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How do I properly serialize and deserialize a QList class in QT using QDatastream?

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  • J.HilkJ J.Hilk

    @JonB said in How do I properly serialize and deserialize a QList class in QT using QDatastream?:

    I may be confusing myself. In my C# we don't have "pointers" and we just de/serialize lists directly without a care.

    I beg to differ!

    you can use pointers in c# and manage your memory by hand, but you have to explicitly tell the compiler to allow it with -unsafe, IIRC

    Quick google search:
    https://www.tutorialspoint.com/csharp/csharp_unsafe_codes.htm

    JonBJ Online
    JonBJ Online
    JonB
    wrote on last edited by
    #20

    @J.Hilk
    But I would never want to use pointers in C# or manage memory by hand, that's (more than) half the point of using C#!?

    Maybe there's a misunderstanding. I don't use C# with Qt (I use Python). I'm just familiar with C# compared to C++. I am trying to understand @VRonin's explanation of de/serializing this QList<T>, where he is saying he does it explicitly to manage pointers, when I know I would just de/serialize a list from C# without iterating the elements myself, and trying to understand why.

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    • VRoninV VRonin
      out << qint32(layers.size());
      for(Layer* layer : qAsConst(layers))
      out << qint32(layer->type()) << *layer;
      

      qint32 size;
      qint32 type;
      in >> size;
      while(size-- >0 ){
      in >> type;
      Layer* layer = nullptr;
      switch(type){
      case Raster:
      layer = new RasterLayer;
      break;
      default:
      Q_UNREACHABLE();
      }
      in >> *layer;
      }
      T Offline
      T Offline
      twodee
      wrote on last edited by
      #21

      @VRonin Hi, thanks for the extended example. I have come up with a working solutin that looks similar to yours, could you let me know if this is a good way to deal with it?

      QDataStream& operator >>(QDataStream& stream, QList<Layer*>& layers){
          layers.clear();
          int size;
          int type;
      
          stream>>size;
      
          QString name;
          QPixmap pixmap;
      
          Layer* layer = nullptr;
          for(int i =0; i<size; ++i){
      
              stream >> name >> type;
              switch (type) {
              case Layer::RASTER:
                  stream >> pixmap;
                  layer = new RasterLayer(name, pixmap.toImage());
                  break;
              default:
                  Q_UNREACHABLE();
                  break;
              }
              layer->read(stream);
      
              layers.push_back(layer);
          }
          return stream;
      }
      
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      • VRoninV Offline
        VRoninV Offline
        VRonin
        wrote on last edited by
        #22

        The very first line of your code is a memory leak. This is exactly my point. Don't handle memory inside serialising/deserialising it's not the right place

        "La mort n'est rien, mais vivre vaincu et sans gloire, c'est mourir tous les jours"
        ~Napoleon Bonaparte

        On a crusade to banish setIndexWidget() from the holy land of Qt

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        • T Offline
          T Offline
          twodee
          wrote on last edited by
          #23

          I felt wrong in doing so too as I mentioned in my original question, but I still am not sure where would I be creating the new RasterLayer in my case. Could you give me some clues on how to go about it?

          kshegunovK 1 Reply Last reply
          0
          • VRoninV Offline
            VRoninV Offline
            VRonin
            wrote on last edited by
            #24

            Memory owned by an object should be created and freed by a method of said object:

            You can create a wrapper class around QList<Layer*> that will take care of allocating/freeing the memory inside and create safe datastream operator for this wrapper

            "La mort n'est rien, mais vivre vaincu et sans gloire, c'est mourir tous les jours"
            ~Napoleon Bonaparte

            On a crusade to banish setIndexWidget() from the holy land of Qt

            T 1 Reply Last reply
            2
            • T twodee

              I felt wrong in doing so too as I mentioned in my original question, but I still am not sure where would I be creating the new RasterLayer in my case. Could you give me some clues on how to go about it?

              kshegunovK Offline
              kshegunovK Offline
              kshegunov
              Moderators
              wrote on last edited by kshegunov
              #25

              @twodee said in How do I properly serialize and deserialize a QList class in QT using QDatastream?:

              I felt wrong in doing so too as I mentioned in my original question, but I still am not sure where would I be creating the new RasterLayer in my case. Could you give me some clues on how to go about it?

