[Solved]Convert ASCII hex to int

[aha_1980]

@Leopold said in [Solved]Convert ASCII hex to int:

Hello,
the error is a hint to line 531 in qlist.h
"{ Q_ASSERT_X(i >= 0 && i < p.size(), "QList<T>::at", "index out of range");"

So take care to check fields.size() before calling fields.at(1). This should solve your problem.

[Leopold]

Hello,
my problem seems to be the line.split
QStringList fields = line.split(' ');
this is a file with ' ' separation
like "80: 1C 02 FC 85 FF 1D"

[jsulm]

@Leopold Can you do

qDebug() << line;
qDebug() << fields;

and post the output here?

[Leopold]

In the meanwhile i have found how to split white space but it does not work.This is my split command:
QStringList fields = line.split("\s+");
this is qDebug()<<fields :("80: 1C 02 FC 85 FF 4F FF 1D 89 17 08 10 01 00 00 00 3B 87 69 00 82 00 48 09 88 10 00 00 ")
what other split commands for white space are possible?

[VRonin]

const QRegularExpression hexRegExp(QStringLiteral("[0-9a-fA-F]{2}(?!:)"));  // regular expression that matches 2 hex digits NOT followed by :
for(QRegularExpressionMatchIterator i = hexRegExp.globalMatch(line);i.hasNext();){ // iterate over all the matches
const QRegularExpressionMatch hexMatch = i.next();
qDebug() << "Hex: " << hexMatch.capturedRef(0) << " Dec: " << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); //capturedRef contains the part matched by the regular expression
}

[mpergand]

Using a QByteArray is the way to go !

QString hex="80 1c,02:fc 85, ff* 1000";  // the separator can be any non hex char
QByteArray values=QByteArray::fromHex(hex.toLatin1());
qDebug()<<values;
for(quint8 c : values)  // note the quint8
  qDebug()<<c;

[Leopold]

@ VRonin
sorry , could you explain line by line, i normaly can read c-code but this is too complex and I would like to understand.On the other hand, when I put this code into mine I get a lot of errors.Here is part of my code. I have to examine first field and according to its value read the lines into different vectors.
i need an expression that the line will be split,every ( to me) known didn't work up to know.
my code:

if (line_count>3) // read line from line 4
							{
                                QStringList fields = line.split("[\s]+");// not working
                                  qDebug()<<fields;// shows complete line, should be first field
                                 Eingang.append(fields.at(0));// its a QString declared earlier
                                 qDebug()<<Eingang;             
                                 if( Eingang==("80:"))// then read this line
								{
								 bool bStatus = false;
                                 qDebug() << line;
                                 x.append(tick); // this will be x-line in a plot
                                 tick++;
                            
                                 y1.append(fields.at(1).toUInt(&bStatus,16));// one graph inplot
                                 y2.append(fields.at(2).toUInt(&bStatus,16));// second graph in plot
              
								}
                                else if ( Eingang== ("7D:"))
								{
                                    bool bStatus = false;
                                    qDebug() << line;
                                    QStringList fields = line.split("\\s+");// didn't work too
                                    x.append(tick);
                                    tick++;
                                 y29.append(fields.at(1).toUInt(&bStatus,16));
                                 y30.append(fields.at(2).toUInt(&bStatus,16));
                     
								}
							}
						}		 

and here part of the file:

Running command: read-raw
ECU responded to D0 command with: 98 00 01 02

80: 1C 02 FC 85 FF 4F FF 1D 89 17 08 10 01 00 00 00 3B 87 69 00 82 00 48 09 88 10 00 00 
7D: 20 10 1C FF 92 00 A8 FF FF 01 01 7D 59 00 FF 51 FF FF 30 80 7F 7F FF 01 00 07 00 0D C0 1E 00 45 
80: 1C 03 0C 85 FF 4F FF 1E 89 17 08 10 01 00 00 00 3B 87 69 00 82 00 48 09 88 10 00 00 
7D: 20 10 1C FF 92 00 9D FF FF 01 01 7D 59 00 FF 51 FF FF 30 80 7F 6D FF 01 00 07 00 0D C0 1E 00 45 
80: 1C 02 F8 85 FF 4F FF 1E 89 17 08 10 01 00 00 00 3B 87 69 00 8C 00 48 09 88 10 00 00 
7D: 20 10 1C FF 92 00 43 FF FF 01 01 7D 58 00 FF 51 FF FF 30 80 7F 79 FF 01 00 07 00 0D C0

[VRonin]

could you explain line by line

Added comments, for more info just look here: http://doc.qt.io/qt-5/qregularexpression.html#global-matching

On the other hand, when I put this code into mine I get a lot of errors

what errors? if it's because you don't support C++11 for some reason I changed the code so it works on old compilers

if( Eingang==("80:"))

add a regular expression for that too:

const QRegularExpression eingangExp(QStringLiteral("^\\s*([0-9a-fA-F]{2}):"));
const QRegularExpression hexRegExp(QStringLiteral("[0-9a-fA-F]{2}(?!:)"));
const QRegularExpressionMatch eingangMatch = eingangExp.match(line);
if(eingangMatch.hasMatch()){
if(eingangMatch.capturedRef(1).compare("80",Qt::CaseInsensitive)==0){ // Eingang==("80:")
qDebug() << "Eingang is 80";
for(QRegularExpressionMatchIterator i = hexRegExp.globalMatch(line);i.hasNext();){ // iterate over all the matches
const QRegularExpressionMatch hexMatch = i.next();
qDebug() << "Hex: " << hexMatch.capturedRef(0) << " Dec: " << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); //capturedRef contains the part matched by the regular expression
}
}
else if(eingangMatch.capturedRef(1).compare("7D",Qt::CaseInsensitive)==0){ // Eingang==("7D:"){
qDebug() << "Eingang is 7D";
for(QRegularExpressionMatchIterator i = hexRegExp.globalMatch(line);i.hasNext();){ // iterate over all the matches
const QRegularExpressionMatch hexMatch = i.next();
qDebug() << "Hex: " << hexMatch.capturedRef(0) << " Dec: " << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); //capturedRef contains the part matched by the regular expression
}
}
}

