Program is running in command line mode and another instance is launched!?

[alexandros]

Hello Developers :D

I have developed an application that takes command-line arguments.
The application has the ability to focus to the already running application if another instance is launched, by sending a message from the launched (new) application to the already open application.
So, the problem is that if the program is running with a command line argument (something that does not open the GUI, it runs in the console) and another instance is launched I don't know what to do exactly...
The argument is running a function every 30min using a qtimer and does nothing else actually, so, should I have the app connected and ready to receive a signal and when it receive it from the another instance to call the w.show(); (where w is MainWindow w;) and stop the command line-mode and its functionality (also maybe display a message that the process X has stopped because another instance was launched) ?

I think that this is what I should do but not sure, and I don't want to do something wrong and have to correct it afterwards... (also by doing my way of thinking, MainWindow w; should be global)

So, what would be your way to do it, or what do you expect to be the behaviour of a program if it had a command-line interface and GUI was called?

Thanks :)

[tobias.hunger]

Are you looking for something like "this":http://doc.qt.nokia.com/solutions/4/qtsingleapplication/qtsingleapplication.html?

[alexandros]

Thank Tobias for the answer!
No! The problem is specific :)
I have my own (really safe, no files used) way to check if my application is running.

I don't need this.

I want your opinion about what would you have done in an occassion where your program was running in non-GUI mode and GUI was called, and briefly how would you do it (I have mentioned my way in the 1st post)