[Solved] Size of QGraphicview
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Hello,
I try to get the size of my QGraphicview and I used
@int sizeX,sizeY;
sizeX = ui->gvResultGraph->size().width;
sizeY = ui->gvResultGraph->size().height;@But I got an error message like that
@error C3867: 'QSize::width': function call missing argument list; use '&QSize::width' to create a pointer to member
error C2440: '=' : cannot convert from 'int (__thiscall QSize::* )(void) const' to 'int'@I don't really know what it means.. Would anyone have an idea about what is wrong with the synthax?
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Change code like this:
@int sizeX,sizeY;
sizeX = ui->gvResultGraph->size().width();
sizeY = ui->gvResultGraph->size().height();@
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oh yeah I thought they were parameters of size(), not functions. Thank you very much!
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Intellisense of IDE could be very informative and saves a lot of your time by helping to avoid this kind of mistakes.
