[SOLVED] using toUInt on a QBytearray with a Sha3-Hashsum fails

delok

I am having a little problem right now which has left me puzzled for the past days.
Unfortunately I didn't find any solutions in the forum for it:

@QByteArray t_barr = (QCryptographicHash::hash(file.readAll(), QCryptographicHash::Sha3_512));

    qDebug() << "the size of the raw bytearray is: " << t_barr.size();

    quint64 result = t_barr.toUInt(&ok, 0);

    file.close();

    qDebug() << "Hash is "  << result << ok;

    return result;

@

This is the paste from the code-section that gives me trouble (all variables are defined. i left the debugging stuff in it).
What I want is to cast the QBytearray with the Hash to a Uint or any other number-datatype.

It does not work however.
The Hash functions succeeds, the file can be opened in rw-mode, I can cast the Bytearray toHex without problem.
The .size() tells me that the resulting Hash is 64 bytes long, shouldn't be a problem to store it.
I tried using different datatypes for the cast, but every time the result is 0 and the
@ bool ok

@

is set to false.

I tried:

using a different hash algorithm
converting the result to base64 first
using int, quint, quint64, qulonglong, long, ...
specifying the base in .toUint(), tried 10, 0, and 16

What could be the problem?

SGaist

Hi and welcome to devnet,

A hash sum is not a mathematical sum, you don't end up with a number

delok

Hi,
thanks you for your quick response.

That explains a lot.

I guess I will be returning the QBytearray raw then, instead of converting it.

I would say that this solves my problem.

SGaist

You're welcome !

There's really no conversion needed, it's the data you need for other processing like comparing two files that should be the same.

Happy coding !