Add to Qt GUI logger functionality

[Gaetano03]

@JonB said in Add to Qt GUI logger functionality:

Not sure where to declare the log function though

At this point what I did is

I created a QApplication subclass in a .h file (integer_interface.h) which looks like this

class integer_interface : public QApplication
{
    Q_OBJECT
public:
    integer_interface(int &argc, char *argv[]) {}; // empty constructor

signals:
    void libraryLogged(std::string message);

};

then in my logger_widget class, logger_widget.h (the one that contains the QPlainTextWidget) I have the following class definition:

namespace Ui {
class logger_widget; 
}

class logger_widget : public QWidget
{
    Q_OBJECT

public:
    explicit logger_widget(QWidget *parent = nullptr);
    ~logger_widget();

signals:


public slots:
    void onLibraryLogged(std::string message);


private:
    Ui::logger_widget *ui;

    integer::logger::errors err_init;
    integer::logger::integer_logger& logger = integer::logger::integer_logger::get_instance();
    integer_interface *myApp = qobject_cast<integer_interface *>(qApp);

};

and a declaration of the log static function outside the class

static void log(std::string message); 

In the logger_widget constructor I have the following two lines to define the connection

integer::logger::g_loggerCallback = log;
connect(myApp,&integer_interface::libraryLogged,this,&logger_widget::onLibraryLogged);

while log and onLibraryLogged implementations look like this

void logger_widget::onLibraryLogged(std::string message)
{
    ui->plainTextEdit_logger->appendPlainText(QString::fromStdString(message));
}

void log(std::string message)
{
    integer_interface *myApp = qobject_cast<integer_interface *>(qApp);
    emit myApp->libraryLogged(message);
}

constructor and function implementations are obviously in the corresponding logger_widget.cpp file

It compiles fine, but I get a runtime error "abort()" and the following message

qt.core.qobject.connect: QObject::connect(integer_interface, logger_widget): invalid nullptr parameter

[JonB]

@Gaetano03
So I assume that occurs at runtime when it hits

connect(myApp,&integer_interface::libraryLogged,this,&logger_widget::onLibraryLogged);

and indicates one of the two objects are nullptr. Check on line above with e.g.

qDebug() << myApp << this;

?

If myApp == nullptr, you did remember to create an integer_interface, not just a QApplication now, didn't you...??

Everywhere you go integer_interface *myApp = qobject_cast<integer_interface *>(qApp); you might follow that with Q_ASSERT(myApp); to verify all is well at that instant.

P.S.

integer_interface(int &argc, char *argv[]) {}; // empty constructor

Do you have integer_interface(int &argc, char *argv[]) : QApplication(argc, argv) somewhere?

[Gaetano03]

@JonB
I think the problem might be where I define myApp is not correct? Which is at the moment into the logger_widget class

when I qDebug as you said I get indeed the following value for myApp

QObject(0x0) logger_widget(0x1e04f63bcd0, name="logger_widget")

and the app crashes few seconds after it starts

Should I declare the myApp out of any member class as I did for the log function?

[JonB]

@Gaetano03

@JonB said in Add to Qt GUI logger functionality:

If myApp == nullptr, you did remember to create an integer_interface, not just a QApplication now, didn't you...??

??

[Gaetano03]

@JonB

Do you have integer_interface(int &argc, char *argv[]) : QApplication(argc, argv) somewhere?

ye I have it in an integer_interface.cpp, looks like this

#include "integer_interface.h"

integer_interface::integer_interface(int &argc, char *argv[])
    : QApplication(argc, argv)
{

}

??

I have it declared in my logger_widget.h class file (if you also see my previous reply), but was thinking maybe should be declared outside of the class?

Or maybe you meant something else from this

[Christian Ehrlicher]

@Gaetano03 said in Add to Qt GUI logger functionality:

I have it declared in my logger_widget.h class file (if you also see my previous reply), but was thinking maybe should be declared outside of the class?

You should also instantiate it somewhere.

[Gaetano03]

@Christian-Ehrlicher

I have it declared and instantiated both in the logger_widget.h class among the private members

private:
    Ui::logger_widget *ui;

    integer::logger::errors err_init;
    integer::logger::integer_logger& logger = integer::logger::integer_logger::get_instance();
    integer_interface *myApp = qobject_cast<integer_interface *>(qApp);

and in the static log function

void log(std::string message)
{
    integer_interface *myApp = qobject_cast<integer_interface *>(qApp);
    emit myApp->libraryLogged(message);
}

as suggested by @JonB

PS
@JonB doing as you suggested as sanity check with the following lines

    integer_interface *myApp = qobject_cast<integer_interface *>(qApp);
    Q_ASSERT(myApp);

gives a bunch of errors not sure I understand:
logger_widget.h:42:14: C++ requires a type specifier for all declarations

logger_widget.h:42:5: Expected ')'
0:0: :42:5: note: to match this '('

logger_widget.h:42:14: Duplicate member 'myApp'
logger_widget.h:41:24: previous declaration is here

[JonB]

@Gaetano03
Look, can you please show your main() function now. I have a funny feeling your still have QApplication a(argc, argv); there, and what do you think you actually need instead of that?

[JonB]

@Gaetano03 said in Add to Qt GUI logger functionality:

integer_interface *myApp = qobject_cast<integer_interface *>(qApp);
Q_ASSERT(myApp);

If that is in a .h where you are declaring member variables in a class definition you cannot add arbitrary C++ statements to execute..... Put the qobject_cast<> in the constructor, where you can verify it.

[Gaetano03]

@JonB
you have the right funny feeling, just realized how silly I was.

Everything works fine now and I get stuff printed on my QPlainText, at least for now XD.

Thanks a lot, really!

I really appreciate

[JonB]

@Gaetano03
Yeah, do you get the point? You can subclass QApplication to add whatever you want, but then you must create a SubclassedApplication not the original base class QApplication to use it. Just like any other subclassing.

qApp() macro returns QApplication *-type pointer, for whatever (single) QApplication instance has been created. If you derived and created the derived instance, qApp won't return that derived type (though it will return the correct derived instance). So to call methods/access variables you defined in your subclass that's why we qobject_cast<SubclassedApplication *>(qApp).

[Gaetano03]

@JonB
Yes I got the point, thanks also for this explanation!! That helps a lot understanding what I am doing behind the lines!!!

I have to admit that I worked so much on the library that I forgot for a while a main calling it and launching the app was even existing XD