Problem with arg at QString.

Leon

What am i doing wrong here?

@ QString written = QString(tr("In random order") + ":\n" + "Leon Vytanos <" + ("<a >%1</a>").arg("leon.check.me@gmail.com") + ">\nAlex Solanos <" + ("<a >%1</a>").arg("alexsol.developer@gmail.com") + ">");
@

I kwow the "(" is wrong but i am not familiar with arg..

I am trying to do this..

!http://img35.imageshack.us/img35/6444/screenshot2psv.png(Screenshot)!

Eddy

You cannot use tr with the + QString operator.

You just use one string with several %1 %2 %3 arguments

Leon

Yes but the part i want to be translateble is only the "In random order" text..
Even if i change the second %1 to %2 i have some errors

error: request for member ‘arg’ in ‘("<a >%1</a>")’, which is of non-class type ‘const char [154]’

Eddy

Here is an example from the book
C++ GUI Programming with Qt 4 by Jasmin Blanchette; Mark Summerfield.

// WRONG
@statusBar()->showMessage(tr("Host " + hostName + " found"));@
The solution is to use QString::arg():

@statusBar()->showMessage(tr("Host %1 found").arg(hostName));@

Leon

And what would you have done if there was a second argument?

Eddy

@statusBar()->showMessage(tr("Host %1 found %2").arg(hostName).arg(parameter));
@

Do you know the book i mentioned? It's free and it has a complete chapter devoted to translating Qt applications.

Leon

Now i understand! Hmm i gave a try:
@ QString written = QString(tr("In random order") + ":\n" + "Leon Vytanos <" + "<a >%1%2%3%4%5</a>").arg("leon.check.me@gmail.com").arg(">\nAlex Solanos <").arg("<a >").arg("alexsol.developer@gmail.com").arg(">");
@

No erros but the textbrowzer is somehow like this now..
!http://img36.imageshack.us/img36/3006/screenshot3izm.png(Screenshot)!

I will be sure to take a look at the book.. Is it real free? Cause i see that at Amazon it costs 25$

Eddy

you can find a link to the free book here :

http://doc.qt.nokia.com/4.7/how-to-learn-qt.html

Leon

Downloaded! What about the problem?

Eddy

Hint : get rid of those "+" symbols in your string!
that's why you get those results as I explained already

Leon

Yes but if get rid of "+" then the whole thing will be translatable.. I want only the "In random order" part to be..

P.S The second edition of the book is better? And the second is the one that is not free?

Eddy

[quote author="Leon" date="1309702921"]Yes but if get rid of "+" then the whole thing will be translatable.. I want only the "In random order" part to be..[/quote]

Try the same without those plusses and you will see youself.
Tr() cannot translate as you think when those plusses are there. Read the book and it will be all clear to you.

[quote]P.S The second edition of the book is better? And the second is the one that is not free?[/quote]

It's almost the same. The first one is free as the webpage tells you.

Leon

Tr() will translate only the “In random order” part even if there are plusses.. I just checked it..
I just removed every "+" exactly the same problem. :/

@QString written = QString(tr("In random order%1%2%3%4%5%6%7%8")).arg(":\n").arg("Leon Vytanos <").arg("<a >%1%2%3%4%5</a>").arg("leon.check.me@gmail.com").arg(">\nAlex Solanos <").arg("<a >").arg("alexsol.developer@gmail.com").arg(">");
@

Eddy

can you please use my example instead and tell me what you see.?

one more try :
you use one looooong QString and AT THE END you put the arg() one after another. Don't put the arg() in between.

Leon

Ok look the code.. I removed the %1%2%3%4%5 because it was wrong.. So this should work..

@QString written = QString(tr("In random order%1%2%3%4%5%6%7")).arg(":\nLeon Vytanos <").arg("<a >").arg("leon.check.me@gmail.com").arg(">\nAlex Solanos <").arg("<a >").arg("alexsol.developer@gmail.com").arg(">");
@

I putted the outpout at tomboy notes and it look like this.. "SCREENSHOT":http://img843.imageshack.us/img843/8437/screenshot4rp.png

:/

Eddy

for instance :
@.arg("<a >")@

Do you need to translate this ?

@<a>")@

you should put everything in one string except the parts you want translated. put them in the arg()

i suggest you look at my example and experiment with it. Try to understand it. Read the books chapter.

Leon

I got it but same problem..

@QString written = QString(tr("In random order%1")).arg(":\nLeon Vytanos <<a >leon.check.me@gmail.com>\nAlex Solanos <<a >alexsol.developer@gmail.com>");
@

The book at that point doesn't say anything more than what you have already told me..

Eddy

Now it's ok. It's your html syntax that's wrong.

Leon

It seems like the textbrowzer has a different type of html.. so i finally found a solution and it is:

@ QString written = QString("<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0//EN" "http://www.w3.org/TR/REC-html40/strict.dtd"><html><head><meta name="qrichtext" content="1" /><style type="text/css">p, li { white-space: pre-wrap; }</style></head><body font-family:'Ubuntu'; font-size:11pt; font-weight:400; font-style:normal;">%1%2").arg(tr("In random order")).arg(":Leon Vytanos <<a >leon.check.me@gmail.com</a>>Alex Solanos <<a >alexsol.developer@gmail.com</a>></body></html>");
@

But the
@ QString written = QString("<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0//EN" "http://www.w3.org/TR/REC-html40/strict.dtd">@
part if i remove it there will be no problem, Should it be with or without this line?