How to use QString.arg

[Weichao Wang]

Actually there are several static number() functions. But none of them contains fieldwidth and fillchar.

[JonB]

@Weichao-Wang
I believe you are trying to use this overload:
http://doc.qt.io/qt-5/qstring.html#arg-4
QString QString::arg(int a, int fieldWidth = 0, int base = 10, QChar fillChar = QLatin1Char(' ')) const

So I make your parameters wrong. I think you're passing '0' as the base (so base 48!) and therefore ' ' as the fillChar, so I would guess you're actually seeing <space>8 as the output?

Try:

QString("%1").arg(runningDate.date().month(), 2, 10, '0').toStdString() 

?

[Weichao Wang]

Now the output is 8.000000000... (some 30 '0').

[Weichao Wang]

In the documentation we can find
QString QString::arg ( const QString & a, int fieldWidth = 0, const QChar & fillChar = QLatin1Char( ' ' ) ) const
It contains only 3 parameters.
I'm using Qt 4.6.

[J.Hilk]

@Weichao-Wang why reinventing the wheel?

cout << runningDate.toString("MM").toStdString() << endl;

[Weichao Wang]

Now I've changed the line into following and the output is 08:
cout << QString("%1").arg(QString::number(runningDate.date().month()), 2, '0').toStdString() << endl;
I miss something like:
static QString QString::number(int a, int fieldWidth = 0, int base = 10, QChar fillChar = QLatin1Char(' '))
which would convert an interger into a string with desired length and fillchar without creating a QString object.

[JonB]

@Weichao-Wang said in How to use QString.arg:

In the documentation we can find
QString QString::arg ( const QString & a, int fieldWidth = 0, const QChar & fillChar = QLatin1Char( ' ' ) ) const
It contains only 3 parameters.
I'm using Qt 4.6.

Your code reads:

QString("%1").arg(runningDate.date().month(), 2, '0')

QDate::date().month() returns an int not a QString. So how do you figure it is calling your overload with const QString & a?

[Weichao Wang]

@J.Hilk
this is ingenious! Thank you!
Actually I need "20180803" for 3.Aug.2018. With date.toString("yyyyMMdd") I've solved the problem with one stroke.
But for a normal integer i can we only use the following or is there a simpler conversion?
QString("%1").arg(QString::number(i), 2, '0' )

[Weichao Wang]

@JonB said in How to use QString.arg:

@Weichao-Wang said in How to use QString.arg:

In the documentation we can find
QString QString::arg ( const QString & a, int fieldWidth = 0, const QChar & fillChar = QLatin1Char( ' ' ) ) const
It contains only 3 parameters.
I'm using Qt 4.6.

Your code reads:

QString("%1").arg(runningDate.date().month(), 2, '0')

QDate::date().month() returns an int not a QString. So how do you figure it is calling your overload with const QString & a?

Yes, I've noticed the problem and changed it to
QString("%1").arg(QString::number(i), 2, '0')

[J.Hilk]

@Weichao-Wang like @JonB said all overloads of arg that accept an int want a base to convert it to string

QString("%1").arg(QString::number(i), 2, '0' );
==
QString("%1").arg(i, 2, 10, QChar('0') );