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InsertRow

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  • JonBJ JonB

    @Duy-Khang
    If that column is in the table but you don't want to show it, use void QTableView::hideColumn(int column) to suppress it in your view.

    Oh, I misunderstood what you were wanting to hide in your picture! I thought you meant the first column!

    In which case it's the horizontal header as @Christian-Ehrlicher has pointed you to.

    D Offline
    D Offline
    Duy Khang
    wrote on last edited by
    #20

    @JonB yes, thank you, it works

    1 Reply Last reply
    0
    • JonBJ JonB

      @Duy-Khang
      If that column is in the table but you don't want to show it, use void QTableView::hideColumn(int column) to suppress it in your view.

      Oh, I misunderstood what you were wanting to hide in your picture! I thought you meant the first column!

      In which case it's the horizontal header as @Christian-Ehrlicher has pointed you to.

      D Offline
      D Offline
      Duy Khang
      wrote on last edited by
      #21

      @JonB hi,
      set.png

      how can i change the name of column in picture ?

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      • SGaistS Offline
        SGaistS Offline
        SGaist
        Lifetime Qt Champion
        wrote on last edited by
        #22

        What names do you want there ?

        Interested in AI ? www.idiap.ch
        Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

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        0
        • D Offline
          D Offline
          Duy Khang
          wrote on last edited by Duy Khang
          #23

          @SGaist hi, how can I insert a row after the current row, assuming we don't have any rows at first, I use QSqlTableModel.

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          • SGaistS Offline
            SGaistS Offline
            SGaist
            Lifetime Qt Champion
            wrote on last edited by
            #24

            The same as usual.

            As for setting the header data, it's shown in the QSqlTableModel documentation.

            Interested in AI ? www.idiap.ch
            Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

            1 Reply Last reply
            1
            • D Offline
              D Offline
              Duy Khang
              wrote on last edited by
              #25

              yes, i have done it and then how can I insert a row after the current row, assuming we don't have any rows at first, I use QSqlTableModel.

              JonBJ 1 Reply Last reply
              0
              • SGaistS Offline
                SGaistS Offline
                SGaist
                Lifetime Qt Champion
                wrote on last edited by
                #26

                What issue do you have with using insertRow ?

                Interested in AI ? www.idiap.ch
                Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

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                • D Duy Khang

                  yes, i have done it and then how can I insert a row after the current row, assuming we don't have any rows at first, I use QSqlTableModel.

                  JonBJ Offline
                  JonBJ Offline
                  JonB
                  wrote on last edited by
                  #27

                  @Duy-Khang said in InsertRow:

                  how can I insert a row after the current row, assuming we don't have any rows at first

                  In addition to what @SGaist has been saying, how do you have a "current" row to insert after if you don't have any rows to start with?

                  1 Reply Last reply
                  1
                  • A Offline
                    A Offline
                    ArthurPYQT
                    wrote on last edited by
                    #28
                    import sys
                    
                    from PyQt5.QtWidgets import QWidget, QApplication,QTableView, QVBoxLayout,QPushButton
                    from PyQt5.QtSql import QSqlDatabase, QSqlQuery, QSqlTableModel,QSqlRecord
                    
                    class demo(QWidget):
                        def __init__(self):
                            super().__init__()
                            lyt = QVBoxLayout()
                            self.setLayout(lyt)
                            tview = QTableView()
                            btn = QPushButton('add')
                            lyt.addWidget(tview)
                            lyt.addWidget(btn)
                            db = QSqlDatabase.addDatabase("QSQLITE")
                            db.setDatabaseName(r"xxx.db")
                            self.model = testModel(db)
                            tview.setModel(self.model)
                            btn.clicked.connect(self.insertNewRecord)
                        
                        def insertNewRecord(self):
                            r = QSqlRecord()
                            r.setValue('name', 'hello')
                            r.setValue('age', 23)
                    
                            if self.model.insertRecord(0, r):
                    
                                print(self.model.submitAll())
                                print(self.model.lastError().text())
                            else:
                                self.model.db.rollback()
                                print(self.model.lastError().text())
                            self.model.select()
                            
                    class testModel(QSqlTableModel):
                        def __init__(self, db):
                            super().__init__()
                            self.db = db
                         
                            print(self.db.open())
                            self.setTable('test')
                            self.setEditStrategy(QSqlTableModel.OnManualSubmit)
                            print(self.select())
                            print(self.lastError().text())
                            print(self.tableName())
                    
                    if __name__ == '__main__':
                        app = QApplication(sys.argv)
                        t = demo()
                        t.show()
                        sys.exit(app.exec())
                    
                    

                    data is displayed properly, but when i try to insertRecord, something wrong "No fields to update ". tableview not updated, let alone the database.

                    how to insert a record into the table?

