Need use some eval() command

LCorona

Ok, I put the needed instructions for use QJSEngine and apply the command evaluate, but maybe there is a missunderstanding, the evaluation returns an error, cant process the operator "->", I need to evaluate a commands that not are javascipt type, i need evaluate commands like objects assignments and other similar instrictios like this:

GCPGraph graph1* = ui->plot1->addGraph;
GCPGraph graph2* = ui->plot2->addGraph;
GCPGraph graph3* = ui->plot1->addGraph;
.
.
.
etc..

The needs are execute a repetitive set of instructions with several objects of the ui that the only way to avoid write all the code is construct the set using a QString and evaluate afte like this:

QString command="GCPGraph graph1* = ui->plot1->addGraph; GCPGraph graph2* = ui->plot2->addGraph; GCPGraph graph3* = ui->plot1->addGraph;"
eval(command);

Apparently QJSEngine cant do this.

Chris Kawa

C++ is a statically typed compiled language. There's no eval or anything like that in C++. You can't create and execute code from strings in runtime. That's what dynamic interpreted languages like javascript do.

What you're describing sound like you just need a simple for loop over some objects.

mrjj

@LCorona
Hi
Can you explain what you are trying to do as
"GCPGraph graph1* = ui->plot1->addGraph"
makes little sense.

I assume your are using QCustomPlot

The GCPGraph is a class from there.

so what should
GCPGraph graph1* = ui->plot1->addGraph
do ?

You seem to call
QCPGraph * QCustomPlot::addGraph

so are you trying to assign some variables of type "QCPGraph *"
from your plot1 and plot2 ??

LCorona

@mrjj
My App have 48 widgets on UI, each widget draw a plot grid, but each widget is promoted to other class, then I need asign each widget to an QCPGraph objet with the command

QCPGraph *graphX = ui->plotX->addGraph();

Where X es a number for identify each object and plot grid. The task are repetitive, and is clear, that is not good write the 48 lines of code plus agregates for assign the objects and the widgets, then the solution is made it in a loop. For that the QCPGraph are in a QVector, and the lines chane by this:

QVector<QCPGraph*>graphs(48);

for (i=0;i<graphs.lenght();i++)
{
graphs[i] = ui->plotX->addGraph();
}

but, how iterate over the widgets???? , plotX->addGraph(), (I dont know if QT have some iterative array of the ui objects), then the idea es build in a for a command a chain of commands with all generating instructions. Also, later need other chain of instructios for generate the names of each plot.

The main problem become for the several widgets of use, and because the promotion of them is made in the ui designer, not programatically, then iterate over the iu widgets is not possible for generalizing the code.

jsulm

@LCorona said in Need use some eval() command:

The task are repetitive, and is clear, that is not good write the 48

Then put all these ui->plotX pointers in a list and iterate over that list.

// Define your plots list and add the pointers to it, then:
for (i=0;i<graphs.lenght();i++)
{
    graphs[i] = plots[i]->addGraph();
}

mrjj

Hi

but, how iterate over the widgets????

You can use FIndChildren with QCustomPlot type to get list of all in UI

QList<QCustomPlot *> plots = findChildren<QCustomPlot*>();

the promotion of them is made in the ui designer, not programatically,

Actually, they are of right type in the code. the ui_xxx file generated is the right type even before runtime.
just try
ui->plot1-> and see that it suggest QCustomPlot functions.

So promotion does change type to the promoted one. just use compile file then code reflects the promoted type.

LCorona

@mrjj
Yes, thank you, seems good, only a last question, what is the order of elements of the QList?, the element 0 is the plot0, the element 1 is the plot1? , or depends of the order or creation in the interface?

mrjj

@LCorona
hi
I think it comes in creation order as it searches from the top of the widget tree.
You can look in setupUI function to see what the order is.

LCorona

@mrjj
Thanks, works really fine. Problem solved.

mrjj

@LCorona
Splendid. Happy plotting :)