelData }
                                          
                                                      Connections {
                                                          target: sceneSetupPane
                                                          function onFeatureListChanged(spaceId, activityId, status) {
                                                              if (spaceId.localeCompare(space.uuid) === 0) {
                                                                  if (status) {
                                                                      if (spaceFeatureList.indexOf(activityId) === -1) {
                                                                          var i = spaceFeatureList.push(activityId)
                                                                      }
                                                                  } else {
                                                                      var j = spaceFeatureList.indexOf(activityId)
                                                                      if (j !== -1) {
                                                                          spaceFeatureList.splice(spaceFeatureList.indexOf(activityId), 1)
                                                                      }
                                                                  }
                                                                  console.log("spaceFeatureList is now", spaceFeatureList)
                                                              }
                                                          }
                                                      }
                                          

                                          I've verified that the callback is invoked appropriately, all the arguments are good, and the spaceFeatureList is correct after processing. Yet, my view doesn't change.

                                          J 1 Reply Last reply 3 Oct 2024, 20:56
                                          0
                                          • M Offline
                                            M Offline
                                            mzimmers
                                            wrote on 3 Oct 2024, 04:33 last edited by
                                            #20

                                            BTT: anyone have an idea on this? Thanks...

                                            1 Reply Last reply
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