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Parse large text file

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  • SGaistS Offline
    SGaistS Offline
    SGaist
    Lifetime Qt Champion
    wrote on last edited by SGaist
    #4

    Hi,

    The expression you are looking for is "X(\\d+(?:\\.\\d+)?) Y(\\d+(?:\\.\\d+)?)".

    You should rather do the rounding with the captured data otherwise you will lose precession.

    You can use the QRegularExpression tool to test your expressions.

    [edit: Fixed RE missing . escaping SGaist]

    Interested in AI ? www.idiap.ch
    Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

    1 Reply Last reply
    5
    • ODБOïO Offline
      ODБOïO Offline
      ODБOï
      wrote on last edited by
      #5

      You are awesome guys, thank you so much for quick/complete answers

      1 Reply Last reply
      0
      • SGaistS Offline
        SGaistS Offline
        SGaist
        Lifetime Qt Champion
        wrote on last edited by SGaist
        #6

        @LeLev take a look again at the expression. I forgot to escape the .. Therefore the expression was "wrong" in the sense that it will also find values like X1231a212.

        Interested in AI ? www.idiap.ch
        Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

        ODБOïO 1 Reply Last reply
        2
        • SGaistS SGaist

          @LeLev take a look again at the expression. I forgot to escape the .. Therefore the expression was "wrong" in the sense that it will also find values like X1231a212.

          ODБOïO Offline
          ODБOïO Offline
          ODБOï
          wrote on last edited by ODБOï
          #7

          @SGaist got it, thank you!

          1 Reply Last reply
          0
          • ODБOïO Offline
            ODБOïO Offline
            ODБOï
            wrote on last edited by
            #8

            Hi !
            I have lot of troubles trying to use the tool @SGaist
            suggested to me. I want to edit my QRegularExpression so it also can catch lines where there is only X or only Y

            N9 G40 X411 Y7.62 // capture 
            N3 G40 Y6000 // << capture this also
            N1 G0 X411 Y7.52 // capture
            N3 G40 X-6000 // << capture this also
            
            
            // ...open file 
             const QRegularExpression regx("X([-+]?\\d*\\.?\\d+)\\s+Y([-+]?\\d*\\.?\\d+)");
                QTextStream in(&file);
            
                while(!in.atEnd()) {
            
                    QString line = in.readLine();
                    const QRegularExpressionMatch reMatch = regx.match(line);
                    bool iok;
                    if(reMatch.hasMatch()){
            
                        double lx = reMatch.captured(1).toDouble();
                        double ly = reMatch.captured(2).toDouble();
            
                        qDebug()<<"X : " << lx << " ly" << ly;
                  
            //please tell me if there is a more efficient way to get maximum/minimum X  and  maximum/minimum Y in this file, 
                        if(lx<minX)
                            minX=lx;
                        else if (lx>maxX) maxX=lx;
            
                        if(ly<minY)
                            minY=ly;
                        else if (ly>maxY) maxY=ly;
                    }
                }
            

            My final aim is to get maximum x and y And minimum x and y in the whole file
            Thank you

            kshegunovK 1 Reply Last reply
            0
            • ODБOïO ODБOï

              Hi !
              I have lot of troubles trying to use the tool @SGaist
              suggested to me. I want to edit my QRegularExpression so it also can catch lines where there is only X or only Y

              N9 G40 X411 Y7.62 // capture 
              N3 G40 Y6000 // << capture this also
              N1 G0 X411 Y7.52 // capture
              N3 G40 X-6000 // << capture this also
              
              
              // ...open file 
               const QRegularExpression regx("X([-+]?\\d*\\.?\\d+)\\s+Y([-+]?\\d*\\.?\\d+)");
                  QTextStream in(&file);
              
                  while(!in.atEnd()) {
              
                      QString line = in.readLine();
                      const QRegularExpressionMatch reMatch = regx.match(line);
                      bool iok;
                      if(reMatch.hasMatch()){
              
                          double lx = reMatch.captured(1).toDouble();
                          double ly = reMatch.captured(2).toDouble();
              
                          qDebug()<<"X : " << lx << " ly" << ly;
                    
              //please tell me if there is a more efficient way to get maximum/minimum X  and  maximum/minimum Y in this file, 
                          if(lx<minX)
                              minX=lx;
                          else if (lx>maxX) maxX=lx;
              
                          if(ly<minY)
                              minY=ly;
                          else if (ly>maxY) maxY=ly;
                      }
                  }
              

              My final aim is to get maximum x and y And minimum x and y in the whole file
              Thank you

              kshegunovK Offline
              kshegunovK Offline
              kshegunov
              Moderators
              wrote on last edited by
              #9

              https://regex101.com/r/n42ANB/1

              When and/or if you use it, you must escape it properly for C++.

