How make a program interface asynchronous with the program logic execution?

[gyok]

I have a program which go through QTableWidget cells (left&right) and change symbols in them. Execution starts when I press "run" button, but when program executing I can't see intermediate result, only finish result. If I trying resize program interface it freezing. Already trying to avoid this problem with running program logic with concurrent function:

int Run() {
    QFuture<int> future = QtConcurrent::run(this, &Core::run);
    return 0;
}

int Core::run () {
    while (i < 5) {
        i++;
        execute();
        mainwindow.update();
        _table.update();
    }
    return 0;
}

int Core::execute() {
    // move right in table
    _table.item(0, _current++)->background() = Qt::yellow;
    return 0;
}

But this not working. Should I try emit signals for execute() function to change colour of table cells, or how you remove freezing of program interface?

[Christian Ehrlicher]

@gyok said in How make a program interface asynchronous with the program logic execution?:

_table.item(0, _current++)->background() = Qt::yellow;

If _table is a QTableWidget I doubt this will ever compile.

[aha_1980]

@gyok the simplest way is to use a QTimer instead a loop. in the timeout slot, process one or a few cells, then exit the slot. that gives Qt the chance to refresh your GUI before you process the next elements.

Regards

[gyok]

@Christian-Ehrlicher I add this exemple of code to show the main idea of code