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can not print correctly after convert QString to char *

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  • Christian EhrlicherC Christian Ehrlicher

    @Mozzie said in can not print correctly after convert QString to char *:

    char* p = s.toUtf8().data();

    C++ basics - you're creating a temporary here so p points to garbage after this statement.

    MozzieM Offline
    MozzieM Offline
    Mozzie
    wrote on last edited by
    #15

    @Christian-Ehrlicher
    Thank you very much, and thank other replyer.
    I think i understand your reply, and I do fogot the temp object , maybe because I also use java a lot.

    and i alse have a few questions:

    1. where is the temp object in memory, stack or heap or somewhere else.
    2. if it is on stack, it can not remain until the stack is finished
    Christian EhrlicherC 1 Reply Last reply
    0
    • hskoglundH hskoglund

      @Mozzie You had a bit of bad luck, if you compile in Release mode instead of Debug it'll work fine

      "hello world"
      hello world
      hello world
      hello world
      

      And if you switch to MinGW compiler it'll work both in Debug and Release :-)

      JonBJ Offline
      JonBJ Offline
      JonB
      wrote on last edited by JonB
      #16

      @hskoglund
      Your findings are even more scary in view of the above conversation! :)

      @aha_1980 , and others
      I think I get it. Also that it's nothing to do with Qt specific classes. Not because of shared QByteArrays and stuff.

      So to summarize: s.toUtf8() only "lasts" for the lifetime of the statement (probably rather expression) it is in. But if you go QByteArray b = s.toUtf8() then the b will persist OK as usual. Right?

      hskoglundH 1 Reply Last reply
      3
      • hskoglundH hskoglund

        @Mozzie You had a bit of bad luck, if you compile in Release mode instead of Debug it'll work fine

        "hello world"
        hello world
        hello world
        hello world
        

        And if you switch to MinGW compiler it'll work both in Debug and Release :-)

        aha_1980A Offline
        aha_1980A Offline
        aha_1980
        Lifetime Qt Champion
        wrote on last edited by
        #17

        @hskoglund said in can not print correctly after convert QString to char *:

        And if you switch to MinGW compiler it'll work both in Debug and Release :-)

        Today. Tomorrow it will run away with your wife, bankrupt your workplace and aim for world domination.

        t

        Qt has to stay free or it will die.

        1 Reply Last reply
        4
        • JonBJ JonB

          @hskoglund
          Your findings are even more scary in view of the above conversation! :)

          @aha_1980 , and others
          I think I get it. Also that it's nothing to do with Qt specific classes. Not because of shared QByteArrays and stuff.

          So to summarize: s.toUtf8() only "lasts" for the lifetime of the statement (probably rather expression) it is in. But if you go QByteArray b = s.toUtf8() then the b will persist OK as usual. Right?

          hskoglundH Offline
          hskoglundH Offline
          hskoglund
          wrote on last edited by hskoglund
          #18

          Yes! I's just luck that the bits are still around in Release mode. The Debug mode output of ??????? could happen in Release also some other day when the sun doesn't shin.e

          Anyway, one simple modification to make it waterproof could be:

          QString s = "hello world";
          qDebug() << s;
          qDebug() << s.toUtf8().data();
          
          QByteArray a = s.toUtf8();
          char* p = a.data();
          qDebug() << p;
          
          QByteArray b = s.toUtf8();
          p = b.data();
          qDebug() << p;
          

          Edit: too fast, didn't read the code in the 3d paragraph ! But they are both waterproof now :-)

          1 Reply Last reply
          1
          • hskoglundH hskoglund

            @Mozzie You had a bit of bad luck, if you compile in Release mode instead of Debug it'll work fine

            "hello world"
            hello world
            hello world
            hello world
            

            And if you switch to MinGW compiler it'll work both in Debug and Release :-)

            MozzieM Offline
            MozzieM Offline
            Mozzie
            wrote on last edited by
            #19

            @hskoglund
            that is interesting .
            i dont have test on linux or MinGW, maybe vs and MinGW is diffrent on deal with temp object?

            hskoglundH 1 Reply Last reply
            0
            • MozzieM Mozzie

              @hskoglund
              that is interesting .
              i dont have test on linux or MinGW, maybe vs and MinGW is diffrent on deal with temp object?

              hskoglundH Offline
              hskoglundH Offline
              hskoglund
              wrote on last edited by
              #20

              @Mozzie Actually MinGW works on Windows as well (I prefer it over MSVC2017 because MinGW compiles/builds my projects faster).

