[Solved]Appending to Last added QString in QStringList

[Rututraj]

Hello All,
As my previous post this might also be a silly question, but I am processing a data and creating QStringList as its output,
but at certain point I want to append to same index of QStringList multiple times.
PseudoCode:

QStringList mylist;
for(i = 0; i < 35; i++)
{
mylist.append("this is ");
if(condition)
{
mylist.append("the output");
}
}

So I want "This is the output" as single string appended to same location in QStringList.
Is this possible?

Thanks!

[KroMignon]

@Rututraj said in Appending to Last added QString in QStringList:

So I want "This is the output" as single string appended to same location in QStringList.
Is this possible?
Thanks!

Why not just use QStringList::last()?

QStringList mylist;
for(i = 0; i < 35; i++)
{
    mylist.append(QString("this is"));
    if(condition) 
        mylist.last().append(" the output");
}

[J.Hilk]

@Rututraj

the obvious solution would be to check the condition before inserting (as it's inside your loop)

QStringList mylist;
for(i = 0; i < 35; i++)
{
     QString str("this is");
     if(condition) 
           mylist.append(str);
     else
           mylist.append(str + QString("the output"));
}

alternatively:

QStringList mylist;
for(i = 0; i < 35; i++)
{
     mylist.append(QString("this is"));
     if(condition) 
         mylist[mylist.size()-1] = mylist.last() + QString("the output");
}

[KroMignon]

@Rututraj said in Appending to Last added QString in QStringList:

So I want "This is the output" as single string appended to same location in QStringList.
Is this possible?
Thanks!

Why not just use QStringList::last()?

QStringList mylist;
for(i = 0; i < 35; i++)
{
    mylist.append(QString("this is"));
    if(condition) 
        mylist.last().append(" the output");
}

[J.Hilk]

@KroMignon
I could have sworn last() is a const reference only, but apparently it also has a pure reference overload 🤷‍♂️

[artwaw]

@J-Hilk Other way around: const T &QList::last() const is an overload of T &QList::last(). I was surprised as well.

[VRonin]

Just a side note in all the answers above where QString(const char*) is used, it should be replaced with QStringLiteral (see docs for the explanation)

[Rututraj]

@KroMignon This works fine, Thanks :)