Getting the dimensions of a QTableWidget object

[Swati777999]

Hi All,

In the main window, my outer widget is QLayout inside which a QTableWidget resides.

Now, I want to get the dimensions of the inner widget which is of QTableWidget type, so that I can resize the outer widget which is of QLayout type.

Suppose my inner widget is
QTableWidget *first_table=new QTableWidget();
whereas my outer widget is
QGridLayout *tableLayout = new QGridLayout();

By first_table->width();, I can get the width of the inner widget but how to get its dimension.

Any suggestion will be appreciated.

Thanks! :)

[jsulm]

@Swati777999 said in Getting the dimensions of a QTableWidget object:

whereas my outer widget is
QGridLayout *tableLayout = new QGridLayout();

It's not a widget but a layout.

What's wrong with https://doc.qt.io/qt-5/qlayout.html#geometry ?

[Ketan__Patel__0011]

You can try this

ui->YourTableWidget->geometry();

it's Return Your TableWidget Location And Size;

[JonB]

Since the user is asking the same question and getting the same answers in thread https://forum.qt.io/topic/132497/how-to-get-the-dimensions-of-the-widgets, suggest people don't post further in this thread.