exposing entire C++ object to QML

sierdzio

@mzimmers one annoying thing about Q_GADGET is that you cannot instantiate it in QML. But you can create it in C++ and pass around you QML - that's why I suggested it. You can keep you Q_GADGET objects in C++ model and then use them to pass the whole entry data in a single property. Like so:

drawerStack.push("SpaceDetail.qml",
                                        {
                                            "mySpace": space // fromModel
                                        }

In SpaceDetail.qml you can have a property but you cannot let it auto-construct because QML can't do it :( So, maybe this will work:

property Space mySpace: null
// or
property Space mySpace: undefined

kshegunov

@mzimmers said in exposing entire C++ object to QML:

struct Space {
    Q_GADGET
    Q_PROPERTY(QUuid uuid READ uuid WRITE setUuid)
    Q_PROPERTY(QString name READ name WRITE setName)
    QML_VALUE_TYPE(space)

    // Method definitions here ...

    QUuid m_uuid;
    QString m_name;
}

(potentially you may want to have Space(const QJSValue&) to be able to construct from QML json.)
this this should work:

ColumnLayout {
    id: spaceDetail
    required property space mySpace
    // ...

More details here

mzimmers

@kshegunov @sierdzio I'm still missing something here -- I have access to the Space object from the model used by the QML code that invokes SpaceDetail.qml. I want to use that object (not create a new one) to pass to SpaceDetail. How do I do this?

I'm also getting a startup error:

qt.qml.typeregistration: Invalid QML element name "Space"; value type names should begin with a lowercase letter

which I assume comes from this line:

    qmlRegisterType<Space>("Space", 1, 0, "Space");

and which I don't understand, because all of my other calls to qmlRegisterType() work without error, eg:

    qmlRegisterType<SpaceModel>("SpaceModel", 1, 0, "SpaceModel");

I suspect this is because SpaceModel is a subclass of QAbstractListModel, where Space is just a struct, but I don't fully understand the implications.

Aliviya

@mzimmers said in exposing entire C++ object to QML:

Hi all -
My app uses a C++ (list) model which is exposed to QML via the means mentioned in the docs. Everything seems to work fine.
I use the model on a summary page to display item information. When the user clicks on a list item, he'll go to a detail page.
A minimal bit of my model:
struct Space {
QUuid m_uuid;
QString m_name;
}
class SpaceModel: public QAbstractListModel
{
Q_OBJECT
QList<Space> *m_list;
...
}

and some of my QML:
// space summary screen
delegate: SpaceCard {
uuid: spaceUuid // from model
drawerEnabled: false
onTileClicked: (uuid) => {
drawer.open()
drawerStack.push("SpaceDetail.qml",
{
"uuid": uuid,
"name": displayName // from model
}

// SpaceDetail.qml
ColumnLayout {
id: spaceDetail
required property string uuid
required property string name
// etc...

My question: what if the struct used in the model list were to contain, say, 100 elements? Obviously I don't want to pass each one individually from the summary to the detail. How best to handle this situation?
Thanks...

Hi there,

If the struct used in the model list contains 100 elements, it would be inefficient to pass each one individually from the summary to the detail. A better way to handle this situation would be to use a data model.

A data model is a way of representing data in a way that is easy to access and manipulate. In QML, data models are implemented using the QtObject class.

To use a data model, you would first need to create a class that inherits from QtObject. This class would then contain the properties that you want to pass to the detail page. For example, you could create a class called SpaceModel that contains the following properties:

uuid: string
name: string
Once you have created the data model, you can then pass it to the detail page using the Object.fromJson() function. For example, you could do the following in the QML:

// space summary screen
delegate: SpaceCard {
    uuid: spaceUuid // from model
    drawerEnabled: false
    onTileClicked: (uuid) => {
                       drawer.open()
                       drawerStack.push("SpaceDetail.qml",
                                        JSON.stringify({
                                            "uuid": uuid,
                                            "name": displayName // from model
                                        })
    }
}

// SpaceDetail.qml
ColumnLayout {
    id: spaceDetail
    required property string uuid
    required property string name
    // etc...
    SpaceModel {
        uuid: uuid
        name: name
    }
}

This would create a data model object in the detail page that contains the uuid and name properties of the selected item from the summary page.

sierdzio

@mzimmers said in exposing entire C++ object to QML:

@kshegunov @sierdzio I'm still missing something here -- I have access to the Space object from the model used by the QML code that invokes SpaceDetail.qml. I want to use that object (not create a new one) to pass to SpaceDetail. How do I do this?