              1 Reply Last reply
              0
              • MozzieM Mozzie

                @Christian-Ehrlicher
                Thank you very much, and thank other replyer.
                I think i understand your reply, and I do fogot the temp object , maybe because I also use java a lot.

                and i alse have a few questions:

                1. where is the temp object in memory, stack or heap or somewhere else.
                2. if it is on stack, it can not remain until the stack is finished
                Christian EhrlicherC Offline
                Christian EhrlicherC Offline
                Christian Ehrlicher
                Lifetime Qt Champion
                wrote on last edited by
                #21

                @Mozzie said in can not print correctly after convert QString to char *:

                where is the temp object in memory, stack or heap or somewhere else.

                It's on the stack since you did not allocate it with new

                if it is on stack, it can not remain until the stack is finished

                No, this is not allowed since it's unnamed.

                It's also not c++ specific - you can do the same (in a little bit more obvious way) in C:

                int *myPtr = nullptr;
                {
                  int a = 3;
                  myPtr = &a;
                  printf("%d\n", *myPtr);   // works fine
                }
                printf("%d\n", *myPtr);   // works on garbage and may eat kitten
                

                Qt Online Installer direct download: https://download.qt.io/official_releases/online_installers/
                Visit the Qt Academy at https://academy.qt.io/catalog

                JonBJ MozzieM 2 Replies Last reply
                3
                • Christian EhrlicherC Christian Ehrlicher

                  @Mozzie said in can not print correctly after convert QString to char *:

                  where is the temp object in memory, stack or heap or somewhere else.

                  It's on the stack since you did not allocate it with new

                  if it is on stack, it can not remain until the stack is finished

                  No, this is not allowed since it's unnamed.

                  It's also not c++ specific - you can do the same (in a little bit more obvious way) in C:

                  int *myPtr = nullptr;
                  {
                    int a = 3;
                    myPtr = &a;
                    printf("%d\n", *myPtr);   // works fine
                  }
                  printf("%d\n", *myPtr);   // works on garbage and may eat kitten
                  
                  JonBJ Offline
                  JonBJ Offline
                  JonB
                  wrote on last edited by JonB
                  #22

                  @Christian-Ehrlicher said in can not print correctly after convert QString to char *:

                  int *myPtr = nullptr;

                  Never heard of nullptr in C ;-) NULL was much nicer to read anyway.

                  MozzieM 1 Reply Last reply
                  0
                  • JonBJ JonB

                    @aha_1980
                    Wow, OK, yes, I need to read! My problem is I have been "spoiled" by using C# and then Python/PyQt/PySide2 for so long now that I rarely have to think about this!

                    So let's take a basic, if my C++ holds up. If I write a function

                    QByteArray func()
                    {
                        QByteArray qb;
                        return qb;
                    }
                    

                    does that return such a "temporary object"? And that would be true for any class/struct I decalred and then returned in that fashion?

                    jsulmJ Offline
                    jsulmJ Offline
                    jsulm
                    Lifetime Qt Champion
                    wrote on last edited by
                    #23
                    This post is deleted!
                    1 Reply Last reply
                    0
                    • Christian EhrlicherC Christian Ehrlicher

                      @Mozzie said in can not print correctly after convert QString to char *:

                      where is the temp object in memory, stack or heap or somewhere else.

                      It's on the stack since you did not allocate it with new

                      if it is on stack, it can not remain until the stack is finished

                      No, this is not allowed since it's unnamed.

