[Re-ReOpened) Easy input mask

mrjj

hi
is that a date u want to have mask for ?

? Offline

Hi! QDateEdit is your friend ;-)

yczo

I need a custom mask, for example "0000 : 000 /234 1230 - 1234" to take different characters (numbers as characters too) and store all in a unique string.

Greetings

mrjj

@yczo

Hi you must define your input using the below symbols.
"9999:9999/999 999 - 9999" for "0000 : 000 /234 1230 - 1234"
But might need to use N also etc.
So first you should think about what your format really is. the rules
of it.

Character	Meaning
A	ASCII alphabetic character required. A-Z, a-z.
a	ASCII alphabetic character permitted but not required.
N	ASCII alphanumeric character required. A-Z, a-z, 0-9.
n	ASCII alphanumeric character permitted but not required.
X	Any character required.
x	Any character permitted but not required.
9	ASCII digit required. 0-9.
0	ASCII digit permitted but not required.
D	ASCII digit required. 1-9.
d	ASCII digit permitted but not required (1-9).
#	ASCII digit or plus/minus sign permitted but not required.
H	Hexadecimal character required. A-F, a-f, 0-9.
h	Hexadecimal character permitted but not required.
B	Binary character required. 0-1.
b	Binary character permitted but not required.
>	All following alphabetic characters are uppercased.
<	All following alphabetic characters are lowercased.
!	Switch off case conversion.
\	Use \ to escape the special characters listed above to use them as separators.

VRonin

you can use a QRegularExpressionValidator

ui->lineEdit->setValidator(
new QRegularExpressionValidator(
QRegularExpression(
// put here the regular expression that matches the valid input
)
,ui->lineEdit
)
);

? Offline

@yczo said:

for example "0000 : 000 /234 1230 - 1234"

... numbers and characters:

ui->lineEdit->setInputMask("NNNN : NNNN /NNN NNN - NNNN");

? Offline

...or as suggested by @VRonin :

const QString a4 = "[0-9A-Za-Z]{4}";
const QString a3 = "[0-9A-Za-Z]{3}";
const QString expression = QString("%1\\s\\:\\s%1\\s\\/%2\\s%2\\s\\-\\s%1").arg(a4).arg(a3); 
QRegExp rx(expression);
QValidator *validator = new QRegExpValidator(rx, this);
ui->lineEdit->setValidator(validator);

yczo

Wow, that was great, thank you very much for your help. Have you not thought about doing a book with small examples of c ++ with qt and sell it on amazon.

Thank you very much

VRonin

@Wieland QRegExp should be banished from new code. The only place I still use it over QRegularExpression is QSortFilterProxyModel::filterRegExp just because I don't have a choice. see http://doc.qt.io/qt-5/qregularexpression.html#notes-for-qregexp-users

@yczo you might be interested in: http://www.bogotobogo.com/cplusplus/files/c-gui-programming-with-qt-4-2ndedition.pdf

? Offline

@VRonin Oh yes, right. Old habits die hard :-)

yczo

hello un thank you, A question more...

But with this code some fails. I can only the first validator a4 write, a3 don't work. The expresion dont work, only a4. Why might it be?

/    const QString a4 = "[0-9A-Za-Z]{4}";
    const QString a3 = "[0-9A-Za-Z]{3}";
    const QString expression = QString("%1\\s\\:\\s%1\\s\\/%2\\s%2\\s\\-\\s%1").arg(a4).arg(a3);
    QRegExp rx(expression);
    QValidator *validator = new QRegExpValidator(rx, this);
    ui->lineEdit->setValidator(validator);
/your code here

Thanks in advance

? Offline

@yczo You also need to enter the spaces, the colon, the slash and the dash.

yczo

Upssss....thank you very much, as could not see the extra characters, like in ui->lineEdit->setInputMask("NNN:NNNN /NNN NNN - NNNN;X");

is there a way to merge both? Because

    ui->setupUi(this);
   // ui->lineEdit->inputMask ;

  //  ui->getLine->setMaxLength(sizeMSG);
  //  ui->lineEdit->setInputMask("nnn;A");
   // ui->lineEdit->setInputMask("nnn;");
  //  ui->lineEdit->adjustSize();

ui->lineEdit->setInputMask("NNN:NNN/NNN;X");
const QString a0 = "[0-9A-Za-Z]{3}";
const QString a1 = "[0-9A-Za-Z]{3}";
const QString a2 = "[0-9A-Za-Z]{3}";
const QString expression = QString("%1\\:\\%2\\/\\%3").arg(a0).arg(a1).arg(a2);
//ui->lineEdit->setCursorPosition(0);
 //   const QString a4 = "[0-9A-Za-Z]{4}";
 //   const QString a3 = "[0-9A-Za-Z]{3}";
 //   const QString expression = QString("%1\\s\\:\\s%1\\s\\/%2\\s%2\\s\\-\\s%1").arg(a4).arg(a3);

    QRegExp rx(expression);
    QValidator *validator = new QRegExpValidator(rx, this);
    ui->lineEdit->setValidator(validator);

    ui->lineEdit->setFixedWidth(600);
    ui->lineEdit->setCursorPosition(0);

don't works.

Greetings

? Offline

@yczo said:

is there a way to merge both?

Yes, just make the parts of the input optional, like this:

    ui->setupUi(this);
    ui->lineEdit->setInputMask("NNN : NNN");

    const QString a0 = "[ 0-9A-Za-z]{3}"; // space before 0
    const QString space = "\\s";
    const QString colon = "\\:";
    const QString expression = QString("%1%2%3%2%1").arg(a0).arg(space).arg(colon);
    QRegExp rx(expression);
    QValidator *validator = new QRegExpValidator(rx, this);
    ui->lineEdit->setValidator(validator);

yczo

thank you that was great.

yczo

The last question, ist posible set a max int value in the string (after other characters)?

for example A37 (37 is the max),We could write from A00, A01.., to A37

Greetings

? Offline

@yczo Yes, you can do this by adjusting the regular expression.

yczo

Please, can you show me how to make it? Because I tried several options but, I have not luck.

That is my idea

    ui->leStr->setInputMask("A99");

                                        //el conjunto para tanto espacios
    const QString id ="[ (A,M,O)]{1}";  //espacio delante para poder editar
    const QString cm ="[ 0-9]{2}";

    //const QString sl ="[0-50]{2}";
    const QString expr = QString("%1%2").arg(id).arg(cm);
    QRegExp cmp(expr);
    QValidator *vld = new QRegExpValidator(cmp,this);
    ui->leStr->setValidator(vld);
    ui->leStr->setCursorPosition(0);

yczo

That is another idea, but don't work too

ui->le1->setInputMask("99");
ui->le1->setValidator(new QDoubleValidator(01,10,1,this));
ui->le1->setCursorPosition(0);

or

ui->le1->setInputMask("99");
ui->le1->setValidator(new QIntValidator(1,10,this));
ui->le1->setCursorPosition(0);

i don't understand what I make wrong,

Greetings

Edit---
ok i discovered that,

ui->le1->setValidator(new QIntValidator(1,10,this));

work good for integers, but, only in a separate field. how to make all together, that is another story und not idea XDD

jsulm

For your example (max A37) it should be like this:

A[0-3][0-7]