Function with Signals & Slots

gabor53

I changed the following line:

       connect(Image_Button, &QPushButton::clicked, [this]() { imagePath =  findimage( QString);});

to

   connect(Image_Button, &QPushButton::clicked, [this]() { imagePath =  findimage( fileName);});

Now I get the following error message:
C:\Programming\backup\Folkfriends\additem.cpp:195: error: no match for 'operator=' (operand types are 'QString' and 'void')
        connect(Image_Button, &QPushButton::clicked, [this]() { imagePath =  findimage( fileName);});
                                                    
What else to change? Thank you.

mrjj

Hi
in the first post you show it as
findimage(bool)

so that would be callable as
imagePath = findimage( true);

So what you give it as parameter, depends on how u declare it.
(in the .h file)

gabor53

@mrjj
I changed it from findimage(bool) to findimage(fileName) because I need it to return the fileName.
In the .h file it is defined as void findimage(QString fileName);
I still have the same error message. Thank you.

mrjj

@gabor53 said:
hi
I would kinda expect it to be declared as
void findimage();
as you
return(fileName);
in the function and return filename that way.
so why you need a QString as parameter too ?

gabor53

@mrjj
I changed it as you recommended:
in the .h file: void findimage();

 connect(Image_Button, &QPushButton::clicked, [this]() { imagePath =  findimage();});

the function : void Additem::findimage();
It still gives the same exact error message. Thnks.

kshegunov

@gabor53
void means "nothing", so you're trying to save that "nothing" into a variable, how should that happen? The compiler doesn't know, I don't and I'm pretty sure no one does. If you want to assign a value returned from a function to a variable, well then, by all means, make the function return the proper type and value. Meaning, if you want the function to return a QString then you declare it as such:

class MyClass
{
    QString myFunction(); //< MyClass::myFunction is going to return a value of type QString.
}

QString MyClass::myFunction()
{
    return QString("Some string"); //< The function returns the value and it is of type QString
}

mrjj

sorry my bad
void findimage();

should have been

QString findimage();

I think i should let @kshegunov handle this one as I keep missing the errors :)

gabor53

@mrjj
I changed the .h file declaration to QString findimage();.
Now it works without error, but I still can't capture the findimage returned value (fileName) in the line after connect.
code
The function works because the qDebug in the last line returns the correct value.
How can I return the value before the add layout section so I would be able to display the image next to the button? (That was the original issue I had).

Thank you.

kshegunov

@mrjj
As I noted before, the errors are swiftly and cleanly reported by the compiler:

C:\Programming\backup\Folkfriends\additem.cpp:195: error: no match for 'operator=' (operand types are 'QString' and 'void')
connect(Image_Button, &QPushButton::clicked, this { imagePath = findimage( fileName);});

So the compiler can't make heads or tails of what to do with the arguments given to the assignment operator. :)

kshegunov

@gabor53

http://forum.qt.io/topic/64635/function-with-signals-slots/12

@jsulm already gave you what the problem with this construct is. You're trying to predict the future. You want at some point when the user clicks a button to take an image, and that's fine. The erroneous part is when you want to go back in the past where the connect was made and do something with that image, it's simply not possible. If you want to operate on the value returned from your function, then you should put the code that uses it inside the lambda function, so you wouldn't need to jump through time-travel hoops to get the string. QObject::connect simply says that some function should be called when a signal is emitted, it doesn't guarantee you in any way when or if that shall happen.

Kind regards.

gabor53

Thank you all. It worked.