                      It's also not c++ specific - you can do the same (in a little bit more obvious way) in C:

                      int *myPtr = nullptr;
                      {
                        int a = 3;
                        myPtr = &a;
                        printf("%d\n", *myPtr);   // works fine
                      }
                      printf("%d\n", *myPtr);   // works on garbage and may eat kitten
                      
                      MozzieM Offline
                      MozzieM Offline
                      Mozzie
                      wrote on last edited by
                      #24

                      @Christian-Ehrlicher
                      thanks, it helped a lot.
                      and i have a hunch

                      {//main stack
                      	QString s = "hello world";
                      	char* p = nullptr;
                      	{// toUtf8()
                      		QByteArray b = s.toUtf8();
                      		{// data();
                      			p = b.data();
                      			qDebug() << p; // does this is same as "qDebug() << s.toUtf8().data();"
                      		}
                      	}
                      	// b is freed
                      	qDebug() << p; // this is same as "char * p = s.toUtf8().data(); qDebug() << p;"
                      }
                      

                      does this right?

                      Christian EhrlicherC 1 Reply Last reply
                      1
                      • JonBJ JonB

                        @Christian-Ehrlicher said in can not print correctly after convert QString to char *:

                        int *myPtr = nullptr;

                        Never heard of nullptr in C ;-) NULL was much nicer to read anyway.

                        MozzieM Offline
                        MozzieM Offline
                        Mozzie
                        wrote on last edited by
                        #25

                        @JonB
                        nullptr is a c++11 key word, you can still use NULL, but NULL is defined as 0, sometimes it may cause some problem.

                        such as:

                        
                        void test(int *p)
                        {
                        	qDebug() << "int *";
                        }
                        void test(int i)
                        {
                        	qDebug() << "int";
                        }
                        test(NULL);
                        test(nullptr);
                        

                        output

                        int
                        int *
                        
                        JonBJ 1 Reply Last reply
                        1
                        • MozzieM Mozzie

                          @JonB
                          nullptr is a c++11 key word, you can still use NULL, but NULL is defined as 0, sometimes it may cause some problem.

                          such as:

                          
                          void test(int *p)
                          {
                          	qDebug() << "int *";
                          }
                          void test(int i)
                          {
                          	qDebug() << "int";
                          }
                          test(NULL);
                          test(nullptr);
                          

                          output

                          int
                          int *
                          
                          JonBJ Offline
                          JonBJ Offline
                          JonB
                          wrote on last edited by JonB
                          #26

                          @Mozzie
                          I know this :) That's why I was picking @Christian-Ehrlicher on his use of nullptr in his C program, it was just intended for amusement ;-)

                          1 Reply Last reply
                          1
                          • MozzieM Mozzie

                            @Christian-Ehrlicher
                            thanks, it helped a lot.
                            and i have a hunch

                            {//main stack
                            	QString s = "hello world";
                            	char* p = nullptr;
                            	{// toUtf8()
                            		QByteArray b = s.toUtf8();
                            		{// data();
                            			p = b.data();
                            			qDebug() << p; // does this is same as "qDebug() << s.toUtf8().data();"
                            		}
                            	}
                            	// b is freed
                            	qDebug() << p; // this is same as "char * p = s.toUtf8().data(); qDebug() << p;"
                            }
                            

                            does this right?

                            Christian EhrlicherC Offline
                            Christian EhrlicherC Offline
                            Christian Ehrlicher
                            Lifetime Qt Champion
                            wrote on last edited by
                            #27

                            @Mozzie said in can not print correctly after convert QString to char *:

                            does this right?

                            Yes, exactly.

                            Qt Online Installer direct download: https://download.qt.io/official_releases/online_installers/
                            Visit the Qt Academy at https://academy.qt.io/catalog

                            MozzieM 1 Reply Last reply
                            0
                            • Christian EhrlicherC Christian Ehrlicher

                              @Mozzie said in can not print correctly after convert QString to char *:

                              does this right?

                              Yes, exactly.

                              MozzieM Offline
                              MozzieM Offline
                              Mozzie
                              wrote on last edited by
                              #28

                              @Christian-Ehrlicher
                              thanks.

                              1 Reply Last reply
                              0

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