              Read and abide by the Qt Code of Conduct

              ODБOïO 1 Reply Last reply
              2
              • kshegunovK kshegunov

                https://regex101.com/r/n42ANB/1

                When and/or if you use it, you must escape it properly for C++.

                ODБOïO Offline
                ODБOïO Offline
                ODБOï
                wrote on last edited by
                #10

                @kshegunov hi
                thak you.
                i only doubled the " \ "s

                // (X(-?\d+(?:\.\d+)?))?\s*(Y(-?\d+(?:\.\d+)?))? 
                 const QRegularExpression regx("(X(-?\\d+(?:\\.\\d+)?))?\\s*(Y(-?\\d+(?:\\.\\d+)?))?");
                

                I tested your exemple on regex101.com and it is doind what i need. But in My program i get Zeros only

                1 Reply Last reply
                0
                • VRoninV Offline
                  VRoninV Offline
                  VRonin
                  wrote on last edited by VRonin
                  #11
                  This post is deleted!
                  1 Reply Last reply
                  0
                  • SGaistS Offline
                    SGaistS Offline
                    SGaist
                    Lifetime Qt Champion
                    wrote on last edited by SGaist
                    #12

                    Because you are using way more capturing groups than you need and are not handling the case where there's no capture which is allowed since you make the whole thing optional.

                    What about simplifying things a bit ?

                    const QRegularExpression rx ("(?:[XY](-?\\d+(?:\\.\\d+)?))");
                    
                    while (!in.atEnd()) {
                        QString line = in.readLine();
                        QRegularExpressionMatchIterator iter = re.globalMatch(line);
                        bool ok;
                        while (iter.hasNext()) {
                            QRegularExpressionMatch match = iter.next();
                            double x_or_y = match.captured(1).toDouble(&ok);
                            if (!ok) {
                                   qDebug() << "Failed to convert" << match.captured(1);
                                   continue;
                            }
                            if (match.captured(0).startsWith(QLatin1Char('X')) {
                                  minX = qmin(minX, x_or_y);
                                  maxX = qmax(maxX, x_or_y);
                            } else {
                                  minY = qmin(minY, x_or_Y);
                                  maxY = qmax(maxY, x_or_y);
                            }
                    }
                    

                    [edit: fixed rx, escaping was missing SGaist]

                    Interested in AI ? www.idiap.ch
                    Please read the Qt Code of Conduct - https://forum.qt.io/topic/113070/qt-code-of-conduct

                    1 Reply Last reply
                    5
                    • VRoninV Offline
                      VRoninV Offline
                      VRonin
                      wrote on last edited by VRonin
                      #13

                      I'd use:

                      const QRegularExpression regx("(?:([XY])([-+]?\\d*\\.?\\d+))");
                      QTextStream in(&file);
                      while(!in.atEnd()) {
                          QString line = in.readLine();
                          QRegularExpressionMatchIterator iter = re.globalMatch(line);
                          while (iter.hasNext()){
                              const QRegularExpressionMatch reMatch = iter.next();
                              if(reMatch.captured(1).compare(QLatin1String("X"),Qt::CaseInsensitive)==0){ // matched X
                                  const double lx = reMatch.captured(2).toDouble();
                                  qDebug()<<"X : " << lx;
                                  if(lx<minX)
                                      minX=lx;
                                  else if (lx>maxX)
                                      maxX=lx;
                              }
                              else {// matched Y
                                  const double ly = reMatch.captured(2).toDouble();
                                  qDebug() << " ly" << ly;
                                  if(ly<minY)
                                      minY=ly;
                                  else if (ly>maxY)
                                      maxY=ly;
                              }
                          }
                      }
                      
                      1 Reply Last reply
                      4

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