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Convert QVariantList to QList<Type> list

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  • M Offline
    M Offline
    mcosta
    wrote on 26 Mar 2015, 23:58 last edited by
    #12

    QSet is based on a hash table; this means that internally it uses qHash()

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    I 1 Reply Last reply 27 Mar 2015, 08:34
    0
    • I ikim
      26 Mar 2015, 22:02

      Hi All

      I have a QVariantList which is passed as a parameter to my function.

      void myfunc(const QVariantList &list)
      {
        // I want to convert this to  QList<Type> newList
        // where Type is the type() of list.at(0)
        // the variant list consists of variants all of the same type 
      }
      

      What I want to do is

      QList<Type> newList;   //how do I declare this if I dont know the Type
        foreach(QVariant v, list) 
          newList << v.value();
      

      Then create a QSet from the newList

      Is there a way of easily achieving this

      Regards

      Ikim

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      MayEnjoy
      wrote on 27 Mar 2015, 05:48 last edited by
      #13

      @ikim why not use QVariant::Type method? even you can use it with c++ template.

      I am a engineer.

      I 1 Reply Last reply 27 Mar 2015, 08:40
      0
      • M mcosta
        26 Mar 2015, 23:58

        QSet is based on a hash table; this means that internally it uses qHash()

        I Offline
        I Offline
        ikim
        wrote on 27 Mar 2015, 08:34 last edited by
        #14

        @mcosta Thanks but this gives a compile error

        QSet<QVariant> existingValues;
        existingValues.insert(1);

        1 Reply Last reply
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        • M MayEnjoy
          27 Mar 2015, 05:48

          @ikim why not use QVariant::Type method? even you can use it with c++ template.

          I Offline
          I Offline
          ikim
          wrote on 27 Mar 2015, 08:40 last edited by
          #15

          @MayEnjoy Thanks, but how would this enable me to achieve my goal ?

          M 1 Reply Last reply 28 Mar 2015, 07:15
          0
          • M Offline
            M Offline
            mcosta
            wrote on 27 Mar 2015, 08:50 last edited by
            #16

            Which kind of error?

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            I 1 Reply Last reply 27 Mar 2015, 08:55
            0
            • M mcosta
              27 Mar 2015, 08:50

              Which kind of error?

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              ikim
              wrote on 27 Mar 2015, 08:55 last edited by
              #17

              @mcosta /usr/include/QtCore/qhash.h:882:24: error: no matching function for call to 'qHash(const QVariant&)'

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              • M Offline
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                mcosta
                wrote on 27 Mar 2015, 09:11 last edited by
                #18

                mmmm, You're right.

                So I suggest to create a template method

                This code works for me

                template <typename T>
                QSet<T> mergeList(const QVariantList& l1, const QVariantList& l2) {
                    QSet<T> s1, s2;
                
                    for (const QVariant& v: l1) {
                        s1.insert(v.value<T>());
                    }
                
                    for (const QVariant& v: l2) {
                        s2.insert(v.value<T>());
                    }
                
                    return s1 & s2;
                }
                

                Used as

                    QVariantList l1, l2;
                    l1 << 1 << 2 << 3;
                    l2 << 1 << 3 << 5;
                
                    QSet<int> s1 = mergeList<int> (l1, l2);
                    qDebug() << s1;
                
                    l1.clear();
                    l2.clear();
                
                    l1 << "Foo" << "Bar";
                    l2 << "Bar" << "Fred";
                
                    QSet<QString> s2 = mergeList<QString> (l1, l2);
                    qDebug() << s2;
                

                Once your problem is solved don't forget to:

                • Mark the thread as SOLVED using the Topic Tool menu
                • Vote up the answer(s) that helped you to solve the issue

                You can embed images using (http://imgur.com/) or (http://postimage.org/)

                I 1 Reply Last reply 27 Mar 2015, 09:30
                1
                • M mcosta
                  27 Mar 2015, 09:11

                  mmmm, You're right.

