QML and Qt Quick

You can check the status of component with its status property and the errorString() method.

@JustAbhi said in Override CloseEvent for qml file in Qt Creator and python: So now I am facing a new bug (I think its a bug). Your Answer is correct it does what I want but then the Qt Creator has a problem with the above mentioned line. The error pops up in Qt Creator when editing the qml file and prevents the design tab to open. The error goes something like: Invalid property name "onClosing". (M16) Yes it is a QT Creator issue. This issue has already been reported in: https://bugreports.qt.io/browse/QTCREATORBUG-13347

As a workaround we can use QMAKE_RESOURCE_FLAGS += -threshold 0 for QMake projects. All the files from resources will be compressed and most part of the QML code will be hidden. The reason why all QML files are included to the final executable when QtQuickCompiler is turned on is described here.

@vicky_mac said in Custom streamer pipeline in QML: module org.freedesktop.gstreamer.GLVideoItem if vaapi is used in the pipeline on linux, install libva-dev

Sorry, I misunderstood some concepts. Now running with: Backend backend; QQmlApplicationEngine engine; engine.rootContext()->setContextProperty("backend", &backend); class Backend : public QObject { Q_OBJECT QML_ELEMENT

I think you will have to use https://doc.qt.io/qt-5/qml-qtquick-listview.html#itemAtIndex-method to get the Item before and after the current item. I think if it is not rendered it may return null. But if that is the case it should be off screen. let beforeitem = <listviewid>.itemAtIndex(index-1) let afteritem = <listviewid>.itemAtIndex(index+1) Probably need to do check with isChecked to trigger changes. Might need to be tricky and fire off events or create a signal that fires anytime any isChecked changes. You can use Qt.callLater to make sure the event is not called for every item all the time.

You should setup wireshark and check what happens exactly. At some point you wrote you had a timeout error, that's one of the thing you should resolve first it means that one side fails to connect to the other. Don't forget one important thing: your server needs to be accessible from outside of your network especially if you connect to it from a mobile device. You will have lots of items between your server and client like firewalls, NAT layers and whatnot.

I have QT Creator in Windows and Ubuntu, the version is 7.0.2, and both occurs the same problem.

There's no data because there's nothing using your CommSerial object on the QML side. By the way, calling a C++ class QmlWorker and then naming it Dlg in your QtQuick code does not make your code easy to understand.

Hello guys, I'm quite often facing the same problem. Who to fix this problem?

I've seen that and also found something online that indicated that you could pass a field width argument and if it was negative it would left align. I was really more interested in other things that you can do with C++ arg's, such as converting the base of a numeric argument. Thanks, Greg