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How to Split Hex String?

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  • JonBJ JonB

    @ahsan737
    I don't understand your question. I have stated what you should do.

    ahsan737A Offline
    ahsan737A Offline
    ahsan737
    wrote on last edited by
    #10

    @JonB sorry for the vague question but #mpergand has already responded to my query in great detail. Thank you for your kind response.

    KroMignonK 1 Reply Last reply
    0
    • ahsan737A ahsan737

      @JonB sorry for the vague question but #mpergand has already responded to my query in great detail. Thank you for your kind response.

      KroMignonK Offline
      KroMignonK Offline
      KroMignon
      wrote on last edited by
      #11

      @ahsan737 I don't believe you are understanding what you are asking/doing!

      First, please learn what is a "Base Numbered System":

      • base 2 (aka Binary)
      • base 8 (aka Octal)
      • base 10 (aka Decimal)
      • base 16 (aka Hexadecimal)

      There are many, many explanation available on internet, for example ==> https://www.mathsisfun.com/binary-decimal-hexadecimal.html

      Then you will learn that:

      • 80 in hexadecimal equals 128 in decimal
      • 0A in hexadecimal equals 10 in decimal
      • etc.

      It is an old maxim of mine that when you have excluded the impossible, whatever remains, however improbable, must be the truth. (Sherlock Holmes)

      ahsan737A 1 Reply Last reply
      3
      • KroMignonK KroMignon

        @ahsan737 I don't believe you are understanding what you are asking/doing!

        First, please learn what is a "Base Numbered System":

        • base 2 (aka Binary)
        • base 8 (aka Octal)
        • base 10 (aka Decimal)
        • base 16 (aka Hexadecimal)

        There are many, many explanation available on internet, for example ==> https://www.mathsisfun.com/binary-decimal-hexadecimal.html

        Then you will learn that:

        • 80 in hexadecimal equals 128 in decimal
        • 0A in hexadecimal equals 10 in decimal
        • etc.
        ahsan737A Offline
        ahsan737A Offline
        ahsan737
        wrote on last edited by ahsan737
        #12

        @KroMignon You completely misunderstood the question. Of course, I totally understand this base numbered system. I am not talking about Hex to Dec conversion. My question is about string format as it is supposed to start with "80" but it is ending up at that, so I want to ask how can I sort it out? (given that I do not have access to change incoming data format)

        KroMignonK JonBJ 2 Replies Last reply
        0
        • ahsan737A ahsan737

          @KroMignon You completely misunderstood the question. Of course, I totally understand this base numbered system. I am not talking about Hex to Dec conversion. My question is about string format as it is supposed to start with "80" but it is ending up at that, so I want to ask how can I sort it out? (given that I do not have access to change incoming data format)

          KroMignonK Offline
          KroMignonK Offline
          KroMignon
          wrote on last edited by KroMignon
          #13

          @ahsan737 I don't understand what you are trying to do.

          QByteArray is a container for char (qint8).
          If you what to convert the content of a QByteArray variable into hex string, simply read the documentation and you will found QbyteArray::toHex().

            QByteArray macAddress = QByteArray::fromHex("123456abcdef");
            macAddress.toHex(':'); // returns "12:34:56:ab:cd:ef"
            macAddress.toHex(0);   // returns "123456abcdef"
          

          If you want to convert a hex string to QByteArray, use QbyteArray::fromHex().

            QByteArray text = QByteArray::fromHex("517420697320677265617421");
            text.data();            // returns "Qt is great!"
          

          To decode binary data from QByteArray, the easiest way it do use QDataStream (see post from @mpergand)

          So what is your problem?

          It is an old maxim of mine that when you have excluded the impossible, whatever remains, however improbable, must be the truth. (Sherlock Holmes)

          1 Reply Last reply
          0
          • ahsan737A ahsan737

            @KroMignon You completely misunderstood the question. Of course, I totally understand this base numbered system. I am not talking about Hex to Dec conversion. My question is about string format as it is supposed to start with "80" but it is ending up at that, so I want to ask how can I sort it out? (given that I do not have access to change incoming data format)

            JonBJ Online
            JonBJ Online
            JonB
            wrote on last edited by
            #14

            @ahsan737
            Then @KroMignon is not the only one who does not understand what you are saying/asking for.

