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[Solved]Program exited with code 0

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  • G Offline
    G Offline
    gayu
    wrote on 15 Nov 2012, 06:42 last edited by
    #1

    Hi,
    I am new to Qt. I am using Qtcreator version 4.6.2, in linux.
    The main theme of my project is to prepare a question bank.
    In that, through the editor i am entering the various options (i.e fill,choose,match,short ques,and long ques).
    While entering through editor, the .xml file first generate and from that xml file it will enter the database.
    In that the i’m having problem in entering short ques and long ques into the database.
    While entering the Question and Answer,it generates the xml file bt nt enter to the database, and get exit from the editor showing the following.

    @
    ASSERT: “i >= 0” in file /usr/include/qt4/QtCore/qstring.h, line 875
    The program has unexpectedly finished.
    /home/tts/Desktop/QbankEditorAllrequirement/qbank exited with code 0
    @
    please help me to solve this.

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    0
    • L Offline
      L Offline
      lgeyer
      wrote on 15 Nov 2012, 07:02 last edited by
      #2

      Your index to operator[] is invalid (< 0).

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      0
      • G Offline
        G Offline
        gayu
        wrote on 15 Nov 2012, 07:05 last edited by
        #3

        sorry to ask might be a silly Question.
        What "index to operator[] is invalid (< 0)" this mean

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        0
        • A Offline
          A Offline
          AlekseyOk
          wrote on 15 Nov 2012, 07:17 last edited by
          #4

          This means that you are trying to make something like this:

          @
          QVector<int> vec;
          vec[-1] = 0;
          @

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          0
          • G Offline
            G Offline
            gayu
            wrote on 15 Nov 2012, 07:23 last edited by
            #5

            ya, in my code it is returning the index value "index=-1". so it is exiting.
            It should not return the "-1". I am trying to solve, bt i dont know how to solve this. please help me

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            • A Offline
              A Offline
              AlekseyOk
              wrote on 15 Nov 2012, 07:26 last edited by
              #6
              1. Find error in your code
                or/and
              2. Check for correctness your index @(index >= 0 && index < vec.size())@ before operator[]

              if (index == -1) is an exit condition - just exit from your app :-))

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              • G Offline
                G Offline
                gayu
                wrote on 15 Nov 2012, 07:56 last edited by
                #7

                The index is initialized to '0'.
                Some formats are there to enter the Question and Answers in Database, through editor.
                While the Question is entered the parseQuestion function is called.
                While the Answer is entered the parseOption function is called.
                In the parseOption function, the condition is checked. The function includes the index,option,stmt,phrase .
                The phrase is the one entered within the '| ' (eg |Lotus\ is our national flower) In this eg to highlight "Lotus" we are using the '| ' symbol.
                In the above eg Lotus is the phrase, if any stmt seen before the phrase is considered as stmt1,and after the phrase is the stmt2.

                I give another eg.

                If i am entering a Ques and Ans like this

                What is Qt?
                Qt is a |cross platform application framework
                Qt is a is the stmt1
                *|cross platform application framework* is the phrase

                While running with above eg my code runs fine and every thing enters into the database.

                But when i am entering like this

                What is Qt?
                Qt is a |cross platform application framework\ .
                Qt is a is the stmt1
                *|cross platform application framework* is the phrase
                .. is considered as the stmt2 and returns the index value as '-1' since there is no '|'
                The following is the condition it checks for the stmt2, and no '|' is seen so returning '-1'

                until for stmt1 amd the phrase it reads the index value as +ve value only.
                bt when reading the stmt2 it is returning '-1'.

                @
                while(option[index] != '|')
                {
                stmt1[j] = option[index];
                cout<<"stmt1[j]\n"<<stmt1<<endl;
                if(option[index]=='\0')
                {
                stmt1[j] = '\0';
                option[0] = '\0';
                return -1; //here it returns '-1'
                }
                index++;
                j++;
                }
                @

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                • A Offline
                  A Offline
                  AlekseyOk
                  wrote on 15 Nov 2012, 08:13 last edited by
                  #8

                  You should check for '|' and NOT '\0'.

                  E.g.:

                  @
                  while(option[index] != '|' &&
                  option[index] != '\0')
                  @

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                  0
                  • G Offline
                    G Offline
                    gayu
                    wrote on 15 Nov 2012, 09:04 last edited by
                    #9

                    I used some cout stmts to check wat the option of index is.
                    The option[index] is printing as the "|" symbol.
                    After the stmt1 the "|" is seen and return the option[index] as "|" and returning the index value as +ve value.
                    Then when coming to the stmt2 it checks the condition, "|" . The condition is not get satisfied returning "-1".

