What is the class of the children of a QMenu?
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I'am trying to install an event filter on all existing QObject.
Then I toggle the enabled property when shift+clicking a graphical element. I am also printing out the clicked element's class.It works for most of the QWidgets but when I click on a QAction of a QMenu, the whole menu is disabled, and my output is "QMenu" when I would expect a QToolButton, or a QAction.
Here is my code:
@bool MainWindow::init()
{
...
QList<QObject*> objects = this->findChildren<QObject*>();
for (int i = 0; i < objects.size(); ++i)
objects.at(i)->installEventFilter(this);
}bool MainWindow::eventFilter(QObject *obj, QEvent event)
{
if (event->type() == QEvent::MouseButtonPress && ( ((QMouseEvent)event)->modifiers() & Qt::ShiftModifier ) )
{
obj->setProperty("enabled", !obj->property("enabled").toBool());
qDebug(obj->objectName().toLatin1().data());
qDebug(obj->metaObject()->className());
return true;
}
else
{
// standard event processing
return QObject::eventFilter(obj, event);
}
}@ -
If you click on the entry that represents a sub menu, that entry is associated with a QAction and/or a QMenu. If you disable that one all its submenu entries are disabled too resp. you cannot open that submenu. Which looks quite sensible to me, that's what I would expect here.
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Thanks for your answer Volker!
Maybe I was not clear.!http://pix.wefrag.com/i/7/7/a/1/8/448248ff5d702f9bbb4bf57907143104.png(menu)!
If I shift+click "About" the whole Help menu is disabled. -
I'm still struggling with this. Let's formulate the problem differently:
I want to change the stylesheet of all the widgets associated with a specific QAction.
I can do this for actions added to a toolbar (in that case the corresponding widget is a QToolButton) but how do I access the widget that represent the action in a QMenu?QAction::associatedWidgets() does not help, it returns the QMenu not the menu item.
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QMenu is one widget. Take a look at its code to see how it is rendered. It does not consist of QToolButtons or QActions. Note that QAction is not a widget at all. So, I guess what you are after is not possible, at least not without subclassing QMenu.
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Thanks for your help Andre. I agree that QActions are not QWidgets. However there is something I don't understand:
- when you add a QAction to a QToolBar, you "get" a QToolButton
- when you add a QAction to a QMenu, do you "get" any widget?
If QMenu is one widget, maybe it has child widgets?
If it has no child, then I guess it is impossible to style its items? -
No, you do not get a widget for an action on a QMenu. However, you can style items using style sheets. Items support a whole array of pseudo states you can use. If you want to keep only a specified action enabled, you should also keep the container it is in enabled.
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I tried to "style a specific item":http://doc.trolltech.com/latest/stylesheet-syntax.html#selector-types of a QMenu using selector, dynamic properties and object name.
None of these methods worked. -
You'll need to show more than just "It doesn't work" in order for us to be able to help you.
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Ok, I set this stylesheet to my QMenu containing (among others) a QAction whose object name is "actionExit" and whose text is "Exit". I also added a dynamic property to the QAction: a boolean called "styleMe" set to true.
@*#actionExit { background-color: blue; }
*[text="Exit"] { background-color: blue; }
*[styleMe="true"] { background-color: blue; }@
I also tried with QWidget or QMenu::item instead of * -
No, that won't work. Now you are trying to style the items in your menu as if they are widgets. Again, they are not. You can only use the QMenu::item subcontrol and the associated pseudo states.
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By pseudo states you mean this list?
@:checked
:disabled
:enabled
:focus
:hover
:indeterminate
:off
:on
:pressed
:unchecked @
Is this is the only way to set specific styling? -
Unless you want to reimplement QMenu itself, and do the rendering yourself: yes, it is.