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Data Format issue

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  • S Stoyan

    @vidisha
    You don't need to convert numbers to strings and vice versa.
    Use shift function and work only with numbers:

    int Data = (3 << 4) | (i1 >> 2);
    

    3 is decimal value for 0011. Result from (3 << 4) is 00110000 binary or 48 decimal.
    If i1 = 45 = 101101, then (i1 >> 2) will give you 1011 = 11.
    Final result is 00111011 = 59.
    Then you can convert it to QString and choose format.
    For example:

    QString res = QString("W %1 1A"").arg(Data, 0, 16).toUpper();
    
    V Offline
    V Offline
    vidisha
    wrote on last edited by
    #3

    @Stoyan
    Thankyou so much...
    This is what i needed..
    Really tq so much..

    1 Reply Last reply
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    • S Stoyan

      @vidisha
      You don't need to convert numbers to strings and vice versa.
      Use shift function and work only with numbers:

      int Data = (3 << 4) | (i1 >> 2);
      

      3 is decimal value for 0011. Result from (3 << 4) is 00110000 binary or 48 decimal.
      If i1 = 45 = 101101, then (i1 >> 2) will give you 1011 = 11.
      Final result is 00111011 = 59.
      Then you can convert it to QString and choose format.
      For example:

      QString res = QString("W %1 1A"").arg(Data, 0, 16).toUpper();
      
      V Offline
      V Offline
      vidisha
      wrote on last edited by
      #4

      @Stoyan
      One more thing is i have to write 2nd Byte which is 2 LSB's of i1 & value from ( 31.5 to 0).

      Im poor in Bit masking,
      How to get only 2 LSB's of i1 i.e 45(101101)

      S 1 Reply Last reply
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      • V vidisha

        @Stoyan
        One more thing is i have to write 2nd Byte which is 2 LSB's of i1 & value from ( 31.5 to 0).

        Im poor in Bit masking,
        How to get only 2 LSB's of i1 i.e 45(101101)

        S Offline
        S Offline
        Stoyan
        wrote on last edited by
        #5

        @vidisha

        int Data2 = i1 & 3;
        
        V 1 Reply Last reply
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        • S Stoyan

          @vidisha

          int Data2 = i1 & 3;
          
          V Offline
          V Offline
          vidisha
          wrote on last edited by
          #6

          @Stoyan
          Ya got it,but i have to OR it with value chosen from ( 31.5 to 0)
          which has floating point numbers too..

          int i1 = ui->comboBox_PS1 ->currentText().toFloat();
          float AT1 = ui-> comboBox_AT1 ->currentText().toFloat();
          int Byt2 = (i1 & 3 );
          int BYT3 = Byt2 << 6;
          int BYT4 = (BYT3 | (AT1));

          it gives me error
          error: C2297: '|' : illegal, right operand has type 'float'

          so what's the correct way to convert floating numbers to add with decimal number

          S 1 Reply Last reply
          0
          • V vidisha

            @Stoyan
            Ya got it,but i have to OR it with value chosen from ( 31.5 to 0)
            which has floating point numbers too..

            int i1 = ui->comboBox_PS1 ->currentText().toFloat();
            float AT1 = ui-> comboBox_AT1 ->currentText().toFloat();
            int Byt2 = (i1 & 3 );
            int BYT3 = Byt2 << 6;
            int BYT4 = (BYT3 | (AT1));

            it gives me error
            error: C2297: '|' : illegal, right operand has type 'float'

            so what's the correct way to convert floating numbers to add with decimal number

            S Offline
            S Offline
            Stoyan
            wrote on last edited by
            #7

            @vidisha
            You can't use bit operations on float or double, because they have completely different inner representations. But if a float number have one digit after the point you can multiply it by 10 and then convert result to integer. With this number you can use bit operations, but result may be different of what you expect.
            I don't understand in this case what you want to achieve. Can you give me expected result for a sample input values?

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            • S Stoyan

              @vidisha
              You can't use bit operations on float or double, because they have completely different inner representations. But if a float number have one digit after the point you can multiply it by 10 and then convert result to integer. With this number you can use bit operations, but result may be different of what you expect.
              I don't understand in this case what you want to achieve. Can you give me expected result for a sample input values?

              V Offline
              V Offline
              vidisha
              wrote on last edited by
              #8

              @Stoyan
              Hi,
              I'm doing typecasting I.e converting to char and performing logical operations on it.
              This is solved for me.
              Tq so much.😊
              One more thing I want to know is
              I get 2 bytes incoming over serial port.
              So, I need to compare each bit with a reference bit.
              So how can I access each bit of a byte?