QStringList fields = line.split("[\s]+");// not working

You have to tell split you are using a regexp and escape the \: QStringList fields = line.split(QRegularExpression("\\s+"));

[mpergand]

QString line="80: 1C 02 FC 85 FF 4F FF 1D 89 17 08 10 01 00 00 00 3B 87 69 00 82 00 48 09 88 10 00 00 ";
QStringList fields=line.split(':');
qDebug()<<"en-tête:"<<fields[0];
QByteArray values=QByteArray::fromHex(fields[1].toLatin1());
qDebug()<<"data:"<<values;

en-tête: "80"
data :"\x1C\x02\xFC\x85\xFFO\xFF\x1D\x89\x17\b\x10\x01\x00\x00\x00;\x87i\x00\x82\x00H\t\x88\x10\x00\x00"

[Leopold]

heureka
VRonin's code works:
QVector()
"80: 1C 02 FC 85 FF 4F FF 1D 89 17 08 10 01 00 00 00 3B 87 69 00 82 00 48 09 88 10 00 00 "
4
QRegularExpressionMatch(Valid, has match: 0:(0, 3, "80:"), 1:(0, 2, "80"))
"1C" 28
"02" 2
"FC" 252
now I have to give eyh value to the different y
but I think I can gigure that out.

@mpergand
this will divide first field from rest but how to divide the rest?
y1= field1,y2=field2 and so on
but I will test.

[mpergand]

@Leopold said in [Solved]Convert ASCII hex to int:

this will divide first field from rest but how to divide the rest?
y1= field1,y2=field2 and so on
but I will test.

No need to split anything, you can access each byte in a QByteArray with at() or []
See the doc ...

[Leopold]

@VRonin
the example works great for transforming from hex to dec but i get the same row what i have in the txt now as a vektor. In my code you see that I have different y Vektors.
I need value of field1 in y1, field2 in y2 and so on.I can not figure out how to take the i into a loop with y(i).

[VRonin]

@Leopold Every time you call i.next(); it moves to the next field in order so it's quite easy to manage

[Leopold]

I tried this:
{ // iterate over all the matches

										const QRegularExpressionMatch hexMatch = i.next();
										qDebug() <<  hexMatch.capturedRef(0) <<  hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); //capturedRef contains the part matched by the regular expression
                                        y1.append(hexMatch.capturedRef(1).toUInt(Q_NULLPTR,16));
                                         y2.append(hexMatch.capturedRef(2).toUInt(Q_NULLPTR,16));
                                          y3.append(hexMatch.capturedRef(3).toUInt(Q_NULLPTR,16));
                                           y4.append(hexMatch.capturedRef(4).toUInt(Q_NULLPTR,16));
                                    }

[VRonin]

@Leopold said in [Solved]Convert ASCII hex to int:

{ // iterate over all the matches

Look at that comment. Do you see what you are doing wrong?

[Leopold]

yes I see that it is a loop but if i write :

 if(eingangMatch.hasMatch())
								{
									if(eingangMatch.capturedRef(1).compare("80",Qt::CaseInsensitive)==0)
									{ // Eingang==("80:")
										qDebug() << eingangMatch;
										for(QRegularExpressionMatchIterator i = hexRegExp.globalMatch(line);

                                            i.hasNext();


                                            )


											const QRegularExpressionMatch hexMatch = i.next();
                                            qDebug() << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); //capturedRef contains the part matched by the regular expression
                                            y1.append(hexMatch.capturedRef(1).toUInt(Q_NULLPTR,16));
                                             y2.append(hexMatch.capturedRef(2).toUInt(Q_NULLPTR,16));
                                              y3.append(hexMatch.capturedRef(3).toUInt(Q_NULLPTR,16));
                                               y4.append(hexMatch.capturedRef(4).toUInt(Q_NULLPTR,16));



                                }

the qDebug() << eingangMatch; and qDebug() << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16);
don't work and all my y vectors get "0"
"80: 1C 05 3A 85 FF 4F FF 1D 89 1E 08 10 01 00 00 00 3B 87 51 01 AF 00 58 09 88 10 00 00 "
QVector(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)
QVector(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)

[VRonin]

@Leopold said in [Solved]Convert ASCII hex to int:

yes I see that it is a loop

I don't think you do...

int h=0;
for(QRegularExpressionMatchIterator i = hexRegExp.globalMatch(line);i.hasNext();++h){
const QRegularExpressionMatch hexMatch = i.next();
qDebug() << hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16); 
switch(h){
case 1 : y1.append(hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16)); break;
case 2 : y2.append(hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16)); break;
case 3 : y3.append(hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16)); break;
case 4 : y4.append(hexMatch.capturedRef(0).toUInt(Q_NULLPTR,16)); break;
default: break;
}
}

[Leopold]

i get error for the "i" no match for operator "++"
and the switch operator is not an integer
I copied the int i=0 as well
btw:my compiler is mingw9-32 from QT 5.6.2

[Leopold]

the i was occupied by the "QRegularExpressionMatchIterator"
i changed int i to int h then ++h and switch h and it works.
Thank you great!