QTest fails to compile when in QCOMPARE use classes under some namespace

RonaldViscarraL

Lets say we have:

namespace MyNamespace {
class MyClass {
public :
    QString a;
};
}

and in test unit:

....
#include "myclass.h"
using namespace MyNamespace;
....

test_case1 {
    MyClass myClass;
    myClass.a = "test";

    MyClass myClass2;
    myClass2.a = "test";

    QCOMPARE(myClass, myClass2); //Fails to compile 
}

operator==(const MyClass &class1, MyClass &class2) {
    return (class1.a == class2.a);
}

it fails in QCOMPARE

error: no match for ‘operator==’ (operand types are ‘const MyNamespace MyClass’ and ‘const MyNamespace MyClass’)

some idea?

RonaldViscarraL

I solved by wrapping the definition of operator == into std namespace

    namespace std {
    bool operator==(const MyNamespace::MyClass class1, const MyNamespace::MyClass class2)
    {
    return (class1.a == class2.a);       
    }
    }

mrjj

Hi
did you try to make both parameters for the operator const ?
The signature is
bool operator==(const X& lhs, const X& rhs)

RonaldViscarraL

@mrjj yes, both are const

bool operator==(const MyNamespace::MyClass &class1, const MyNamespace::Myclass &class2) {
    return (class1.a == class2.a);
}

without using namespace works as expected.

SGaist

Hi,

Can you show the complete declaration of your class and operator ?

RonaldViscarraL

I solved by wrapping the definition of operator == into std namespace

    namespace std {
    bool operator==(const MyNamespace::MyClass class1, const MyNamespace::MyClass class2)
    {
    return (class1.a == class2.a);       
    }
    }