            I have looked at your "attached picture" and I do not understand what it is you want to achieve. You show an "Actual Outcome" which has two windows, one showing some hex numbers and the other the decimal equivalents. You show a "Desired Outcome" which has two lines, one showing hex numbers and the other the decimal equivalents. I don't understand what you want to do to what to achieve what.

            If all you want to do is take either a decimal or a hex string of numbers and output a string in the other base, what is there to say other than you need to convert the input string in the correct base to its number and then convert that to string in the desired output base?

            I do not know what your "I am not able to make changes to the incoming data format. " signifies, there is no need to change incoming format.

            ahsan737A 1 Reply Last reply
            0
            • JonBJ JonB

              @ahsan737
              Then @KroMignon is not the only one who does not understand what you are saying/asking for.

              I have looked at your "attached picture" and I do not understand what it is you want to achieve. You show an "Actual Outcome" which has two windows, one showing some hex numbers and the other the decimal equivalents. You show a "Desired Outcome" which has two lines, one showing hex numbers and the other the decimal equivalents. I don't understand what you want to do to what to achieve what.

              If all you want to do is take either a decimal or a hex string of numbers and output a string in the other base, what is there to say other than you need to convert the input string in the correct base to its number and then convert that to string in the desired output base?

              I do not know what your "I am not able to make changes to the incoming data format. " signifies, there is no need to change incoming format.

              ahsan737A Offline
              ahsan737A Offline
              ahsan737
              wrote on last edited by
              #15

              @KroMignon
              @JonB
              thanks to both of you for paying attention, Now I try to explain at my best.
              Please look at the incoming data pattern in the Desired Outcome, it is starting with "80 0A" but if you look at the Actual Outcome section (green Hex numbers), "80 0A" is the end of the line and then next line starts. So my concern is how can I deal with this situation in order to split data correctly in relevant parts. I hope now I have explained it well.

              jsulmJ 1 Reply Last reply
              0
              • ahsan737A ahsan737

                @KroMignon
                @JonB
                thanks to both of you for paying attention, Now I try to explain at my best.
                Please look at the incoming data pattern in the Desired Outcome, it is starting with "80 0A" but if you look at the Actual Outcome section (green Hex numbers), "80 0A" is the end of the line and then next line starts. So my concern is how can I deal with this situation in order to split data correctly in relevant parts. I hope now I have explained it well.

                jsulmJ Offline
                jsulmJ Offline
                jsulm
                Lifetime Qt Champion
                wrote on last edited by
                #16

                @ahsan737 You simply start to output the values at the wrong index (see the line "00 00 80 0A"). You need to locate 80 first and start from there.

                https://forum.qt.io/topic/113070/qt-code-of-conduct

                ahsan737A 1 Reply Last reply
                2
                • jsulmJ jsulm

                  @ahsan737 You simply start to output the values at the wrong index (see the line "00 00 80 0A"). You need to locate 80 first and start from there.

                  ahsan737A Offline
                  ahsan737A Offline
                  ahsan737
                  wrote on last edited by
                  #17

                  @jsulm the confusion is that it won't be 80 every time, this number will keep updating with every chunk of data.

                  jsulmJ 1 Reply Last reply
                  0
                  • ahsan737A ahsan737

                    @jsulm the confusion is that it won't be 80 every time, this number will keep updating with every chunk of data.

                    jsulmJ Offline
                    jsulmJ Offline
                    jsulm
                    Lifetime Qt Champion
                    wrote on last edited by
                    #18

                    @ahsan737 Do you have any kind of protocol?! How do you know where a block starts and ends?

                    https://forum.qt.io/topic/113070/qt-code-of-conduct

                    ahsan737A 1 Reply Last reply
                    2
                    • jsulmJ jsulm

                      @ahsan737 Do you have any kind of protocol?! How do you know where a block starts and ends?

                      ahsan737A Offline
                      ahsan737A Offline
                      ahsan737
                      wrote on last edited by ahsan737
                      #19

                      @jsulm
                      CR or LF are not being used for the new line.
                      Communication: 9600 baud, 8 data bits, no parity and one stop using Bluetooth (SPP)

                      Data Frame:
                      Frame.JPG

                      is this info sufficient to detect the start of the block?

                      1 Reply Last reply
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