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QStackedWidget: How to check if the next widget should be shown

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  • H hobbyProgrammer
    21 Nov 2019, 12:33

    @J-Hilk alright, but how would I check if the login is correct if there's no function definition?

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    J Offline
    J.Hilk
    Moderators
    wrote on 21 Nov 2019, 12:36 last edited by J.Hilk
    #14

    @hobbyProgrammer

    the idea would be, that you emit the signal, as soon as your function verifies, that the login was successful !

    void LoginWidget::on_pushButton_clicked()
    {
           QString username = ui->lineEdit_2->text();
            QString password = ui->lineEdit->text();
        
            if(username == "Test" && password == "Test123")
            {
                 emit loginSuccessful();
            }
    }
    

    Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct


    Q: What's that?
    A: It's blue light.
    Q: What does it do?
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    1 Reply Last reply
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    • H hobbyProgrammer
      21 Nov 2019, 12:33

      @J-Hilk alright, but how would I check if the login is correct if there's no function definition?

      J Offline
      J Offline
      JonB
      wrote on 21 Nov 2019, 12:37 last edited by JonB
      #15

      @hobbyProgrammer
      Subject to @J-Hilk suggesting an alternative, as I wrote earlier retain your loginSuccesfull() as the slot for the pushbutton click. Have it emit a signal you define on successful validation of the widgets, the signal is a separate thing from your function which you must define as per the Qt/C++ rules.

      EDIT OK, @J-Hilk's code is the same thing, it's just that he has defined the pushbutton slot as on_pushButton_clicked() and the signal as logInSuccessful, so there is no longer any (non-signal) function named loginSuccesfull().

      H 1 Reply Last reply 21 Nov 2019, 12:53
      0
      • J JonB
        21 Nov 2019, 12:37

        @hobbyProgrammer
        Subject to @J-Hilk suggesting an alternative, as I wrote earlier retain your loginSuccesfull() as the slot for the pushbutton click. Have it emit a signal you define on successful validation of the widgets, the signal is a separate thing from your function which you must define as per the Qt/C++ rules.

        EDIT OK, @J-Hilk's code is the same thing, it's just that he has defined the pushbutton slot as on_pushButton_clicked() and the signal as logInSuccessful, so there is no longer any (non-signal) function named loginSuccesfull().

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        H Offline
        hobbyProgrammer
        wrote on 21 Nov 2019, 12:53 last edited by
        #16

        @JonB alright, so using that code and these lines:

            LoginWidget *login = qobject_cast<LoginWidget*>(ui->stackedWidget->widget(0));
            connect(login, SIGNAL(loginSuccesfull()), this, SLOT(showApp()));
        

        should result in showApp to happen anytime the login was succesfull?

        J 1 Reply Last reply 21 Nov 2019, 13:04
        0
        • H hobbyProgrammer
          21 Nov 2019, 12:53

          @JonB alright, so using that code and these lines:

              LoginWidget *login = qobject_cast<LoginWidget*>(ui->stackedWidget->widget(0));
              connect(login, SIGNAL(loginSuccesfull()), this, SLOT(showApp()));
          

          should result in showApp to happen anytime the login was succesfull?

          J Offline
          J Offline
          JonB
          wrote on 21 Nov 2019, 13:04 last edited by
          #17

          @hobbyProgrammer
          I'm hoping so! Did you try it?

          H 1 Reply Last reply 21 Nov 2019, 13:09
          0
          • J JonB
            21 Nov 2019, 13:04

            @hobbyProgrammer
            I'm hoping so! Did you try it?

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            H Offline
            hobbyProgrammer
            wrote on 21 Nov 2019, 13:09 last edited by
            #18

            @JonB yes and it didn't work. I tried debugging but I can't seem to find what's going wrong. It hits the code where the emit loginSuccessfull() is set, but it doesn't go to the SLOT where it's connected to and it ends in :

            while (!d->exit.loadAcquire())
                    processEvents(flags | WaitForMoreEvents | EventLoopExec);
            
            J 1 Reply Last reply 21 Nov 2019, 13:13
            0
            • H hobbyProgrammer
              21 Nov 2019, 13:09