              S 1 Reply Last reply
              1
              • V vidisha

                @Stoyan
                Hi,
                I'm doing typecasting I.e converting to char and performing logical operations on it.
                This is solved for me.
                Tq so much.😊
                One more thing I want to know is
                I get 2 bytes incoming over serial port.
                So, I need to compare each bit with a reference bit.
                So how can I access each bit of a byte?

                S Offline
                S Offline
                Stoyan
                wrote on last edited by Stoyan
                #9

                @vidisha
                Comparison with one bit:

                int bit0 = 1;  // BIT 0 - 00000001
                int bit1 = 2;  // BIT 1 - 00000010
                ...
                int bit7 = 128;  // BIT 7 - 10000000
                ...
                if (num & bit0) 
                    return true;  // BIT 0 in num is 1
                else
                    return false;
                
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                • S Stoyan

                  @vidisha
                  Comparison with one bit:

                  int bit0 = 1;  // BIT 0 - 00000001
                  int bit1 = 2;  // BIT 1 - 00000010
                  ...
                  int bit7 = 128;  // BIT 7 - 10000000
                  ...
                  if (num & bit0) 
                      return true;  // BIT 0 in num is 1
                  else
                      return false;
                  
                  V Offline
                  V Offline
                  vidisha
                  wrote on last edited by
                  #10

                  @Stoyan
                  Hi ,
                  Actually i send 2 bytes(commands) & in response i get 2 bytes.
                  I want to check whether received each bit is set or not.
                  I dont know what each bit should be, but i want to see whether it is 1 or 0.
                  so for reference i defined -> unsigned short tocheck = 9203( 00100011 11110011)
                  & i compare each received bit with reference bits.

                  unsigned short tocheck = 9203;
                  for(int bitnum = 0; bitnum <= 16; bitnum++){
                  bool biton = (tocheck >> bitnum) & 1;
                  qDebug() << "bit" << bitnum << "->" << biton;

                      }
                  

                  Is it correct the way i'm doing?

                  S 1 Reply Last reply
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                  • V vidisha

                    @Stoyan
                    Hi ,
                    Actually i send 2 bytes(commands) & in response i get 2 bytes.
                    I want to check whether received each bit is set or not.
                    I dont know what each bit should be, but i want to see whether it is 1 or 0.
                    so for reference i defined -> unsigned short tocheck = 9203( 00100011 11110011)
                    & i compare each received bit with reference bits.

                    unsigned short tocheck = 9203;
                    for(int bitnum = 0; bitnum <= 16; bitnum++){
                    bool biton = (tocheck >> bitnum) & 1;
                    qDebug() << "bit" << bitnum << "->" << biton;

                        }
                    

                    Is it correct the way i'm doing?

                    S Offline
                    S Offline
                    Stoyan
                    wrote on last edited by
                    #11

                    @vidisha
                    It is correct. But if you want to use them afterward individually, may be it is better to store them in QBitArray. It depends on what you want to do with them.

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                    • S Stoyan

                      @vidisha
                      Comparison with one bit:

                      int bit0 = 1;  // BIT 0 - 00000001
                      int bit1 = 2;  // BIT 1 - 00000010
                      ...
                      int bit7 = 128;  // BIT 7 - 10000000
                      ...
                      if (num & bit0) 
                          return true;  // BIT 0 in num is 1
                      else
                          return false;
                      
                      V Offline
                      V Offline
                      vidisha
                      wrote on last edited by
                      #12

                      @Stoyan
                      Hi,
                      It;s quite not related to above post but i need to solve it urgently so,
                      I receive 10 Bytes over serial port in hex form,
                      4F C0 6F C0....AF C0
                      My incoming data is in m_readData.
                      QByteArray buf ;
                      buf += serial_1->readAll();
                      m_readData.append(buf);

                      I have to perform bitwise operations on the received data, so i need to convert it into int or binary form,
                      so , how can i convert incoming hex data to some other form??

                      Regards
                      Vidisha

                      jsulmJ 1 Reply Last reply
                      0
                      • V vidisha

                        @Stoyan
                        Hi,
                        It;s quite not related to above post but i need to solve it urgently so,
                        I receive 10 Bytes over serial port in hex form,
                        4F C0 6F C0....AF C0
                        My incoming data is in m_readData.
                        QByteArray buf ;
                        buf += serial_1->readAll();
                        m_readData.append(buf);

                        I have to perform bitwise operations on the received data, so i need to convert it into int or binary form,
                        so , how can i convert incoming hex data to some other form??

                        Regards
                        Vidisha

                        jsulmJ Offline
                        jsulmJ Offline
                        jsulm
                        Lifetime Qt Champion
                        wrote on last edited by
                        #13

                        @vidisha Well, you could read documentation: http://doc.qt.io/qt-5/qbytearray.html#fromHex

                        https://forum.qt.io/topic/113070/qt-code-of-conduct

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