As dynamic libraries to use class variables?

Mikee

Now all includes are working.
When I use function

void StrategyCod(MainWindow * main)
{
    //MainWindow w;
    main->NBar;
    qDebug()<<"Library work2"<<main->NBar;//<<w.NBar;
}

qDebug message is not a valid value NBar

Mikee

I think that need to do reference class variable. But this code isn't working

void StrategyCod(/*MainWindow * main*/)
{
    long long &NBar1 =MainWindow.NBar;
    qDebug()<<"Library work2";//<<w.NBar;
}

How can i do reference?

mrjj

@Mikee

via the parameter ( main or what u called it)

void StrategyCod(MainWindow * main) {
    qDebug()<<"Library work2"<<main->NBar;
}

if NBAr is wrong, then something else is wrong. not the function
it might be you call StrategyCod BEFORE setting it in mainwindow or
something like that.

Mikee

I checked:
library:
void StrategyCod(double Parametr)

{
    MainWindow *w;
    qDebug()<<"Library work2"<<Parametr<<w->NBar;
}

main.cpp:

QLibrary MyLib("C:\\Qt\\project\\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\\debug\\StrategyCod");  
    MyLib.load();
    typedef void (*MyPrototype)();
    MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
    qDebug()<<w.NBar;  //NBar=0 is hear 
    StrategyCod();  //NBar=5943858560 is hear 
    MyLib.unload();

Maybe here typedef void (*MyPrototype)(); need append void (*MyPrototype)(class); ?

mrjj

@Mikee
Yes it must all match.

typedef void (*MyPrototype)();

means pointer to function takes no parameters
which is untrue.

Mikee

But what to do with NBar?

void StrategyCod()
{
    MainWindow *w;
    qDebug()<<"Library work2"<<w->NBar;
  
}

jsulm

@Mikee

typedef void (*MyPrototype)(MainWindow *w);

Mikee

I have done this and it's working

 QLibrary MyLib("C:\\Qt\\project\\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\\debug\\StrategyCod");  
    MyLib.load();
    typedef void (*MyPrototype)(MainWindow *);
    MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
    StrategyCod(&w);  
    qDebug()<<"q1"<< q1;
    MyLib.unload();

Thank you

mrjj

Congrats :)

Mikee

I have are new problem.

qDebug()<<NBar;

return NBar=1064,

qDebug()<<"Library work2"<< Parametr<<w->NBar;

return NBar=0
In class MainWindow:

void MainWindow::on_ButtonRuneOne_clicked()//запуск стратегии на одном ядре
{
    bool ok;
    double d = QInputDialog::getDouble(this, tr("ParametrForStrategy"),
                                           tr("double:"), 37.56, -100000, 100000, 6, &ok);
    if (ok) {ParametrForStrategyCod=d; }

    QLibrary MyLib("C:\\Qt\\project\\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\\debug\\StrategyCod");  
    MyLib.load();
    typedef void (*MyPrototype)(double,MainWindow *);
    MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
    MainWindow w;
    qDebug()<<NBar;
    StrategyCod(ParametrForStrategyCod,&w);  /
    MyLib.unload();
}

In library:

void StrategyCod(double Parametr, MainWindow *w)
{
    qDebug()<<"Library work2"<< Parametr<<w->NBar;
}

But in main.cpp it works good. How can I fix problem with link of object class?

SGaist

You're passing w to your method which is not the current MainWindow object you are calling StrategyCod from.

Pass this to the method.

On a side note, you are doing some pretty convoluted stuff here for what seems to be a pretty simple task. I'd encourage you to re-think a bit the design of your application.

Mikee

Thank you. I wrote it like this

StrategyCod(ParametrForStrategyCod,this);

and it works

Mikee

How can I create lamda function in the slot of the class?


       QVector <double> Perebor1;
       for (double i=d1;i<=d2;i=i+d3) 
       {
           Perebor1.append(i);
       }
       QLibrary MyLib("C:\\Qt\\project\\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\\debug\\StrategyCod");  
       MyLib.load();
       typedef void (*MyPrototype)(double,MainWindow *);
       MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
       //StrategyCod(ParametrForStrategyCod,this);  
       QFuture<void> Perebor2 = QtConcurrent::map(Perebor1,[&](const double& d){ StrategyCod(d,this);}); 
       MyLib.unload();

Mikee

And if I do, the function does not work.

void StrategyCod(double Parametr, MainWindow *w)
{
    qDebug()<<"Library work2"<< Parametr<<w->NBar;
    w->NBar=2000;
}

error:
Invalid parameter passed to C runtime function.
Invalid parameter passed to C runtime function.

mrjj

Well if Perebor2 still runs when you do MyLib.unload()
its not so nice for it...

Mikee

How to wait for all Perebor2?
How to change w->NBar throw StrategyCod? If I do it in one thred

void StrategyCod(double Parametr, MainWindow *w)
{
    qDebug()<<"Library work2"<< Parametr<<w->NBar;
    w->NBar=2000;
}

it compiles, but when it works errors appears:
ASSERT failure in QVector<T>::operator[]: "index out of range", file ....\Qt5.9.2\5.9.2\mingw53_32\include/QtCore/qvector.h, line 430
Invalid parameter passed to C runtime function.
Invalid parameter passed to C runtime function.

mrjj

@Mikee
Dont wait for it.
Just move the MyLib.unload(); to a better place.

also if you have

void mainwindow::somefunction {
QVector <double> Perebor1;
for (double i=d1;i<=d2;i=i+d3)
{
Perebor1.append(i);
}
QLibrary MyLib("C:\Qt\project\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\debug\StrategyCod");
MyLib.load();
typedef void (*MyPrototype)(double,MainWindow *);
MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
//StrategyCod(ParametrForStrategyCod,this);
QFuture<void> Perebor2 = QtConcurrent::map(Perebor1,[&](const double& d){ StrategyCod(d,this);});
MyLib.unload();
} // Perebor1 is deleted here.

Perebor1 also dies as its a local
so make them member variables of the class
and structure code better.

Mikee

`Perebor in class ,MainWindow. It doesn't work. Errors are the same.
``
for (double i=d1;i<=d2;i=i+d3)
{
Perebor.append(i);
}

   QLibrary MyLib("C:\\Qt\\project\\build-StrategyCod-Desktop_Qt_5_9_2_MinGW_32bit-Debug\\debug\\StrategyCod");  
   MyLib.load();
   typedef void (*MyPrototype)(double,MainWindow *);
   MyPrototype StrategyCod = (MyPrototype) MyLib.resolve("StrategyCod");
   //StrategyCod(ParametrForStrategyCod,this);  
   //QFuture<void> Perebor2 = QtConcurrent::map(Perebor1,[&](const double& d){ StrategyCod(d,this);});  
   QFuture<void> Perebor2 = QtConcurrent::map(Perebor,[&](const double& d){ StrategyCod(d,this);});

mrjj

What about Perebor2 ?
Wont it suffer the same and run out of scope ?

Mikee

No. It's okey with Perebor2. Function StrategyCod2 is in class MainWindow works correctly.

for (double i=d1;i<=d2;i=i+d3) 
       {
           Perebor.append(i);
       }

       QFuture<void> Perebor2 = QtConcurrent::map(Perebor,[this](const double& d){ StrategyCod2(d);});