              Firstly, use the factory as you're using polymorphism, that'd be the way to go here. And secondly delegate the deserialization to the object through a virtual function; the whole reading. It's a good idea, since you're dealing with polymorphic objects, to also employ some kind of stack-based memory management here, to make sure you don't leak memory.
              You can see how I did it here and draw some inspiration:
              https://github.com/VSRonin/ChatExample/blob/commonlib/QtSimpleChat/chatmessage.h
              https://github.com/VSRonin/ChatExample/blob/commonlib/QtSimpleChat/chatmessage.cpp

              I am trying to understand @VRonin's explanation of de/serializing this QList<T>, where he is saying he does it explicitly to manage pointers, when I know I would just de/serialize a list from C# without iterating the elements myself, and trying to understand why.

              'Cause when you have allocations and deallocations in different parts of the code, i.e. not declaring the objects' lifetimes clearly you're begging for trouble. C++ is lower level (thank god) than C#, so it's up to the proficiency of the programmer to actually choose the best and most versatile implementation. It may seem elitist, but we don't want the language to be something to be worked around whenever there's something falling outside of the standard set of problems to solve. In Java/C# you start by assuming the programmer is irresponsible and can't handle the problem of finding a good way to manage the memory. This may prevent a lot of errors, but also hits hard on the efficiency ...

              Read and abide by the Qt Code of Conduct

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              • VRoninV VRonin

                Memory owned by an object should be created and freed by a method of said object:

                You can create a wrapper class around QList<Layer*> that will take care of allocating/freeing the memory inside and create safe datastream operator for this wrapper

                T Offline
                T Offline
                twodee
                wrote on last edited by twodee
                #26

                @VRonin So, if I create a function for the wrapper around QList<Layer*> class (let's call it LayerList) that creates the correct layers depending upon the type (essentially acting as a factory), then I can go to the >> stream and instead of doing a new RasterLayer() I will call the LayerList::createLayer() method, in which case the memory is created and freed by the object owning the layers. Is my idea correct?

                kshegunovK 1 Reply Last reply
                0
                • T twodee

                  @VRonin So, if I create a function for the wrapper around QList<Layer*> class (let's call it LayerList) that creates the correct layers depending upon the type (essentially acting as a factory), then I can go to the >> stream and instead of doing a new RasterLayer() I will call the LayerList::createLayer() method, in which case the memory is created and freed by the object owning the layers. Is my idea correct?

                  kshegunovK Offline
                  kshegunovK Offline
                  kshegunov
                  Moderators
                  wrote on last edited by kshegunov
                  #27

                  You have a two-layered problem here.

                  1. How to manage the memory
                  2. How to do (de)serialization

                  Start backwards, ensure you read and write the object correctly. You can do "virtual shift" operators as a syntactic sugar as well by delegating:

                  virtual bool Layer::serialize(QDataStream &) const;
                  virtual bool Layer::deserialize(QDataStream &);
                  
                  // Then just delegate from the base class (need to be `friend`s to the base class):
                  QDataStream & operator >> (QDataStream & stream, Layer & layer)
                  {
                      layer.deserialize(stream);
                      return stream;
                  }
                  
                  QDataStream & operator << (QDataStream & stream, const Layer & layer)
                  {
                      layer.serialize(stream);
                      return stream;
                  }
                  

                  This should more or less take care of task 2. Don't forget to use the virtuals up the hirearchy - i.e. each derived class would call the base class' (de)serialize to get the data of the base read/written. This way you don't have code duplication and you keep the idea that each class is responsible for its own data.