                    JonBJ 1 Reply Last reply
                    0
                    • A ArthurPYQT
                      import sys
                      
                      from PyQt5.QtWidgets import QWidget, QApplication,QTableView, QVBoxLayout,QPushButton
                      from PyQt5.QtSql import QSqlDatabase, QSqlQuery, QSqlTableModel,QSqlRecord
                      
                      class demo(QWidget):
                          def __init__(self):
                              super().__init__()
                              lyt = QVBoxLayout()
                              self.setLayout(lyt)
                              tview = QTableView()
                              btn = QPushButton('add')
                              lyt.addWidget(tview)
                              lyt.addWidget(btn)
                              db = QSqlDatabase.addDatabase("QSQLITE")
                              db.setDatabaseName(r"xxx.db")
                              self.model = testModel(db)
                              tview.setModel(self.model)
                              btn.clicked.connect(self.insertNewRecord)
                          
                          def insertNewRecord(self):
                              r = QSqlRecord()
                              r.setValue('name', 'hello')
                              r.setValue('age', 23)
                      
                              if self.model.insertRecord(0, r):
                      
                                  print(self.model.submitAll())
                                  print(self.model.lastError().text())
                              else:
                                  self.model.db.rollback()
                                  print(self.model.lastError().text())
                              self.model.select()
                              
                      class testModel(QSqlTableModel):
                          def __init__(self, db):
                              super().__init__()
                              self.db = db
                           
                              print(self.db.open())
                              self.setTable('test')
                              self.setEditStrategy(QSqlTableModel.OnManualSubmit)
                              print(self.select())
                              print(self.lastError().text())
                              print(self.tableName())
                      
                      if __name__ == '__main__':
                          app = QApplication(sys.argv)
                          t = demo()
                          t.show()
                          sys.exit(app.exec())
                      
                      

                      data is displayed properly, but when i try to insertRecord, something wrong "No fields to update ". tableview not updated, let alone the database.

                      how to insert a record into the table?

                      JonBJ Offline
                      JonBJ Offline
                      JonB
                      wrote on last edited by
                      #29

                      @ArthurPYQT
                      Since you call print(self.model.lastError().text()) both when insertRecord(0, r) succeeds and when it fails, do you want to tell us (actually prove) which route your code is following...?

                      A 1 Reply Last reply
                      1
                      • JonBJ JonB

                        @ArthurPYQT
                        Since you call print(self.model.lastError().text()) both when insertRecord(0, r) succeeds and when it fails, do you want to tell us (actually prove) which route your code is following...?

                        A Offline
                        A Offline
                        ArthurPYQT
                        wrote on last edited by
                        #30

                        @JonB self.model.insertRecord(0, r) returns True, self.model.submitAll() returns False, self.model.lastError().text() returns "No fields to update"

                        A 1 Reply Last reply
                        0
                        • A ArthurPYQT

                          @JonB self.model.insertRecord(0, r) returns True, self.model.submitAll() returns False, self.model.lastError().text() returns "No fields to update"

                          A Offline
                          A Offline
                          ArthurPYQT
                          wrote on last edited by ArthurPYQT
                          #31

                          @ArthurPYQT I finally found the solution. it should be r=self.model.record() rather than r=QSqlRecord(). And I 'vd come up with a new question, is QSqlRelationalTableModel a must if I want to display data from two tables and write data back?

                          JonBJ 1 Reply Last reply
                          0
                          • A ArthurPYQT

                            @ArthurPYQT I finally found the solution. it should be r=self.model.record() rather than r=QSqlRecord(). And I 'vd come up with a new question, is QSqlRelationalTableModel a must if I want to display data from two tables and write data back?

                            JonBJ Offline
                            JonBJ Offline
                            JonB
                            wrote on last edited by JonB
                            #32

                            @ArthurPYQT
                            QSqlRelationalTableModel is only for: if you have a foreign key relationship in your database between the two tables, it allows you to display to the user the "mapped" values for viewing/editing. Typical example:

                            • Table A has its own PK plus other columns. One column is a country_id number.
                            • That number is from Table B, which has country_id as its PK plus a country_name column.

                            If you do this via QSqlRelationalTableModel and use a QSqlRelationalDelegate, it will show the "mapped" country name from Table B for the column in Table A which is the country id. And if you allow editing it will present the user with a combobox of all the country names in Table B to pick from when editing the column in Table A.

                            However, it is not mandatory to use QSRTM. You can do viewing/updating with or without. Note that what I have described is all it does: people sometimes expect more of it. In particular, it does not have any support for editing the foreign key table (Table B).

                            1 Reply Last reply
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