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Weird behavior of QList<T>

Unsolved General and Desktop

22 Posts 4 Posters 6.8k Views 1 Watching

I'm speechless... I can only thing of something weird going on in building

ok, let's try with an alternative.
replace

for (int i = 0; i < roomCount; i++)
   {
       printf(QString::number(i).toLatin1().data());
       printf(QString("Room #" + QString::number(i) + ", " + building->rooms.at(i).name + "\n\r").toLatin1().data());
       printf(QString("Switches: " + QString::number(building->rooms.at(i).switches.count()) + "\n\r").toLatin1().data());
       printf(QString("Blinds: " + QString::number(building->rooms.at(i).blinds.count()) + "\n\r").toLatin1().data());
       printf("+---------------------------+\n\r");
   }

with

foreach(const kRoom& singleRoom, building->rooms){
qDebug() << singleRoom.name;
}

wrote on

#21

@VRonin The qDebug-Variant works! Still don't understand why the old version doesn't but at least it does something now!

@jsulm @VRonin I am looking into other methods to output now

@Taz742 Yes, I am using Qt 5.9

A advtaco

@VRonin The qDebug-Variant works! Still don't understand why the old version doesn't but at least it does something now!

@jsulm @VRonin I am looking into other methods to output now

@Taz742 Yes, I am using Qt 5.9
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Taz742

wrote on last edited by

#22

@advtaco
The problem was qDebug () or foreach (const kRoom & singleRoom, building-> rooms) ?
Do what you want.
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