You can return Space object in your data() method of your model. Something like (pseudocode):

class SpaceModel: public QAbstractListModel
{
  // ...
  QVartiant data(const QModelIndex &index, const int role) const
  {
    if (index is valid and role is correct etc.) { 
      m_list.at(index.row());
    }
  }
}

I'm also getting a startup error:

qt.qml.typeregistration: Invalid QML element name "Space"; value type names should begin with a lowercase letter

which I assume comes from this line:

    qmlRegisterType<Space>("Space", 1, 0, "Space");

This is some recent change in Qt 6. Uppercase gadgets work fine with Qt 5 & 6 but Qt 6 warns against them. If you don't need Qt 5 support, just make it lower-case and it will be fine.

Ah, one more thing: since Q_GADGETs cannot be constructed in QML, you should use qmlRegisterUncreatableType instead.

mzimmers

@sierdzio said in exposing entire C++ object to QML:

You can return Space object in your data() method of your model. Something like (pseudocode):

Great idea - I'm going to do this. It never occurred to me to use data() for the entire object as well as the individual roles.

But: again, how do I code the access to the entire object in my QML? What is the construct for accessing a complete object from within a delegate?

Thanks...

GrecKo

@mzimmers is the question about how to access a model role from a delegate or how to access properties of an object?

mzimmers

@GrecKo more the latter. I'm trying to pass an instance from my model list from a delegate to another QML module, all in one line of code (if possible).

Right now, I only know how to access individual properties; I'm sure there's a way to refer to the entire object that the delegate is currently set on, but I don't know what that is.

EDIT: this is what I want to be able to do:
EDIT 2: simplified example (no need for the drawer)

// space summary screen
ListView {
    model: spaceModel
    delegate: SpaceCard {
        // MAGIC to pass the model element
    }
    // ...

// SpaceCard.qml                                          
Item {
    id: spaceCard
    // MAGIC to reference the model element
    
    text: MAGIC.text
    uuid: MAGIC.uuid
    // etc. (imagine that the model element had 100 fields

sierdzio

@mzimmers said in exposing entire C++ object to QML:

@sierdzio said in exposing entire C++ object to QML:

You can return Space object in your data() method of your model. Something like (pseudocode):

Great idea - I'm going to do this. It never occurred to me to use data() for the entire object as well as the individual roles.

But: again, how do I code the access to the entire object in my QML? What is the construct for accessing a complete object from within a delegate?

Thanks...

If you use roleNames() and custom roles then it is entirely up to you.
If you just return a list of objects to act as a model, then you can access current element through modelData, for example modelData.uuid.

mzimmers

@sierdzio OK, I think I now understand what you're saying. I've done the following:

modified my Space struct:

struct Space {
    Q_GADGET
    QML_VALUE_TYPE(space) // so "space" can be used in QML.
public:
    QString m_name;
    Q_INVOKABLE QString name() { return m_name; }

added a CompleteObjectRole to my SpaceModel roles
added to SpaceModel::data() for this role:

QVariant SpaceModel::data(const QModelIndex &index, int role) const
{
    QVariant qv = QVariant();

    do {
        Space item = m_list->at(index.row());
        switch (role) {
        case CompleteObjectRole:
            qv = QVariant::fromValue(item));
            break;

use this in my QML:

// space summary screen
ListView {
    id: spaceCards

    model: spaceProxyModel
    delegate: SpaceCard {
        mySpace: completeObject

// SpaceCard.qml
Item { 
    id: spaceCard

    property space mySpace
    property string titleText: mySpace.name()

It works, and is what I was asking for. Is this what you expected/intended? Thanks...

EDIT:

I discovered a flaw in this approach: the property mySpace in SpaceCard.qml is evidently a static copy, and so its data isn't updated when the model changes. Is there a way to fix this?

Thanks...

sierdzio

@mzimmers yup, that's exactly what I had in mind!

EDIT:

I discovered a flaw in this approach: the property mySpace in SpaceCard.qml is evidently a static copy, and so its data isn't updated when the model changes. Is there a way to fix this?

First, try adding a MEMBER Q_PROPERTY to your gadget, it might work.

struct Space {
    Q_GADGET
    QML_VALUE_TYPE(space) // so "space" can be used in QML.

    Q_PROPERTY(QString name MEMBER m_name)

public:
    QString m_name;
    Q_INVOKABLE QString name() { return m_name; }

// ...

property string titleText: mySpace.name

If not, then you'll have to change Space to Q_OBJECT which does support signals & slots so it will also dynamically update for sure.

mzimmers

@sierdzio I'd already tried using Q_PROPERTY; sadly, no success. I guess I'm going to have to go through the effort of basing Space off of QObject...ugh.

I'll report back when I'm done.

EDIT:

@sierdzio is there really no other way to accomplish this? I ask because

this is going to be a non-trivial effort, and
the example in the docs doesn't do it this way.

Any alternative is welcome.

sierdzio

But have you used the property (name without ()) instead of invokable method?

property string titleText: mySpace.name

Also, do you emit dataChanged() in your model when a change occurs?

mzimmers

@sierdzio said in exposing entire C++ object to QML:

But have you used the property (name without ()) instead of invokable method?

property string titleText: mySpace.name

Yes:

Item { // needed for the DropShadow.
    id: spaceCard
    property space spaceObject
    property string spaceName: spaceObject.name

Also, do you emit dataChanged() in your model when a change occurs?

