QML and Qt Quick

Nope, just set it to false and you'll get the rectangle's background.

push

Thanks, syntax or not:-) I need a way to detect such errors. You are right, with @ height: myValue @ I get a ReferenceError: myValue is not defined message, which is very helpfull. But not for the line @ height: parent.heightt @ I see no reason to ignore the second one except a bug. Best Steffen

For sending strings, you can check the code posted above. When you want to switch pages, simply send the loadPage signal and the string as the argument. As you can see, I've used the pageName string to change the page. I don't know about the Person class, maybe you can use variant, or perhaps QtObject, but I'm really not sure.

@srav219: Did you find your solution? I am having the same problem as you. It works when I run on my Ubuntu desktop, but it does not run on my embedded target device (Angstrom). I can build (cross compile) it just find on my host machine, but running on the target does not work. Please help! Thanks,

with Qt5.1 void MainWindow::on_pushButton_clicked() { QQuickView *view = new QQuickView; qDebug()<<"flavio"; view->setSource(QUrl("qrc:/qml/pathview/pathview-example.qml")); view->show(); }

It should do that, unless you're pulling in the wrong direction. Try pulling in the opposite direction. You may want to limit the flickableDirection property to Flickable.VerticalFlick so you can test for just one axis.

Thank you tucnak. Edit : but is there a solution to style spinboxes to be accessible through touch screens ?

Perhaps you could use a SequentialAnimation and PropertyAction inside it after the pop-up animation. Then for PropertyAction you can enable/disable the Submenubars as needed. This way you could prevent the user from clicking any other buttons until the animation finishes. So just set enable to false with PropertyAction, then do a NumberAnimation (or whatever you're using), then use PropertyAction again to enable the Submenubar again.

bq. you would need to react to the change of the power consumption, not the change of color, because if the color has already changed, then it makes no sense to animate it anymore (it has already changed to the destination color). this is logic. I tested it, and it does work. Thanks a lot

@SGaist, thank you for your help.