Call function when StackView.pop

Alexorleon

Hi.

If you make "stackview.push", "Component.onCompleted" will work, but if you do "stackview.pop" then the second time it is not called.
I need to call the function of the current "Item" when I do "stackview.pop". I can not find the signal I need.

property int testNum: 1

    StackView {
        id: stack
        anchors.fill: parent
        initialItem: view1

        onCurrentItemChanged: {
            // I think I need to write something here, but what?
        }
    }

    Component {
        id: view1

        Rectangle {
            color: "lightblue"

            // I need to call this function after stack.pop
            function func() {
                testNum *= 10
            }

            // Component.on ???

            // This is called only once
            Component.onCompleted: func()

            Text {
                text: testNum.toString()
                anchors.centerIn: parent
            }
            MouseArea {
                anchors.fill: parent
                onClicked: stack.push(view2)
            }
        }
    }
    Component {
        id: view2

        Rectangle {
            color: "lightgreen"

            MouseArea {
                anchors.fill: parent
                onClicked: {
                    testNum++
                    stack.pop()
                }
            }
        }
    }

jpnurmi

The counterpart for Component::onCompleted() is Component::onDestruction().

Alexorleon

@jpnurmi, I need to call a function that is in "View1" when I go back there.

ekkescorner

my Pages all have a name property

property string name: "QueueItemDetailPage"

I do not simply a pop() on the stack, I'm calling popOnePage()

function popOnePage() {
            var page = pop()
            if(page.name == "QueueItemDetailPage") {
                // if using Loader deactivate here or call functions if not using onDeconstruction()
                 page.mySpecialFunction()
                detailLoader.active = false
                return
            }
           // and also for the next ones
        } // popOnePage

take a look at some of my sample apps where I'm doing this
https://appbus.wordpress.com/category/qt-for-mobile/overview/

jpnurmi

Depending on what you're trying to achieve, some of the attached signals introduced in Qt Quick Controls 2.1 in Qt 5.8 might be useful:

For your particular use case, the last one might be interesting.

Component {
    id: view2
    Rectangle {
        StackView.onRemoved: doSomething()
    }
}

ekkescorner

@jpnurmi
thx.
have overlooked these new signals from 2.1

ibia

I do not know if it can help you, in the case you are. But, I think you can use the "depth" property (the signal onDepthChanged) to know if it has increased or decreased.

Alexorleon

Many thanks to all!

I forgot to say that I use Qt 5.7. If it is necessary.
I don't understand why I didn't get it right away :)

property int testNum: 1

    StackView {
        id: stack
        anchors.fill: parent
        initialItem: view1

        function ff() {
            // if (depth or name ...) {}
            currentItem.func()
        }
    }

    Component {
        id: view1

        Rectangle {
            color: "lightblue"

            function func() {
                testNum *= 10
            }

            Component.onCompleted: func()

            Text {
                text: testNum.toString()
                anchors.centerIn: parent
            }
            MouseArea {
                anchors.fill: parent
                onClicked: stack.push(view2)
            }
        }
    }
    Component {
        id: view2

        Rectangle {
            color: "lightgreen"

            MouseArea {
                anchors.fill: parent
                onClicked: {
                    testNum++
                    stack.pop()

                    // Additionally call the function
                    stack.ff()
                }
            }
        }
    }

jpnurmi, in the future I will go to Qt 5.8

ekkescorner, a wonderful blog, I will definitely read it.