What does QTimer::singleShot(0, this, SLOT(SlotName))); do
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In my function
void myView::mouseReleaseEvent(QMouseEvent* event)
{
if (action == move) {
QTimer::singleShot(0, this, SLOT(moveItems()));
}
}}
void myView::mouseReleaseEvent(QMouseEvent* event)
{
if (action == move) {
// handle move
// update the x y coordinates in our own customised database code
}}
My question is I am not able to get What does QTimer::singleShot(0, this, SLOT(SlotName))); do ?
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It will call moveitems function immediately only once. Just look at documentation as well. "a QTimer with a timeout of 0 will time out as soon as all the events in the window system's event queue have been processed".
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Is it a good practice to call moveitems once after mouseReleaseEvent , to avoid many calls to moveItems ?
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In your case every time mouse is released called moveitems function will be called. May b this is done with purpose as this has effect of calling moveitems function as event loop processing. Wha is the idea behind calling moveitems ? What does it do ?
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myView is QGraphicsView
We have our own parallel database items for objects shown in myView and
The moveItems update the x and y coordinates of these database objects s
we need to update the x and y coordinates of these database objects so the GUI and database are in sync -
Understood now. There is no need to move your single shot method outside mouserelease. That is the right way. Why did u think of moving single shot function outside your mouserelease ?
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sorry for delayed reply I was just trying understand the design , I think your answers solved my quries
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Super. Just move the issue to "Solved" state. It helps other. Enjoy Qt!!