Yes. When I receive a change, my slot loops through the list of spaces, and updates the appropriate list items:

for (int spaceIndex = 0; spaceIndex < m_list->size(); spaceIndex++) {
    space = m_list->at(spaceIndex);
    if (space.containsEquipment(equipmentUuid)) {

        // update the temperature-related fields.
        QModelIndex qmi = index(spaceIndex, 0, QModelIndex());

        space.m_temperature = temperature;
        space.m_temperatureTimestamp = temperatureTimestamp;
        space.m_temperatureUpdated = true;
        changedRoles << TemperatureRole << TemperatureTimestampRole << TimestampUpdatedRole;
        m_list->replace(spaceIndex, space);
        emit dataChanged(qmi, qmi, changedRoles);
    }
}

I've verified this behavior with telltales.

Rather strange, isn't it...

GrecKo

@mzimmers What role are you using for returning your complete object? What roles do you emit dataChanged on?

mzimmers

@GrecKo I've created a separate role for the complete object:

enum SpaceRoleNames {
    UuidRole = Qt::UserRole,
    ...
    CompleteObjectRole,
    NbrRoles
};

and my data() function does this:

QVariant SpaceModel::data(const QModelIndex &index, int role) const
{
    QVariant qv = QVariant();

    do {
        if (!index.isValid() || m_list == nullptr)
            continue;

        Space item = m_list->at(index.row());
        switch (role) {
        case UuidRole:
            qv = item.m_uuid;
            break;
        ...
        case CompleteObjectRole:
            qv = QVariant::fromValue(item);
            break;

When any of the temperature related stuff changes, I perform the code in my last post.

Marko Stanke

If you want to purely show data inside SpaceCard.qml, you can bind it through QML. All the mentioned things below should work if the data() function has been implemented properly. (Note: sometimes you need to call dataChanged(index,index) inside the setData() function for it to chage it on QML side.

ListView {
    id: spaceCards

    model: spaceProxyModel
    delegate: SpaceCard {
        mySpace: completeObject

// SpaceCard.qml
Item { 
    id: spaceCard

    property space mySpace: spaceCards.currentItem.mySpace
    property string titleText: mySpace.name
}

Also, make sure that inside your list view the currentIndex changes accordingly.

mzimmers

@Marko-Stanke thanks for the suggestion. I still can't get it to work. Here's the QML:

// SpacesScreen.qml
ListView {
    id: spaceCards

    model: spaceProxyModel
    delegate: SpaceCard {
        spaceObject: completeObject

// SpaceCard.qml
Item { // needed for the DropShadow.
    id: spaceCard

    property space thisSpaceObject: spaceCards.currentItem().spaceObject
    property real temperatureReading: thisSpaceObject.temperature()

And the struct:

// space.h
struct Space {
    Q_GADGET
    QML_VALUE_TYPE(space)
    Q_PROPERTY(float temperature MEMBER m_temperature)
public:
    float m_temperature;
    Q_INVOKABLE float temperature () { return m_temperature; }

Why would I need to call dataChanged() inside data()? That's a read-only function, right?

I'm also not sure what you meant about the currentIndex. The ListView should handle that for me, shouldn't it?

Thanks...

GrecKo

@GrecKo said in exposing entire C++ object to QML:

@mzimmers What role are you using for returning your complete object? What roles do you emit dataChanged on?

Sorry if this wasn't clear but that was meant to push you to find the correct solution.

You don't emit dataChanged for the CompleteObjectRole, so if you use this role and change the data, the view and delegates won't be aware of any change.

Don't do what Marko suggested with

    property space mySpace: spaceCards.currentItem().mySpace
    property string titleText: mySpace.name()

or emitting dataChanged in the data function.

You also don't need the Q_INVOKABLE macro on your getters, they are are already exposed with Q_PROPERTY. You don't even need the getters if you are using MEMBER in the Q_PROPERTY (which makes sense for a Q_GADGET).

Marko Stanke

@mzimmers Sorry for the confusion. I edited my response.

The dataChanged signal is needed (sometimes) in the setData() method, not data().
Also, the currentItem,name are properties. No brackets () needed.

ListView has a build in mechanism for handling currentIndex with keyboard navigation, but only if the ListView is in focus,
if you want to change the currentIndex by click, you need to implement a click() signal handler. (By using MouseArea, TapHandler), and changing the currentIndex of your list based on the index of the clicked item.

As for the Q_INVOKABLE goes that @GrecKo mentioned, he's right. No Q_INVOKABLE needed if you're using MEMBER in Q_PROPERTY.

Note: the solution I posted is only viable if you want only to read data.