[Solved] Size of QGraphicview

[silep]

Hello,

I try to get the size of my QGraphicview and I used

@int sizeX,sizeY;

sizeX = ui->gvResultGraph->size().width;
sizeY = ui->gvResultGraph->size().height;@

But I got an error message like that
@error C3867: 'QSize::width': function call missing argument list; use '&QSize::width' to create a pointer to member
error C2440: '=' : cannot convert from 'int (__thiscall QSize::* )(void) const' to 'int'@

I don't really know what it means.. Would anyone have an idea about what is wrong with the synthax?

[qxoz]

Change code like this:
@int sizeX,sizeY;
sizeX = ui->gvResultGraph->size().width();
sizeY = ui->gvResultGraph->size().height();@

[silep]

oh yeah I thought they were parameters of size(), not functions. Thank you very much!

[qxoz]

Intellisense of IDE could be very informative and saves a lot of your time by helping to avoid this kind of mistakes.