QDockWidget + Menu

[mirswith]

Hi,. This should be an easy one.

I have a QDockWidget that I have tied to a menu using addAction( dock->toggleViewAction() );

What I would like to do is have this dock not open when the program loads and the first time it is activated for it to be docked to Qt::BottomDockWidgetArea. I have managed to make it not load when my program does but when I activate it, it is floating.

Any ideas?

Thanks.

-=ben

[Knacktus]

Hmm, the following works for me (Python code and ignore the stylesheet stuff ...):

@import PyQt4.QtGui as QtGui
import PyQt4.QtCore as QtCore

class MyMainWindow(QtGui.QMainWindow):

def __init__(self, parent=None):
    super(MyMainWindow, self).__init__(parent)
    self.menu_bar = self.menuBar()
    
    self.tool_bar = self.addToolBar("&Session")
    self.dock = QtGui.QDockWidget("Test")
    self.dock.setWidget(QtGui.QLabel("Test"))
    self.addDockWidget(QtCore.Qt.BottomDockWidgetArea, self.dock)
    self.dock.hide()
    self.action = self.dock.toggleViewAction()
    self.tool_bar.addAction(self.action)
            
    self.session_menu = self.menu_bar.addMenu("&Session")

    self.setStyleSheet("""
    * 
    { 
        background-color: blue;
    } 
    """)
    
    button = QtGui.QPushButton("Test")
    self.setCentralWidget(button)

if name == "main":
import sys
app = QtGui.QApplication(sys.argv)
main_window = MyMainWindow()
main_window.show()
app.exec_() @

[mirswith]

Thanks, that did it, I just needed to hide it right after adding it.

-=ben