Passing Pointer to QByteArray

[jediengineer]

I'm working on a function that needs a pointer to a QByteArray that stores a UDP datagram. So fat I've tried passing the pointer like this with no luck:

@
void my_func::udp_read();
{
QByteArray buffer;
udpSocket->readDatagram(buffer.data(), buffer.size(), &sender, &senderPort);

process_buffer(QByteArray * buffer);
...
...
return;

}
void process_buffer(QByteArray * incoming);
{
QByteArray in_buffer = (QByteArray)incoming;
...
...
return;
}
@

So far, all I get is a compiler error that says " Expected primary-expression before "(asterisk)" token" at the function call line, and " No matching function for call to 'QByteArray::QByteArray(QByteArray*&)' QByteArray buffer = (QByteArray)incoming;" at that line in the error.

Can someone point me in the right direction (no pun intended) and let me know what I'm missing?

[bipll]

The correct C++ syntax of the call would be @ process_buffer(&buffer);@

BTW, you don't have to return; on the last line of void-returning function, inside these functions return is only needed as the means of preliminary escape, so the control would jump out of the function body.

[jediengineer]

Hey! Thanks for the info, that cleared it up. If it works (I'll know by the end of the day) I'll let you know. So far so good! Thanks again!!

[Chris Kawa]

This
@
QByteArray in_buffer = (QByteArray)incoming;
@
won't wok. You can't cast pointer to a class type (well, you can, but it's nonsense).

Just make your function accept a reference and don't play with pointers when there's no need for it.

@
void my_func::udp_read() //Don't put ; here !!
{
QByteArray buffer;
udpSocket->readDatagram(buffer.data(), buffer.size(), &sender, &senderPort);
process_buffer(buffer);
...
}
void process_buffer(const QByteArray& incoming);
{
//this is redundant, just work directly with "incoming"
//QByteArray in_buffer = (QByteArray)incoming;
doSomething(incoming);
...
}
@