Passing Pointer to QByteArray

jediengineer

I'm working on a function that needs a pointer to a QByteArray that stores a UDP datagram. So fat I've tried passing the pointer like this with no luck:

@
void my_func::udp_read();
{
QByteArray buffer;
udpSocket->readDatagram(buffer.data(), buffer.size(), &sender, &senderPort);

process_buffer(QByteArray * buffer);
...
...
return;

}
void process_buffer(QByteArray * incoming);
{
QByteArray in_buffer = (QByteArray)incoming;
...
...
return;
}
@

So far, all I get is a compiler error that says " Expected primary-expression before "(asterisk)" token" at the function call line, and " No matching function for call to 'QByteArray::QByteArray(QByteArray*&)' QByteArray buffer = (QByteArray)incoming;" at that line in the error.

Can someone point me in the right direction (no pun intended) and let me know what I'm missing?

bipll

The correct C++ syntax of the call would be @ process_buffer(&buffer);@

BTW, you don't have to return; on the last line of void-returning function, inside these functions return is only needed as the means of preliminary escape, so the control would jump out of the function body.

jediengineer

Hey! Thanks for the info, that cleared it up. If it works (I'll know by the end of the day) I'll let you know. So far so good! Thanks again!!

Chris Kawa

This
@
QByteArray in_buffer = (QByteArray)incoming;
@
won't wok. You can't cast pointer to a class type (well, you can, but it's nonsense).

Just make your function accept a reference and don't play with pointers when there's no need for it.

@
void my_func::udp_read() //Don't put ; here !!
{
QByteArray buffer;
udpSocket->readDatagram(buffer.data(), buffer.size(), &sender, &senderPort);
process_buffer(buffer);
...
}
void process_buffer(const QByteArray& incoming);
{
//this is redundant, just work directly with "incoming"
//QByteArray in_buffer = (QByteArray)incoming;
doSomething(incoming);
...
}
@