                    And I also tried wat u said,
                    @
                    1.
                    while(option[index] != '|' &&
                    2.
                    option[index] != '\0')
                    @
                    It is not taking the phrase value,only it reads the stmt1, and exit from the editor.

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                    • A Offline
                      A Offline
                      AlekseyOk
                      wrote on 15 Nov 2012, 09:06 last edited by
                      #10

                      try to add you check

                      @
                      if(option[index]=='\0')
                      {
                      stmt1[j] = '\0';
                      option[0] = '\0';
                      return -1; //here it returns '-1'
                      }
                      @

                      after the loop if you want to exit with code -1.

                      Why are you using this loop instead of "QString::indexOf":http://qt-project.org/doc/qt-4.8/qstring.html#indexOf

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                      • G Offline
                        G Offline
                        gayu
                        wrote on 15 Nov 2012, 09:16 last edited by
                        #11

                        Ya i checked by adding the "if" after the loop.
                        But it doesn't exit from the loop, runs until i stop the execution.

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                        • A Offline
                          A Offline
                          AlekseyOk
                          wrote on 15 Nov 2012, 09:18 last edited by
                          #12
                          1. Is option a QString?
                          2. Is option ends with '\0'?

                          If 1 and 2 are true than this loop shouldn't be infinite.

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                          0
                          • G Offline
                            G Offline
                            gayu
                            wrote on 15 Nov 2012, 09:30 last edited by
                            #13

                            ya the option is QString only.
                            You asked me to check the "if" by adding it after the loop. By adding it after the loop only becomes infinite.

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                            • A Offline
                              A Offline
                              AlekseyOk
                              wrote on 15 Nov 2012, 09:39 last edited by
                              #14

                              Should this help?

                              @
                              int pos1 = option.indexOf('|');
                              if (pos1 != -1)
                              {
                              stmt1 = option.left(pos1);

                              int pos2 = option.indexOf('\\', pos1);
                              if (pos2 != -1)
                              {
                                  phrase = option.mid(pos1, pos2 - pos1);
                              }
                              

                              else
                              {
                              // there is no '|' symbol in option
                              }
                              @

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                              0
                              • G Offline
                                G Offline
                                gayu
                                wrote on 15 Nov 2012, 10:11 last edited by
                                #15

                                Ya i tried tis by replacing tat, bt it is still the same not exiting from the loop, also printing the stmt as null.

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                                0
                                • A Offline
                                  A Offline
                                  AlekseyOk
                                  wrote on 15 Nov 2012, 10:25 last edited by
                                  #16

                                  You shouldn't use a single backslash in option string, because it will be processed as '.' in second case.
                                  So, before processing, replace single backslashes with doubled or select another symbol

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                                  0
                                  • G Offline
                                    G Offline
                                    gayu
                                    wrote on 15 Nov 2012, 10:33 last edited by
                                    #17

                                    This means whether you are asking me to use double backslash in the phrase itself or at the end of last stmt i've to put double backslash.

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                                    0
                                    • G Offline
                                      G Offline
                                      gayu
                                      wrote on 15 Nov 2012, 11:23 last edited by
                                      #18

                                      By trying with this code,

                                      @
                                      1.int pos1 = option.indexOf('|');
                                      2.if (pos1 != -1)
                                      3. {
                                      4. stmt1 = option.left(pos1);
                                      5. int pos2 = option.indexOf('\', pos1);
                                      7. if (pos2 != -1)
                                      8. {
                                      9. phrase = option.mid(pos1, pos2 - pos1);
                                      10 }
                                      11. else
                                      12. {
                                      13. // there is no '|' symbol in option
                                      14. }
                                      @
                                      I am getting this error "commitdb.cpp:1219: error: a function-definition is not allowed here before ‘{’ token" in some other functions.
                                      so i removed this code and compile with the the original code itself.@@

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                                      • A Offline
                                        A Offline
                                        AlekseyOk
                                        wrote on 15 Nov 2012, 12:08 last edited by
                                        #19

                                        add } before else

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                                        0
                                        • G Offline
                                          G Offline
                                          gayu
                                          wrote on 15 Nov 2012, 12:23 last edited by
                                          #20

                                          Ya i added }
                                          Now it is not exiting from the editor and its working.
                                          But, the question is entering into database finely, the answer is not entering to the database (i.e options) printing the null values for option,stmt1 and stmt2 . Also the null values are entering to database more than once

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