Append struct into nested QList don't work [SOLVED]

ChanchoCiego

Hello,

This does not work, what am I doing wrong?

I appreciate the help,

regards,

@
struct StructA
{
QString strStrA;
unsigned int uintStrA;
qreal qrlStrA;

StructA(void)
{
    uintStrA = 0;
    qrlStrA  = 0;
}

}

struct StructB
{
QString strStrB;
unsigned int uintStrB;
qreal qrlStrB;

QList<StructA> lstStructA;

StructB(void)
{
    uintStrB = 0;
    qrlStrB  = 0;
}

}

void procedure(void)
{
QList<StructB> lstStructB;

StructB strb;
StructA stra;

strb.strStrB  = "abc";
strb.uintStrB = 1;
strb.qrlStrB  = 2;

stra.strStrA  = "def";
stra.uintStrA = 3;
stra.qrlStrA  = 4;

strb.lstStructA.append( stra ); // this works
lstStructB.append( strb );

StructA structa;

structa.strStrA  = "ghi";
structa.uintStrA = 5;
structa.qrlStrA  = 6;

// this does not work, compiling reports
// "error: C2663: 'QList <T> :: append': 2 overloads have no meaningful
// conversion to pointer 'this' with [T = StructA]"
lstStructB.at( lstStructB.size()-1 ).lstStructA.append( structa );

}
@

sierdzio

QList returns const objects. You can't modiy the objects by calling "append" on them. Consider using takeAt() method instead.

ChanchoCiego

Hello sierdzio, thanks for reply,

I apologize, the QList man says:

bq. QList uses 0-based indexes, just like C++ arrays. To access the item at a particular index position, you can use operator [] (). On non-const lists, operator [] () returns a reference to the item and can be used on the left side of an assignment:

in the following line:

bq. Because QList is implemented as an array of pointers, this operation is very fast (constant time). For read-only access, an alternative syntax is to use at()

a mistake of mine,

I ask apologies and thank you for the reply,

Best regards

sierdzio

Hey, no problem. That is one of the reasons this forum exists: to solve issues like this one :)