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trouble with QByteArray

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  • ? Offline
    ? Offline
    A Former User
    wrote on last edited by
    #1

    i done this operation
    quint32 registry =0x00000000;
    quint8 value1l=3;
    quint8 value2=0;
    quint16 value3=8191;
    quint16 value4=29;

    registry=(value4<<19)|(value3<<6)|(value2<<4)|value1;
    QByteArray b;
    b.setNum(registry,10);

    i get in debugger this one

    b "15728579" QByteArray
    [0] 49 '1' char
    [1] 53 '5' char
    [2] 55 '7' char
    [3] 50 '2' char
    [4] 56 '8' char
    [5] 53 '5' char
    [6] 55 '7' char
    [7] 57 '9' char

    why we get 8 Byte?
    i think it schoud be 6 Byte because
    value 1 ist 1Byte
    value 2 ist 1Byte
    value 3 ist 2 Byte
    value 4 ist 2Byte
    where may i think false ?

    kshegunovK 1 Reply Last reply
    0
    • ? A Former User

      i done this operation
      quint32 registry =0x00000000;
      quint8 value1l=3;
      quint8 value2=0;
      quint16 value3=8191;
      quint16 value4=29;

      registry=(value4<<19)|(value3<<6)|(value2<<4)|value1;
      QByteArray b;
      b.setNum(registry,10);

      i get in debugger this one

      b "15728579" QByteArray
      [0] 49 '1' char
      [1] 53 '5' char
      [2] 55 '7' char
      [3] 50 '2' char
      [4] 56 '8' char
      [5] 53 '5' char
      [6] 55 '7' char
      [7] 57 '9' char

      why we get 8 Byte?
      i think it schoud be 6 Byte because
      value 1 ist 1Byte
      value 2 ist 1Byte
      value 3 ist 2 Byte
      value 4 ist 2Byte
      where may i think false ?

      kshegunovK Offline
      kshegunovK Offline
      kshegunov
      Moderators
      wrote on last edited by kshegunov
      #2

      @carter_james
      Hello,

      why we get 8 Byte?

      http://doc.qt.io/qt-5/qbytearray.html#setNum

      Sets the byte array to the printed value of n in base base (10 by default) and returns a reference to the byte array. The base can be any value between 2 and 36. For bases other than 10, n is treated as an unsigned integer.

      Your number has 8 digits, so the string (stored in the byte array) contains 8 characters.

      i think it schoud be 6 Byte because

      If I understand correctly what you're trying to do, the byte array should be 4 bytes long, because qint32 registry is 32 bits (or 4 bytes) in size.

      where may i think false ?

      As I suggested in your previous thread, you should mask your numbers, because if the value1 variable has a value larger than 15, then this line:

      registry=(value4<<19)|(value3<<6)|(value2<<4)|value1;
      

      could simply produce incorrect values.

      That aside you can create byte array by casting the data appropriately:

      QByteArray data = QByteArray::fromRawData(reinterpret_cast<char * >(&registry), sizeof(registry));
      

      However you should be aware this doesn't take into account the endianness of the integer. If you need a portable way to transmit that data (for example through a network) you can serialize it with a data stream:

      QByteArray data;
      QDataStream stream(&data);
      stream << registry;
      

      So depending on what byte-order the binary data is expected to be in, you can call QDataStream::setByteOrder if applicable.

      PS.
      What you're trying to do with shifting can also be done with a union a struct and some bit fields as well:

      union  {
          struct   {
              qint8 field1 : 4;
              qint8 field2 : 2;
              qint16 field3 : 13;
              qint16 field4 : 13;
          } flags;
          char * raw;
      } dataVar;
      
      // Fill the data
      dataVar.flags.field1 = value1;
      dataVar.flags.field2 = value2;
      dataVar.flags.field3 = value3;
      dataVar.flags.field4 = value4;
      
      // Convert to byte array
      QByteArray data = QByteArray::fromRawData(dataVar.raw, sizeof(dataVar.flags));
      

      Which is used a bit more intuitively.

      Read and abide by the Qt Code of Conduct

      1 Reply Last reply
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