                  As for 1), you should ideally go with some kind of clever pointer. In the example above I used QSharedData and QSharedDataPointer, but you can also use QSharedPointer (which provides external reference counting). In principle I'd always opt for the first option, as the refcount is internal to the object a reference is held to. Using QSharedDataPointer would mean also that the base class has to derive from QSharedData, just as the example I sourced above. Whenever you have that it's a breeze, as you don't have to worry when the deallocation is happening and you are left only with one thing to do - read an integer and pass it to the static function of your Layer class that'd create the correct object based on that integer and return a base pointer to it. After all that the stream operator would look really simple:

                  class LayerPointer; //< This is your stack-based memory management class
                  
                  QDataStream & operator >> (QDataStream & stream, QList<LayerPointer> & layers)
                  {
                      layers.clear();
                  
                      int size;
                      stream >> size;
                      layers.reserve(size);
                  
                      for(int i = 0; i < size; i++)  {
                          stream >> type;
                          LayerPointer layer = Layer::create(type); //< Factory creation
                          stream >> *layer; //< The "virtual stream operator", will call the proper implementation
                  
                          layers.append(layer);
                      }
                  
                      return stream;
                  }
                  

                  Read and abide by the Qt Code of Conduct

                  T 1 Reply Last reply
                  3
                  • kshegunovK kshegunov

                    You have a two-layered problem here.

                    1. How to manage the memory
                    2. How to do (de)serialization

                    Start backwards, ensure you read and write the object correctly. You can do "virtual shift" operators as a syntactic sugar as well by delegating:

                    virtual bool Layer::serialize(QDataStream &) const;
                    virtual bool Layer::deserialize(QDataStream &);
                    
                    // Then just delegate from the base class (need to be `friend`s to the base class):
                    QDataStream & operator >> (QDataStream & stream, Layer & layer)
                    {
                        layer.deserialize(stream);
                        return stream;
                    }
                    
                    QDataStream & operator << (QDataStream & stream, const Layer & layer)
                    {
                        layer.serialize(stream);
                        return stream;
                    }
                    

                    This should more or less take care of task 2. Don't forget to use the virtuals up the hirearchy - i.e. each derived class would call the base class' (de)serialize to get the data of the base read/written. This way you don't have code duplication and you keep the idea that each class is responsible for its own data.

                    As for 1), you should ideally go with some kind of clever pointer. In the example above I used QSharedData and QSharedDataPointer, but you can also use QSharedPointer (which provides external reference counting). In principle I'd always opt for the first option, as the refcount is internal to the object a reference is held to. Using QSharedDataPointer would mean also that the base class has to derive from QSharedData, just as the example I sourced above. Whenever you have that it's a breeze, as you don't have to worry when the deallocation is happening and you are left only with one thing to do - read an integer and pass it to the static function of your Layer class that'd create the correct object based on that integer and return a base pointer to it. After all that the stream operator would look really simple:

                    class LayerPointer; //< This is your stack-based memory management class
                    
                    QDataStream & operator >> (QDataStream & stream, QList<LayerPointer> & layers)
                    {
                        layers.clear();
                    
                        int size;
                        stream >> size;
                        layers.reserve(size);
                    
                        for(int i = 0; i < size; i++)  {
                            stream >> type;
                            LayerPointer layer = Layer::create(type); //< Factory creation
                            stream >> *layer; //< The "virtual stream operator", will call the proper implementation
                    
                            layers.append(layer);
                        }
                    
                        return stream;
                    }
                    
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                    T Offline
                    twodee
                    wrote on last edited by twodee
                    #28

                    @kshegunov So for 1) to work, all I have to do is a create a LayerPointer class that extends QSharedData or is there something else I would have to add? I have never dealt with this type of situation before. Also, I have already solved 2) the way you suggested, so I am currently focusing on 1).

                    kshegunovK 1 Reply Last reply
                    0
                    • T twodee

                      @kshegunov So for 1) to work, all I have to do is a create a LayerPointer class that extends QSharedData or is there something else I would have to add? I have never dealt with this type of situation before. Also, I have already solved 2) the way you suggested, so I am currently focusing on 1).

                      kshegunovK Offline
                      kshegunovK Offline
                      kshegunov
                      Moderators
                      wrote on last edited by
                      #29

                      See the chat example above, it's exactly what you have to do. There the ChatMessage is the base class that derives from the QSharedData and there's one typedef for the pointer: typedef QSharedDataPointer<ChatMessage> ChatMessagePointer;. Also you should read this, to have an idea what's happening behind the scenes. That's pretty much it.
                      Then serialization and deserialization is done in fromJson and toJson (the messages come from JSON objects), you can easily adapt that to a data stream.

                      Read and abide by the Qt Code of Conduct

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