With Respect To ScrollBar To Rectangle

[p3c0]

@Pradeep-Kumar.M Must be some problem in your code. Try doing same as done in that example.

[Pradeep Kumar]

@p3c0

same thing i did it, will you please try, i want the scrollbar to have dragged with respect to mouse simulateonusly, not in opposite fashion, i tried,

[p3c0]

@Pradeep-Kumar.M Can you explain it w.r.t to that example ? That example works fine as expected.

[Pradeep Kumar]

@p3c0

code is working fine, but the thing is scrollbar has to move w.r.t to mouse, when i want to scroll, for example in this forum if u want to scroll up, u will move your mouse up, w.r.t to scrollbar, but in the example case moving mouse upwards, scrolling takes place downwards, i mean to say opposite direction.

[p3c0]

@Pradeep-Kumar.M Nope. If you scroll down the scrollbar moves down and ofcourse the image will go up and v.v. That's the intended behaviour.

[Pradeep Kumar]

@p3c0

hm k kk

[Pradeep Kumar]

@p3c0

and one more if we have implementation that works with keys press,
will it work for mouse area on clicked?.

[p3c0]

@Pradeep-Kumar.M Yes should work. Create a function and call that function when required.

[Pradeep Kumar]

@p3c0

you mean to say create function form ex: function sample()
{
// implementation
}

mouse area{
anchors.fill: id
onclicked
{
sample()
}
}

[p3c0]

@Pradeep-Kumar.M Yes, so that same function can be called from Keys and MouseArea. No need to duplicate the code.

[Pradeep Kumar]

@p3c0

what i taught was if there is implementation for keys event
, their will be different implementation for mousearea alse

[p3c0]

@Pradeep-Kumar.M Ofcourse you will need to define a MouseArea as well as Keys.onUpPressed. But if the code that moves the scrollbar is similar then no need to duplicate it. Just put it in the function and call that function.

[Pradeep Kumar]

@p3c0

ya got it,
keys.onuppressed,keys.ondownpressed, coming from .js file, will the same logic work for mousearea
{
} also .

[p3c0]

@Pradeep-Kumar.M

will the same logic work for mousearea

Depends upon the logic :)

[Pradeep Kumar]

@p3c0
k k i''l try.