QML and Qt Quick

I am not getting your problem. Are you looking for something like this to print x and y when there is a position change. onPositionChanged: { console.log("x:"+ mouse.x+ " y:"+mouse.y) }

Here is a bug report: https://bugreports.qt.io/browse/QTBUG-99525 Please vote/watch it if you face the same problem.

OK thanks. The qt docs strongly imply that QML supports Javascript, but I guess it's a subset.

@qAminzzz if you know the formulas and they are static (always the same), then simply render them to an image and then display them on the label: https://math.tools/equation/image

It only works if you use the Fusion-style. The documentation states: The Fusion style uses the standard system palettes to provide colors that match the desktop environment.

I've found a much simpler (and maybe obvious?) workaround! Just capture the Quit menu on macOS: // (...) import Qt.labs.platform ApplicationWindow { id: mainwindow // (...) MenuBar { id: menubar // (...) Menu { title: "" MenuItem { id: quitaction text: qsTr("&Quit") shortcut: StandardKey.Quit onTriggered: mainwindow.close() } } } }

@AI_Messiah from QML-only via FolderListModel

Thank you, that solved my problem!

Hi @qcoderpro , Here you can find a video tutorial, a little outdated but quite complete, on how to setup and use QML for Android: https://www.youtube.com/watch?v=w2RRgRGHsDA This one is also very explicit, but it is in Spanish language and does not show all setup steps: https://www.youtube.com/watch?v=v6SvsTPEe4I Both allowed me to develop my first android application. Regards

as a workaround for now I added a slot in my thread to do that for me using C++ and called it using QML [image: 8b83f1ec-87ba-4d97-a211-904f108e4390.png] if there's a better way to do it please do tell!

https://doc.qt.io/archives/qt-5.9/qtquick-tutorials-dynamicview-dynamicview4-example.html I kind of wish I saw this earlier when doing some of this work. I ended up using some C++ models to do this.

See here; https://forum.qt.io/topic/79071/how-to-set-style-of-button-in-qml Try this; import QtQuick 2.12 import QtQuick.Window 2.12 import QtQuick.Controls 2.12 Window { width: 640 height: 480 visible: true title: qsTr("Hello World") Button { id: control text: "Button" anchors.centerIn: parent background: Rectangle { implicitWidth: 200 implicitHeight: 50 border.width: control.activeFocus ? 2 : 1 border.color: "#888" radius: 4 gradient: Gradient { GradientStop { position: 0 ; color: control.pressed ? "#ccc" : "#eee" } GradientStop { position: 1 ; color: control.pressed ? "#aaa" : "#ccc" } } } } }