                  So I suggest to create a template method

                  This code works for me

                  template <typename T>
                  QSet<T> mergeList(const QVariantList& l1, const QVariantList& l2) {
                      QSet<T> s1, s2;
                  
                      for (const QVariant& v: l1) {
                          s1.insert(v.value<T>());
                      }
                  
                      for (const QVariant& v: l2) {
                          s2.insert(v.value<T>());
                      }
                  
                      return s1 & s2;
                  }
                  

                  Used as

                      QVariantList l1, l2;
                      l1 << 1 << 2 << 3;
                      l2 << 1 << 3 << 5;
                  
                      QSet<int> s1 = mergeList<int> (l1, l2);
                      qDebug() << s1;
                  
                      l1.clear();
                      l2.clear();
                  
                      l1 << "Foo" << "Bar";
                      l2 << "Bar" << "Fred";
                  
                      QSet<QString> s2 = mergeList<QString> (l1, l2);
                      qDebug() << s2;
                  
                  I Offline
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                  ikim
                  wrote on 27 Mar 2015, 09:30 last edited by
                  #19

                  @mcosta Thanks for your effort, but this still doesn't solve the problem as I dont know the Type at compile time

                  1 Reply Last reply
                  1
                  • M Offline
                    M Offline
                    mcosta
                    wrote on 27 Mar 2015, 10:46 last edited by
                    #20

                    Hi,

                    I'm not a C++ super-guru but I don't think you can do it because the compiler must know the type of each variable at compile time.

                    A solution could be implement qHash(const QVariant &v) and use QSet<QVariant>

                    Once your problem is solved don't forget to:

                    • Mark the thread as SOLVED using the Topic Tool menu
                    • Vote up the answer(s) that helped you to solve the issue

                    You can embed images using (http://imgur.com/) or (http://postimage.org/)

                    I 1 Reply Last reply 27 Mar 2015, 10:49
                    1
                    • M mcosta
                      27 Mar 2015, 10:46

                      Hi,

                      I'm not a C++ super-guru but I don't think you can do it because the compiler must know the type of each variable at compile time.

                      A solution could be implement qHash(const QVariant &v) and use QSet<QVariant>

                      I Offline
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                      ikim
                      wrote on 27 Mar 2015, 10:49 last edited by
                      #21

                      @mcosta thanks for your time, I think you may be right :)

                      1 Reply Last reply
                      0
                      • I ikim
                        27 Mar 2015, 08:40

                        @MayEnjoy Thanks, but how would this enable me to achieve my goal ?

                        M Offline
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                        MayEnjoy
                        wrote on 28 Mar 2015, 07:15 last edited by
                        #22

                        @ikim said:

                        @SGaist yes I could compare each QVariant in the list but that would mean iterating over the entire list to determine if the item exists in the second list. Is that my only option ?

                        Thanks

                        I think @mclark 's answer is the better one.

                        I am a engineer.

                        1 Reply Last reply
                        0
                        • S Offline
                          S Offline
                          SGaist
                          Lifetime Qt Champion
                          wrote on 28 Mar 2015, 21:32 last edited by
                          #23

                          You can also implement qHash for the type you need to support and thus it will be used automatically in all your software.

                          #include <QtDebug>
                          
                          inline uint qHash(const QVariant &key, uint seed = 0)
                          {
                              switch (key.userType()) {
                                  case QVariant::Int:
                                      return qHash(key.toInt(), seed);
                          
                                  case QVariant::UInt:
                                      return qHash(key.toUInt(), seed);
                          
                                 // add all cases you want to support;
                          
                              }
                          
                              return 0;
                          }
                          
                          int main( int argc, char * argv[] )
                          {
                              QApplication app( argc, argv );
                              QVariantList vl1;
                              QVariantList vl2;
                          
                              for (int i = 0 ; i < 5 ; ++i) {
                                  vl1 << i;
                              }
                          
                              for (int i = 0 ; i < 3 ; ++i) {
                                  vl2 << i;
                              }
                          
                              qDebug() << (vl1.toSet() & vl2.toSet());
                          
                              return 0;
                          }
                          

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