What is the class of the children of a QMenu?

goetz

If you click on the entry that represents a sub menu, that entry is associated with a QAction and/or a QMenu. If you disable that one all its submenu entries are disabled too resp. you cannot open that submenu. Which looks quite sensible to me, that's what I would expect here.

JulienMaille

Thanks for your answer Volker!
Maybe I was not clear.!http://pix.wefrag.com/i/7/7/a/1/8/448248ff5d702f9bbb4bf57907143104.png(menu)!
If I shift+click "About" the whole Help menu is disabled.

JulienMaille

I'm still struggling with this. Let's formulate the problem differently:
I want to change the stylesheet of all the widgets associated with a specific QAction.
I can do this for actions added to a toolbar (in that case the corresponding widget is a QToolButton) but how do I access the widget that represent the action in a QMenu?

QAction::associatedWidgets() does not help, it returns the QMenu not the menu item.

andre

QMenu is one widget. Take a look at its code to see how it is rendered. It does not consist of QToolButtons or QActions. Note that QAction is not a widget at all. So, I guess what you are after is not possible, at least not without subclassing QMenu.

JulienMaille

Thanks for your help Andre. I agree that QActions are not QWidgets. However there is something I don't understand:

when you add a QAction to a QToolBar, you "get" a QToolButton
when you add a QAction to a QMenu, do you "get" any widget?

If QMenu is one widget, maybe it has child widgets?
If it has no child, then I guess it is impossible to style its items?

andre

No, you do not get a widget for an action on a QMenu. However, you can style items using style sheets. Items support a whole array of pseudo states you can use. If you want to keep only a specified action enabled, you should also keep the container it is in enabled.

JulienMaille

I tried to "style a specific item":http://doc.trolltech.com/latest/stylesheet-syntax.html#selector-types of a QMenu using selector, dynamic properties and object name.
None of these methods worked.

andre

You'll need to show more than just "It doesn't work" in order for us to be able to help you.

JulienMaille

Ok, I set this stylesheet to my QMenu containing (among others) a QAction whose object name is "actionExit" and whose text is "Exit". I also added a dynamic property to the QAction: a boolean called "styleMe" set to true.
@*#actionExit { background-color: blue; }
*[text="Exit"] { background-color: blue; }
*[styleMe="true"] { background-color: blue; }@
I also tried with QWidget or QMenu::item instead of *

andre

No, that won't work. Now you are trying to style the items in your menu as if they are widgets. Again, they are not. You can only use the QMenu::item subcontrol and the associated pseudo states.

JulienMaille

By pseudo states you mean this list?
@:checked
:disabled
:enabled
:focus
:hover
:indeterminate
:off
:on
:pressed
:unchecked @
Is this is the only way to set specific styling?

andre

Unless you want to reimplement QMenu itself, and do the rendering yourself: yes, it is.