Debug Qt vs memory edit

[Kh_nguyen719]

Hi all,
I have a question about debugging on Qt - Ubuntu 64bits. Currently, I have a code as follows:
int a = 257;
char* p = (char*)&a;
However, my issue is printf pointer's address and address of object is different.
Address of pointer - printf: prinntf("%p", p) - Result: 0x7ffef7ccd694
Address of pointer - open memory edit: 7ffef7ccd698
Who can explain this issue help me? Thanks for advanced.

[hskoglund]

Hi, the 1st address is what the pointer points to (the value of the pointer) and the 2nd address is the address to the pointer itself.

[Chris Kawa]

First of all there's no pointers in your example. %p is for printing pointers and p is not a pointer.
If you want to print the value of p, which is the truncated address of a, you would use printf("%d", p).
If you want to print the address of p you would use printf("%p", &p).

[Kh_nguyen719]

Thank all,
I also wanna ask more a question. If I wanna watch value at address what the pointer point to - value of pointer - in memory edit
So what to it will be show how on Qt instead of printf address and then pass those address to memory edit ? Because when open memory edit, it is address of pointer - not address pointer points to.