              @JonB yes and it didn't work. I tried debugging but I can't seem to find what's going wrong. It hits the code where the emit loginSuccessfull() is set, but it doesn't go to the SLOT where it's connected to and it ends in :

              while (!d->exit.loadAcquire())
                      processEvents(flags | WaitForMoreEvents | EventLoopExec);
              
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              J Offline
              jsulm
              Lifetime Qt Champion
              wrote on 21 Nov 2019, 13:13 last edited by
              #19

              @hobbyProgrammer Did you make sure

              connect(login, SIGNAL(loginSuccesfull()), this, SLOT(showApp()));
              

              succeeded? And is this "login" the one you're actually showing?

              https://forum.qt.io/topic/113070/qt-code-of-conduct

              H 1 Reply Last reply 21 Nov 2019, 13:18
              1
              • J jsulm
                21 Nov 2019, 13:13

                @hobbyProgrammer Did you make sure

                connect(login, SIGNAL(loginSuccesfull()), this, SLOT(showApp()));
                

                succeeded? And is this "login" the one you're actually showing?

                H Offline
                H Offline
                hobbyProgrammer
                wrote on 21 Nov 2019, 13:18 last edited by
                #20

                @jsulm
                it should be since I'm doing this:

                    LoginWidget *login = qobject_cast<LoginWidget*>(ui->stackedWidget->widget(0));
                
                J 1 Reply Last reply 21 Nov 2019, 13:19
                0
                • H hobbyProgrammer
                  21 Nov 2019, 13:18

                  @jsulm
                  it should be since I'm doing this:

                      LoginWidget *login = qobject_cast<LoginWidget*>(ui->stackedWidget->widget(0));
                  
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                  J Offline
                  jsulm
                  Lifetime Qt Champion
                  wrote on 21 Nov 2019, 13:19 last edited by
                  #21

                  @hobbyProgrammer And connect succeeded?

                  https://forum.qt.io/topic/113070/qt-code-of-conduct

                  H 1 Reply Last reply 21 Nov 2019, 13:24
                  1
                  • J jsulm
                    21 Nov 2019, 13:19

                    @hobbyProgrammer And connect succeeded?

                    H Offline
                    H Offline
                    hobbyProgrammer
                    wrote on 21 Nov 2019, 13:24 last edited by
                    #22

                    @jsulm I'm not sure, but I don't think so.

                    J 1 Reply Last reply 21 Nov 2019, 13:26
                    0
                    • H hobbyProgrammer
                      21 Nov 2019, 13:24

                      @jsulm I'm not sure, but I don't think so.

                      J Offline
                      J Offline
                      jsulm
                      Lifetime Qt Champion
                      wrote on 21 Nov 2019, 13:26 last edited by
                      #23

                      @hobbyProgrammer said in QStackedWidget: How to check if the next widget should be shown:

                      but I don't think so

                      Then it can't work.
                      Use new Qt5 connect syntax to be sure signal/slot are really connected:

                      connect(login, &LoginWidget::loginSuccesfull, this, &MainWindow::showApp);
                      

                      https://forum.qt.io/topic/113070/qt-code-of-conduct

                      H 1 Reply Last reply 21 Nov 2019, 13:27
                      2
                      • J jsulm
                        21 Nov 2019, 13:26

                        @hobbyProgrammer said in QStackedWidget: How to check if the next widget should be shown:

                        but I don't think so

                        Then it can't work.
                        Use new Qt5 connect syntax to be sure signal/slot are really connected:

                        connect(login, &LoginWidget::loginSuccesfull, this, &MainWindow::showApp);
                        
                        H Offline
                        H Offline
                        hobbyProgrammer
                        wrote on 21 Nov 2019, 13:27 last edited by
                        #24

                        @jsulm yes thank you. That worked!

                        Thank you so much for you patience and help.

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                        • J Offline
                          J Offline
                          J.Hilk
                          Moderators
                          wrote on 21 Nov 2019, 13:27 last edited by
                          #25

                          Because this is getting out of hand:

                          https://github.com/DeiVadder/LoginExample


                          Be aware of the Qt Code of Conduct, when posting : https://forum.qt.io/topic/113070/qt-code-of-conduct


                          Q: What's that?
                          A: It's blue light.
                          Q: What does it do?
                          A: It turns blue.

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                          21 Nov 2019, 13:26

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