Comparing QString with int value

[Swati777999]

Below is the code I wrote

QString aStr ='4';
if (aStr > 5)
  qDebug()<<"Condition-1";
else if (aStr<5)
   qDebug()<<"Condition-2";
else 
qDebug()<<"Condition-3";

I took the following test cases for this code ;
CASE-1 QString aStr='4';
CASE-2 QString aStr='5';
CASE-3 QString aStr='8';

For all the above cases, I got same result as "Condition-1".
Can someone explain me the reason and how to get the desired output?

[JKSH]

@Swati777999 said in Comparing QString with int value:

Can someone explain me the reason

Something looks wrong. Are you certain that you have shown us your actual code? Your compiler should not allow you to compare a QString with an int.

and how to get the desired output?

Convert your string to an int first.

[Kent-Dorfman]

@JKSH

If I had to guess, the operator overload

bool 	operator>(const char *other) const

Is probably to blame. dont know what kind of warnings OP has enabled/disabled, and in its rawest form (5) could be implicitly cast to a pointer, I guess.

[Swati777999]

@JKSH

yes, but how ? QString::toInt() is not working in this case for me.

[jsulm]

@Swati777999 said in Comparing QString with int value:

QString::toInt() is not working in this case for me

Why not?
What happens?

[ChrisW67]

@Swati777999 said in Comparing QString with int value:

QString aStr ='4';

This doesn't compile for me, there is no QString constructor accepting a char.
If you want a plain-old-char-string then:

QString aStr = "4";

As expected, aStr.toInt() works just fine.

QString aStr = "4";
if (aStr.toInt() > 5)
  qDebug()<<"Condition-1";
else if (aStr.toInt() < 5)
   qDebug()<<"Condition-2";
else
qDebug()<<"Condition-3";

qDebug() << aStr.toInt();

Output:

Condition-2
4