Send image inside Json through QTcpSocket

[JonB]

@Tamfub
Dunno, let's start with

while(sock->bytesAvailable()){
    ds.startTransaction();
    ds >> dataReceived;
}
ds.commitTransaction();

Why would you (at least potentially) start multiple transactions and only commit once at the end?

Next, I don't understand your whole sequential bytesAvailable() loops. Why two loops? Are you sure your transactions/tests tally against what is being sent in the same fashion?

Practice code just sending string "hello", perhaps with transactions commented out, while you verify the protocol is correct? Then move to the base64 stuff. And debug out the first & last few characters sent & received to verify they correspond before you look at decoding. You want to discover where your issue is little by little.

[Tamfub]

@Christian-Ehrlicher @JonB
Ok, I guess I'll have to revise my protocol, then I'll return to the other problem later :)

[SGaist]

Hi,

@Tamfub said in Send image inside Json through QTcpSocket:

QString string = (QString)dataReceived;

dataReceived is a QByteArray, that cast is completely wrong.

[Tamfub]

@Christian-Ehrlicher @JonB
I've given a look to the fortune client and server examples and tried to toy with data.

In server.cpp, I replaced

out << fortunes[QRandomGenerator::global()->bounded(fortunes.size())];

with

QString str;
for(int i=0; i<1000000; i++)
    str.append("a");
out << str;

void Client::readFortune() became:

void Client::readFortune()
{
    in.startTransaction();

    QString data;
    in >> data;
    qDebug() << "data: " << data;

    if (!in.commitTransaction())
        return;

    qDebug() << "data (end): ";
    qDebug() << data;

//    if (nextFortune == currentFortune) {
//        QTimer::singleShot(0, this, &Client::requestNewFortune);
//        return;
//    }

//    currentFortune = nextFortune;
//    //statusLabel->setText(currentFortune);
//    qDebug() << "current: " << currentFortune;
//    getFortuneButton->setEnabled(true);
    qDebug() << "finished";
}

The output in the client is:

next:  ""
next (end): 
finished

I guess qDebug() does not print large data?

[JonB]

@Tamfub said in Send image inside Json through QTcpSocket:

I guess qDebug() does not print large data?

Do not rely on qDebug() output visibility. I think it says somewhere qDebug(qPrintable(qString)); or print QString::length().

[Tamfub]

@SGaist
Hi.
Ok, I guess I should use something like QString::fromLatin1(array), right?

[Tamfub]

@JonB
Ok, I put some printing of the sizes, and found out that receivedData.size() = 2 x sentData.size().

Server

ds << QString::fromLatin1(ba.toBase64());
qDebug() << "size: " << QString::fromLatin1(ba.toBase64()).size(); // 75684

Client

ds.startTransaction();
QByteArray data;
ds >> data;

if (!ds.commitTransaction())
        return;

qDebug() << "data(size): " << risp.size();  // 151368

How is this possible? If I try with

QByteArray str;
for(int i=0; i<1000000; i++)
       str.append("a");
ds << str;
qDebug() << "size: " << str.size();  // 1000000

instead, the two sizes match!

[JonB]

@Tamfub said in Send image inside Json through QTcpSocket:

qDebug() << "size: " << QString::fromLatin1(ba.toBase64()).size(); // 75684

qDebug() << "data(size): " << risp.size(); // 151368

What arithmetic formula do you notice connects the two numbers in your comments? :)

[Tamfub]

@JonB I already noticed the receivedData in double the sentData, I wrote it before. But I can't understand why.

[JonB]

@Tamfub
Because one is a QByteArray and one is a QString? You can't send one type, decode it as a different type, and expect them to be the same.

[mrjj]

@Tamfub
Hi
QString is 16 bit. QByteArray is 8bit

[Tamfub]

@JonB @mrjj
you're damn right, I didn't notice that. My bad :)
Thank you both! Now I will try to pack/unpack correctly.

[Tamfub]

I managed to fix the (un)packing during the sending/receiving part. Now I miss the final step: create a Pixmap from the received data and show it. To sum up:

Server

QImage imageObject;
imageObject.load(Path/to/image);
QPixmap image = QPixmap::fromImage(imageObject);

QByteArray ba;              // Construct a QByteArray object
QBuffer buffer(&ba);        // Construct a QBuffer object using the QbyteArray
image.save(&buffer, "JPG"); // Save the QImage data into the QBuffer


qjo.insert("request_type", PHOTO_REQUEST);
qjo.insert("photo", QString::fromLatin1(ba.toBase64()));

qDebug() << "Size of QString::fromLatin1(ba.toBase64())): " << QString::fromLatin1(ba.toBase64()).size();	// 470184

QJsonDocument doc(qjo);
QString strJson(doc.toJson(QJsonDocument::Compact));
info.append(strJson);
ds << info;

Client

ds.startTransaction();

QByteArray risp;
ds >> risp;
qDebug() << "risp: " << risp;

if (!ds.commitTransaction())
    return;

...

QJsonValue photo = obj.take("photo");
QByteArray ba = photo.toString().toLatin1();
qDebug() << "photo data size (latin): " << photo.toString().toLatin1().size();	// 470184
//qDebug() << "photo size (utf8): " << photo.toString().toUtf8().size();
QPixmap pm;

???  // Missing part

ui->myLabel->setPixmap(pm);

ui->myLabel has another Pixmap set at the moment. In the ??? part, I tried:

if(!pm.loadFromData(ba, "JPG")){
    qDebug() << "Error: data could not be loaded.";
    return;
}

and it always ended up printing the error message.

Then, I read this and tried

const uchar * const data = reinterpret_cast<const uchar *>(ba.constData());
qDebug() << "uchar size: " << data;

QPixmap pixmap = QPixmap::fromImage(
    QImage(
        data,
        ui->myLabel->width(),
        ui->myLabel->height(),
        QImage::Format_RGB888
    )
);

The previous Pixmap of ui->myLabel is removed, but now there is a white one. Any ideas?

[KroMignon]

@Tamfub said in Send image inside Json through QTcpSocket:

ow I miss the final step: create a Pixmap from the received data and show it. To sum up:

Have you take a look at QPixmap documentation? I think you will quickly find QPixmap::loadFromData()...

[Tamfub]

@KroMignon
Hi.
I eventually managed to show the image. I was missing:

ba = ba.fromBase64();

before pm.loadFromData(...), and now it works. Thanks!